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\(x\cdot3:x+2\cdot6:4+x:0,5+0,25+x\cdot1=35\)
=>\(3+3+2x+0,25+x=35\)
=>3x+6,25=35
=>3x=35-6,25=28,75
=>\(x=\dfrac{28.75}{3}=\dfrac{115}{12}\)
0,5 × 3,16 × 4 × 2 × 0,25
= ( 0,5 × 2 ) × ( 0,25 × 4 ) × 3,16
= 1 × 1 × 3,16
= 1 × 3,16
= 3,16
Bài 1:
câu a: 4\(\dfrac{4}{9}\) : 2\(\dfrac{2}{3}\) + 3\(\dfrac{1}{6}\)
= \(\dfrac{40}{9}\) : \(\dfrac{8}{3}\) + \(\dfrac{19}{6}\)
= \(\dfrac{5}{3}\) + \(\dfrac{19}{6}\)
= \(\dfrac{10}{6}\) + \(\dfrac{19}{6}\)
= \(\dfrac{29}{6}\)
b, (15,25 + 3,75) \(\times\) 4 + ( 20,71 + 5,29)\(\times\) 5
= 19 \(\times\) 4 + 26 \(\times\) 5
= 76 + 130
= 206
c, \(\dfrac{4}{5}\) \(\times\) \(\dfrac{1}{2}\) + \(\dfrac{4}{5}\) \(\times\) \(\dfrac{1}{3}\) - \(\dfrac{4}{5}\) \(\times\) \(\dfrac{1}{4}\)
= \(\dfrac{2}{5}\) + \(\dfrac{4}{15}\) - \(\dfrac{1}{5}\)
= \(\dfrac{6}{15}\) + \(\dfrac{4}{15}\) - \(\dfrac{3}{15}\)
= \(\dfrac{7}{15}\)
d, 1\(\dfrac{5}{7}\) + 7\(\dfrac{3}{6}\) + 2\(\dfrac{2}{7}\) - 4\(\dfrac{3}{6}\)
= (1 + 2 + \(\dfrac{5}{7}\) + \(\dfrac{2}{7}\)) + ( 7 + \(\dfrac{3}{6}\) - 4 - \(\dfrac{3}{6}\))
= 3 + 1 + 3
= 7
\(x\times\frac{1}{2}+x\div0,25+x\div0,5=13\)
\(x\times0,5+x\times4+x\times2\) \(=13\)
\(x\times(0,5+4+2)\) \(=13\)
\(x\) \(=13\div6,5\)
\(x\) \(=2\)
Học tốt , nhớ kb nha
a) y : 0,25 + y x 8 - y : 0,5 = 230
y x 4 + y x 8 - y x 2 = 230
y x (4 + 8 - 2) = 230
y x 10 = 230
y = 230 : 10
y = 23
b) \(x\) x 4 + \(x\) x 6 = 30
\(x\) x (4 + 6) = 30
\(x\) x 10 = 30
\(x\) = 30 : 10
\(x\) = 3
a; y :0,25 + y x 8 - y: 0,5 = 230
y x 4 + y x 8 - y x 2 = 230
y x (4 + 8 - 2) = 230
y x 10 = 230
y = 230 : 10
y = 23
b; \(x\) \(\times\) 4 + \(x\) \(\times\) 6 = 30
\(x\) \(\times\) (4 + 6) = 30
\(x\) \(\times\) 10 = 30
\(x\) = 30 : 10
\(x\) = 3
x+x:0,5+x:0,25+x:0,125=50-x*35
x+x*2+x*4+x*8=50-x*35
x+x*2+x*4+x*8+x*35=50
x*(1+2+4+8+35)=50
x*50=50
x=50:50
x=1
k dg cho mik nha!
địt mẹ mày đừng dùng olm như cặc
câu trả lời : anbatukam