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\(7^x.7^2+2.\frac{7^x}{7}=345\)
\(343.7^x+2.7^x=7.345\)
\(345.7^x=7.345\Rightarrow7^x=7\Rightarrow x=1\)
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\(\left(\frac{3}{17}-\frac{2}{345}+\frac{5}{12}\right)-\left(-\frac{2}{345}+\frac{3}{17}-\frac{1}{12}\right)\)
\(=\frac{3}{17}-\frac{2}{345}+\frac{5}{12}+\frac{2}{345}-\frac{3}{17}+\frac{1}{12}\)
\(=\left(\frac{3}{17}-\frac{3}{17}\right)+\left(\frac{2}{345}-\frac{2}{345}\right)+\frac{5}{12}+\frac{1}{12}\)
\(=\frac{6}{12}=\frac{1}{2}\)
( 3/17 - 2/345 + 5/12 ) - ( - 2/345 + 3/17 - 1/12 )
= 3/17 - 2/345 + 5/12 + 2/345 - 3/17 + 1/12
= ( 3/17 - 3/17 ) + ( 2/345 - 2/345 ) + ( 5/12 + 1/12 )
= 0 + 0 + 1/2
=1/2
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\(\frac{1}{2}\cdot2^x+2^x\cdot2^2=2^8+2^5\)
\(2^x\left(\frac{1}{2}+4\right)=2^8+2^5\)
\(2^x\cdot\frac{9}{2}=288\)
\(2^x=64\)
\(2^x=2^6\)
\(x=6\)
\(9^x:3^x=3^7\)
\(3^{2x}:3^x=3^7\)
\(3^x=3^7\)
\(x=7\)
\(7^{x+2}+2\cdot7^{x-1}=345\)
\(7^x\cdot7^2+2\cdot7^x:7=345\)
\(7^x\left(7^2+\frac{2}{7}\right)=345\)
\(7^x\cdot\frac{345}{7}=345\)
\(7^x=7\)
\(x=1\)
a) 1/2.2^x + 2^x+2 = 256 + 32
1/2.2^x + 2^2.2^x=288
2^x(1/2+4)= 288
2^x.4,5=288
2^x= 288:4,5
2^x=64=2^6
x=6
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7x + 2 + 2 . 7x - 1 = 345
7x - 1 . ( 73 + 2 ) = 345
7x - 1 . 345 = 345
7x - 1 = 345 : 345
7x - 1 = 1
7x - 1 = 70
x - 1 = 0
x = 0 + 1
x = 1
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\(\left(2x-1\right)^6=\left(2x-1\right)^8\)
\(\Leftrightarrow\left(2x-1\right)^6-\left(2x-1\right)^8=0\)
\(\Leftrightarrow\left(2x-1\right)^6\left[1-\left(2x-1\right)^2\right]=0\)
\(\Rightarrow2x-1=0\)hoặc \(2x-1=1\)hoặc \(2x-1=-1\)
\(\Rightarrow x=\frac{1}{2}\)hoặc \(x=1\)hoặc \(x=0\)
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BT1 :thực hành phép tính
4/3+-11/31+3/10-20/31-2/5 = 7/30
7/12-1/-16+3/4 = 67/48
2/11.-5/4+-9/11.5/4+ 1 và 3/4 = -1/4 * và 3/4 là sao bạn *
-9/27-25/75 = -2/3
\(7^{^{ }1x+2}+2.7^{1x-1}\)=345
=>7^x.7^2+2.7^x:7=345
=>7^x.(49+2/7)=345
=>7^x.345/7=345
=>7^x=345:345/7
=>7^x=7
=>x=1
vậy x=1
\(7^{1x+2}+2.7^{1x-1}=345\\ \Leftrightarrow7^x.49+2.7^x.\dfrac{1}{7}=345\\ \Leftrightarrow7^x\left(49+\dfrac{2}{7}\right)=345\\ \Leftrightarrow7^x.\dfrac{345}{7}=345\\ \Leftrightarrow7^x=7\\ \Leftrightarrow x=1\)
Vay x=1