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\(\dfrac{-5}{12}\cdot\dfrac{7}{15}+\dfrac{-5}{12}\cdot\dfrac{8}{15}+\dfrac{5}{12}\)
\(=\dfrac{-5}{12}+\dfrac{5}{12}\)
=0
a: \(=\dfrac{-5}{8}+\dfrac{7}{12}=\dfrac{-15}{24}+\dfrac{14}{24}=\dfrac{-1}{24}\)
b: \(=\dfrac{3}{4}-\dfrac{5}{6}+\dfrac{11}{12}=\dfrac{9}{12}-\dfrac{10}{12}+\dfrac{11}{12}=\dfrac{10}{12}=\dfrac{5}{6}\)
c: \(=\dfrac{6}{36}-\dfrac{1}{36}=\dfrac{5}{36}\)
d: \(=\dfrac{5}{12}+\dfrac{5}{12}=\dfrac{10}{12}=\dfrac{5}{6}\)
e: \(=\dfrac{-8}{56}-\dfrac{7}{56}=\dfrac{-15}{56}\)
f: \(=\dfrac{-5}{15}+\dfrac{3}{25}=\dfrac{-25}{75}+\dfrac{9}{75}=\dfrac{-16}{75}\)
a: \(=\dfrac{5}{6}\cdot\dfrac{-12}{7}=\dfrac{-10}{7}\)
b: \(=\dfrac{7}{8}\cdot\dfrac{8}{14}=\dfrac{7}{14}=\dfrac{1}{2}\)
c: \(=\dfrac{4}{5}\cdot\dfrac{-15}{8}=\dfrac{-3}{2}\)
d: \(=\dfrac{15}{16}\cdot\dfrac{8}{25}=\dfrac{15}{25}\cdot\dfrac{1}{2}=\dfrac{3}{5}\cdot\dfrac{1}{2}=\dfrac{3}{10}\)
đ: \(=\dfrac{2}{3}-\dfrac{70}{175}=\dfrac{2}{3}-\dfrac{2}{5}=\dfrac{10-6}{15}=\dfrac{4}{15}\)
\(\left|x\right|=\left|-5\right|-\left|-10\right|+15\)
\(\Rightarrow\left|x\right|=5-10+15\)
\(\Rightarrow\left|x\right|=10\)
\(\Rightarrow x=\pm10\)
\(\left|x\right|=-(-12)+(-15)+8\)
\(\Rightarrow\left|x\right|=+12+(-15)+8\)
\(\Rightarrow\left|x\right|=12+(-15)+8\)
\(\Rightarrow\left|x\right|=(-3)+8\)
\(\Rightarrow\left|x\right|=5\)
\(\Rightarrow x=\pm5\)
Bài dưới tương tự
|x|=|−5|−|−10|+15
⇒|x|=5−10+15
⇒|x|=10
⇒x=±10
|x|=−(−12)+(−15)+8
⇒|x|=+12+(−15)+8
⇒|x|=12+(−15)+8
⇒|x|=(−3)+8
⇒|x|=5
⇒x=±5
1: \(=\dfrac{-5}{8}\cdot\dfrac{15}{4}=-\dfrac{75}{32}\)
2: \(=\dfrac{15}{17}\cdot\dfrac{25}{34}=\dfrac{375}{578}\)
3: \(=-12\cdot\dfrac{8}{3}=-4\cdot8=-32\)
4: \(=\dfrac{15}{14}\cdot\dfrac{20}{21}=\dfrac{50}{49}\)
5: \(=48\cdot\dfrac{24}{5}=230.4\)
\(b=\text{}\dfrac{15.2^{24}.3^{14}-4.3^{15}.2^{24}}{19.2^{24}.3^{14}-6.2^{24}.3^{15}}=\)
\(=\dfrac{2^{24}.3^{14}\left(15-4.3\right)}{2^{24}.3^{14}\left(19-6.3\right)}=3\)
\(-15+8+12+\left(-5\right)\)
\(=-7+12+\left(-5\right)\)
\(=5+\left(-5\right)\)
\(=0\)
-15+8+12+(-5)
= (-15-5)+(8+12)
=-20+20
=0