1/tìm x,y,z biết
a/\(\dfrac{y+z+1}{x}\)=\(\dfrac{x+z+2}{y}\)=\(\dfrac{x+y-3}{z}\)=\(\dfrac{1}{x+y+z}\)
b/\(\dfrac{x_1}{a_1}\)=\(\dfrac{x_2}{a_2}\)=....=\(\dfrac{x_{n-1}}{a_{n-1}}\)= \(\dfrac{x_n}{a_n}\)và x\(_1\)+x\(_2\)+.....+x\(_n\)=c
(a\(_1\)khác 0,....,a\(_n\)khác 0; a\(_1\)+a\(_2\)+.....+a\(_n\)khác 0)
c/tìm x,y,z thuộc Q
(x+y):(5-z):(y+z):(9+y)=3:1:2:5
d/\(\dfrac{2x+1}{5}\)=\(\dfrac{3y-2}{7}\)=\(\dfrac{2x+3y-1}{6x}\)
Giúp mk vs các bn
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Đọc tiếp
1/tìm x,y,z biết
a/\(\dfrac{y+z+1}{x}\)=\(\dfrac{x+z+2}{y}\)=\(\dfrac{x+y-3}{z}\)=\(\dfrac{1}{x+y+z}\)
b/\(\dfrac{x_1}{a_1}\)=\(\dfrac{x_2}{a_2}\)=....=\(\dfrac{x_{n-1}}{a_{n-1}}\)= \(\dfrac{x_n}{a_n}\)và x\(_1\)+x\(_2\)+.....+x\(_n\)=c
(a\(_1\)khác 0,....,a\(_n\)khác 0; a\(_1\)+a\(_2\)+.....+a\(_n\)khác 0)
c/tìm x,y,z thuộc Q
(x+y):(5-z):(y+z):(9+y)=3:1:2:5
d/\(\dfrac{2x+1}{5}\)=\(\dfrac{3y-2}{7}\)=\(\dfrac{2x+3y-1}{6x}\)
Giúp mk vs các bn 
chu mi a