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#include <bits/stdc++.h>
using namespace std;
long long a;
int main()
{
cin>>a;
if (a%2==0) cout<<a<<" la so chan";
else cout<<a<<" la so le";
return 0;
}
uses crt;
var a,b,c,max:integer;
begin
clrscr;
write('nhap ba so:');readln(a,b,c);
if a mod 2=0 then writeln(a,' la so chan')
else writeln(a,'la so le);
if b mod 2=0 then writeln(b,'la so chan')
else writeln(b,'la so le');
if c mod 2=0 then writeln(c,'la so chan')
else writeln(c,'la so le');
max:=a;
if max<b then max:=b;
if max<c then max:=c;
writeln('so lon nhat trong ba so la:',max);
readln
end.
uses crt;
var a:integer;
begin
clrscr;
write('Nhap a='); readln(a);
if a<0 then writeln(a,' la so am')
else if a>0 then writeln(a,' la so duong')
else writeln(a,' khong la so am cung khong la so duong');
readln;
end.
var A: integer;
begin
write('Nhap vao mot so A='); readln(A);
if A>0 then write('So A la so nguyen duong');
if A<0 then write('So A la so nguyen am');
If A=0 then write('So A khong la so nguyen am va khong la so nguyen duong');
readln;
end.
Câu 1:
uses crt;
var n,i,dem,j,kt1,kt2,a,b,kt:integer;
begin
clrscr;
write('Nhap n='); readln(n);
dem:=0;
if n mod 2=1 then
begin
a:=2;
b:=n-a;
kt:=0;
for i:=2 to trunc(sqrt(b)) do
if b mod i=0 then kt:=1;
if kt=0 then inc(dem);
end
else begin
for i:=2 to n div 2 do
begin
a:=i;
b:=n-i;
kt1:=0;
kt2:=0;
for j:=2 to trunc(sqrt(a)) do
if a mod j=0 then kt1:=1;
for j:=2 to trunc(sqrt(b)) do
if b mod j=0 then kt2:=1;
if (kt1=0) and (kt2=0) then inc(dem);
end;
end;
writeln('So cach phan tich ',n,' thanh tong hai so nguyen to la: ',dem);
readln;
end.
Câu 2:
uses crt;
var n,x:integer;
{-----------------ham-kiem-tra-nguyen-to-----------------}
function ktnt(x:integer):boolean;
var kt:boolean;
i:integer;
begin
kt:=true;
for i:=2 to trunc(sqrt(x)) do
if x mod i=0 then
begin
kt:=false;
break;
end;
if kt=true then ktnt:=true
else ktnt:=false;
end;
{---------------ham-kiem-tra-so-doi-xung---------------}
function ktdx(x:integer):boolean;
var kt:boolean;
d,i:integer;
st:string;
begin
str(x,st);
d:=length(st);
kt:=true;
for i:=1 to d do
if st[i]<>st[d-i+1] then
begin
kt:=false;
break;
end;
if kt=true then ktdx:=true
else ktdx:=false;
end;
{--------------chuong-trinh-chinh---------------}
begin
clrscr;
repeat
write('Nhap n='); readln(n);
until n>0;
if (ktnt(n)=true) and (ktdx(n)=true) then writeln(n,' la so nguyen to doi xung')
else writeln(n,' khong la so nguyen to doi xung');
x:=n+1;
repeat
x:=x+1;
until (ktnt(x)=true) and (ktdx(x)=true);
writeln('So nguyen to doi xung nho nhat lon hon ',n,' la: ',x);
readln;
end.
#include <bits/stdc++.h>
using namespace std;
long long x,n,i,dem1,dem2;
int main()
{
cin>>n;
dem1=0;
dem2=0;
for (i=1; i<=n; i++)
{
cin>>x;
if (x%2==0) dem1++;
else dem2++;
}
cout<<"So so chan la: "<<dem1<<endl;
cout<<"So so le la: "<<dem2;
return 0;
}
uses crt;
var a:integer;
begin
clrscr;
readln(a);
if (a mod 3=0) or (a mod 5=0) then write('co')
else writeln('khong');
readln;
end.
program;
uses crt;
var a:longint;
begin
clrscr;
write('nhap a:');readln(a);
if(a>=0)and(a<=50)then write('n nam trong khoang tu 1 den 50')
else write('n khong nam trong khoang tu 1 den 50');
readln;
#include <bits/stdc++.h>
using namespace std;
int a;
int main()
{
cin>>a;
if ((a>=1) and (a<=50)) cout<<"YES";
else cout<<"NO";
return 0;
}