tinh 11x325x37-915 phan (2x314)2
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PT
0
TT
2
16 tháng 4 2018
S=\(\dfrac{2}{4}+\dfrac{2}{12}+\dfrac{2}{24}+...+\dfrac{2}{4900}\)
S=\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{2450}\)
S=\(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{49.50}\)
S=\(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{49}-\dfrac{1}{50}\)
S=\(1-\dfrac{1}{50}=\dfrac{49}{50}\)
Vậy S=\(\dfrac{49}{50}\)
16 tháng 4 2018
\(S=\dfrac{2}{4}+\dfrac{2}{12}+\dfrac{2}{24}+...+\dfrac{2}{4900}\)
\(S=\dfrac{2}{2.2}+\dfrac{2}{2.6}+\dfrac{2}{4.6}+...+\dfrac{2}{50.98}\)
\(\Rightarrow\dfrac{1}{2}S=\dfrac{2}{2.4}+\dfrac{2}{4.6}+\dfrac{2}{6.8}+...+\dfrac{2}{98.100}\)
\(\dfrac{1}{2}S=\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{8}+...+\dfrac{1}{98}-\dfrac{1}{100}\)
\(\dfrac{1}{2}S=\dfrac{1}{2}-\dfrac{1}{100}\)
\(\dfrac{1}{2}S=\dfrac{49}{100}\)
\(\Rightarrow S=\dfrac{49}{100}:\dfrac{1}{2}\)
\(\Rightarrow S=\dfrac{49}{50}\)
HT
1
5 tháng 3 2016
- \(\frac{4}{7}.\frac{5}{6}.\frac{5}{7}.\frac{5}{6}=\frac{4.5.5.5}{7.6.7.6}=\frac{500}{1764}=\frac{125}{441}\)
- \(\frac{1}{2:3}.\frac{1}{2}=\frac{1}{2:3.2}\)(Có thể đề thíu)
HT
1
5 tháng 3 2016
\(\frac{4}{7}x\frac{5}{6}+\frac{5}{7}x\frac{5}{6}\)
\(=\frac{5}{6}x\left(\frac{4}{7}+\frac{5}{7}\right)=\frac{5}{6}x\frac{9}{7}=\frac{45}{42}=\frac{15}{14}\)
\(\frac{1}{2}:3x\frac{1}{2}=\frac{1}{6}x\frac{1}{2}=\frac{1}{12}\)
HV
5
PT
3
NB
3
19 tháng 8 2016
\(\frac{4}{5}+\frac{2}{7}+\frac{11}{5}+\frac{12}{7}+\frac{1}{5}\)
\(=\frac{4}{5}+\frac{11}{5}+\frac{1}{5}+\frac{2}{7}+\frac{12}{7}\)
\(=\frac{4+11+1}{5}+\frac{2+12}{7}\)
\(=\frac{16}{5}+\frac{14}{7}\)
\(=\frac{16}{5}+2=\frac{26}{5}\)
19 tháng 8 2016
\(\frac{4}{5}+\frac{2}{7}+\frac{11}{5}+\frac{12}{7}+\frac{1}{5}\)
\(=\left(\frac{4}{5}+\frac{11}{5}+\frac{1}{5}\right)+\left(\frac{2}{7}+\frac{12}{7}\right)\)
\(=\frac{16}{5}+\frac{14}{7}\)
\(=\frac{16}{5}+2=\frac{16}{5}+\frac{10}{5}=\frac{26}{5}\)
6 tháng 4 2017
2 - 5/6= 7/6
7/8+3/4=`13/8
2/5+3/4=23/20
7/12 - 2/7 + 1/12=8/21
12/17 - 5/17 - 4/17=3/17
\(\frac{11.3^{25}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{32}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}=\frac{11.3^{32}-3^{30}}{4.3^{28}}=\frac{3^{30}.\left(11.3^2-1\right)}{4.3^{28}}=\frac{3^2.98}{4}=\frac{9.98}{4}=\frac{882}{4}=\frac{441}{2}\)