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a, x + y = 3 => (x + y)2 = 9 <=> x2 + 2xy + y2 = 9 <=> 5 + 2xy = 9 <=> 2xy = 4 <=> xy = 2
Ta có: x3 + y3 = (x + y)(x2 - xy + y2) = 3 . (5 - 2) = 3 . 3 = 9
b, x - y = 5 => (x - y)2 = 25 <=> x2 - 2xy + y2 = 25 <=> 15 - 2xy = 25 <=> -2xy = 10 <=> xy = -5
Ta có: x3 - y3 = (x - y)(x2 + xy + y2) = 5 . (15 - 5) = 5 . 10 = 50
Trả lời:
7, 5( x + y )2 + 15( x + y )
= 5( x + y )( x + y + 3 )
9, 7x( y - 4 )2 - ( 4 - y )3
= 7x ( 4 - y )2 - ( 4 - y )
= ( 4 - y )2 ( 7x - 4 + y )
11, ( x + 1 )( y - 2 ) - ( 2 - y )2
= ( x + 1 )( y - 2 ) - ( y - 2 )2
= ( y - 2 )( x + 1 - y + 2 )
= ( y - 2 )( x - y + 3 )
8, 9x ( x - y ) - 10 ( y - x )2
= 9x ( x - y ) - 10 ( x - y )2
= ( x - y )[ ( 9x - 10 ( x - y ) ]
= ( x - y )( 9x - 10x + 10y )
= ( x - y )( 10y - x )
10, ( a - b )2 - ( a + b )( b - a )
= ( b - a )2 - ( a + b )( b - a )
= ( b - a )( b - a - a - b )
= - 2a( b - a )
= 2a ( a - b )
12, 2x ( x - 3 ) + y ( x - 3 ) + ( 3 - x )
= 2x ( x - 3 ) + y ( x - 3 ) - ( x - 3 )
= ( x - 3 )( 2x + y - 1 )
a: \(15xy^2z^3:3xyz^2=5yz\)
b: \(12x^4y^4:\left(-4x^4y^2\right)=-3y^2\)
c: \(\dfrac{-15x^2y^3z^2}{-6xz^2}=\dfrac{5}{2}xy^3\)
d: \(\dfrac{\left(x-y\right)^5}{\left(y-x\right)^3}=-\left(x-y\right)^2\)
Tính: a, x2+y2
Ta có: x+y=2 => (x+y)2=4
<=> x2+2xy+y2=4
<=> x2+y2=4-2xy=4-2.(-15)=34 (vì x.y=-15)
vậy x2+y2=34
b, x3+y3
Ta có: x+y=2 => (x+y)3=8
<=>x3+3xy(x+y) + y3 = 8
<=> x3+y3 =8 - 3xy(x+y) = 8 - 3 ( -15) . 2 =98
Vậy x3+y3 = 98
c, x5 + y5
Ta có: ( x2+y2)(x3+y3)=34.98=3332
<=> x5+x3y2+x2y3+y5=3332
<=> x5+y5+x2y2(x+y)=3332
<=> x5+y5 + (xy)2(x+y)=3332
<=> x5+y5 = 3332 - (xy)2(x+y)=3332 - (-15)2 . 2 =2882
Vậy x5+y5=2882
Ta có \(\left(x-y\right)^2=5^2=25\)
\(=>x^2-2xy+y^2=25\)
\(=>15-2xy=25\)
\(=>2xy=-10\)
\(=>xy=-5\)
Ta có : \(x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)\)
\(=5\left(15+\left(-5\right)\right)\)
\(=5.10=50\)
Ủng hộ nha