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( 48 x 5 + 48 x 7 - 48 x 12 )
=48 x ( 5 + 7 - 12 )
=48 x 0
= 0
\(\Rightarrow\)( 48 x 5 + 48 x 7 - 48 x 12 ) : ( 1 + 3 + 5 + 7 +.....+ 91 ) = 0
Hk tốt
\(\left(48\text{ x }5+48\text{ x }7-48\text{ x }12\right)\text{ : }\left(1+3+5+7+...+91\right)\)
\(=\left(48\text{ x }5+48\text{ x }7-48\text{ x }12\right)\text{ : }A\)
\(=48\text{ x }\left(5+7-12\right)\text{ : }A\)
\(=48\text{ x }\left(12-12\right)\text{ : }A\)
\(=48\text{ x }0\text{ : }A\)
\(=0\text{ : }A\)
\(=0\)
x + 5 / 48 = 7 / 42
=> ( x + 5 ).42 = 48.7
=> x + 5 = ( 48.7 ) : 42
=> x + 5 = 336 : 42
=> x + 5 = 8
=> x = 8 - 5
=> x = 3
Vậy x = 3
có X/Y=7/5 ( anh viết dấu x thành dấu . cho dễ đọc hơn nhé )
=>X.5=Y.7
X.5-Y.7=0
X.5-Y.5-Y.2=0
có X-Y=48 =>X.5-Y.5=48.5=240
=>240=2.Y
=>Y=120
có X-Y=48
=> Y+48=X
=>120+48=X
=>X=168
Vậy X=168: Y=120
`x-10/3=7/18+3/5`
`=> x-10/3=89/90`
`=> x=89/90+10/3`
`=> x=389/90`
Đề Bài :\(\frac{9}{14}\)- \(\frac{x}{7}\): \(\frac{5}{3}\)= \(\frac{3}{14}\)
ta có : \(\frac{9}{14}\)- \(\frac{x}{7}\)= \(\frac{3}{14}\)x \(\frac{5}{3}\)= \(\frac{5}{14}\)
\(\frac{x}{7}\)= \(\frac{9}{14}\)- \(\frac{5}{14}\)= \(\frac{4}{14}\)
\(\frac{4}{14}\)= \(\frac{x}{7}\)=> \(\frac{4}{14}\)= \(\frac{2}{7}\)=> x = 2
`3/7+2/5+4/7`
`=(3/7+4/7)+2/5`
`=1+2/5`
`=5/5+2/5`
`=7/5`
`20/34+4/9+7/17`
`=(20/34+7/17)+4/9`
`=(20/34+14/34)+4/9`
`=34/34+4/9`
`=1+4/9`
`=9/9+4/9`
`=13/9`
`48xx2+96+48xx6`
`=48xx2+48xx2+48xx6`
`=48xx(2+2+6)`
`=48xx10`
`=480`
câu thứ hai thì làm như này em nhé:
\(\dfrac{20}{34}\) + \(\dfrac{4}{9}\) + \(\dfrac{7}{17}\)
= (\(\dfrac{20}{34}\) + \(\dfrac{7}{17}\)) + \(\dfrac{4}{9}\)
= (\(\dfrac{10}{17}\) + \(\dfrac{7}{17}\)) + \(\dfrac{4}{9}\)
= 1 + \(\dfrac{4}{9}\)
= \(\dfrac{13}{9}\)
\(\frac{x+5}{48}=\frac{7}{42}=\frac{1}{6}=\frac{8}{48}\)
=> x + 5 = 8
=> x = 8 - 5
=> x = 3.