Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(A=\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6+\frac{7}{4}+\frac{3}{2}\right)\)
\(A=3-\frac{1}{4}+\frac{2}{3}-5+\frac{1}{3}+\frac{6}{5}-6-\frac{7}{4}-\frac{3}{2}\)
\(A=\left(3-5-6\right)-\left(\frac{1}{4}+\frac{7}{4}+\frac{3}{2}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)+\frac{6}{5}\)
\(A=-8-\left(2+\frac{3}{2}\right)+1+\frac{6}{5}\)
\(A=-8-2-\frac{3}{2}+1+\frac{6}{5}\)
\(A=-9-\frac{3}{2}+\frac{6}{5}\)
\(A=\frac{-93}{10}\)
Mk lm đc 1 cách thui
Ủng hộ mk nha ^_-
\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(3x-\frac{3}{2}-5x-3=\frac{1}{5}-x\)
\(\left(3x-5x\right)-\left(\frac{3}{2}+3\right)=\frac{1}{5}-x\)
\(\left(-2\right).x-\frac{9}{2}=\frac{1}{5}-x\)
\(\left(-2\right).x+x.1=\frac{1}{5}+\frac{9}{2}\)
\(-1.x=\frac{47}{10}\)
\(x=\frac{47}{10}:\left(-1\right)\)
\(x=\frac{47}{10}.\frac{1}{-1}\)
\(x=\frac{47}{-10}\)
Vậy \(x=\frac{47}{-10}\)
\(\frac{0,8:\left(\frac{4}{5}:1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(100-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right).2\frac{2}{27}}+\left(1,2.0,5\right):\frac{3}{5}\)
=\(\frac{0,8:0,64}{0,64.25-\frac{1}{25}}+\frac{\left(100-\frac{2}{5}\right).\frac{7}{4}}{\left(\frac{59}{9}-\frac{13}{4}\right).\frac{56}{27}}+\left(1,2.0,5\right).\frac{5}{3}\)
=
Bài 2
a. \(-1\frac{2}{3}-|2x-1|:\frac{3}{5}=-2\)
\(|2x-1|:\frac{3}{5}=\frac{5}{3}-2\)
\(|2x-1|:\frac{3}{5}=-\frac{1}{3}\)
\(|2x-1|=-\frac{1}{5}\)
Vì giá trị tuyệt đối luôn \(\ge0\)với mọi x
mà \(-\frac{1}{5}< 0\)
=> \(x\in\varnothing\)
\(=\frac{\frac{6}{5}:\left(\frac{6}{5}-\frac{5}{4}\right)}{\frac{8}{25}+\frac{2}{25}}+\frac{\frac{2027}{25}:\frac{9}{4}}{\left(\frac{38}{7}-\frac{9}{4}\right):\frac{267}{56}}\)
\(=\frac{\frac{6}{5}:\left(\frac{-1}{20}\right)}{\frac{2}{5}}+\frac{\frac{8180}{225}}{\frac{89}{28}:\frac{167}{56}}\)
\(=\frac{-12}{5}:\frac{2}{5}+\frac{8180}{225}:\frac{178}{167}\)
\(=-1+...\)ra số to vcl
Đề sai à ???
\(\left(\frac{25}{4}\right)^5\cdot\frac{2}{5}+\frac{-5}{4}\)
\(\frac{25}{4}^5=9536,743164\)
\(\Rightarrow\left(\frac{25}{4}\right)^5\cdot\frac{2}{5}+\frac{-5}{4}\)
\(=3814,697266+\frac{-5}{4}\)
\(=3813,447266\)
\(\left(\frac{25}{4}\right)^5.\frac{2}{5}+\frac{-5}{4}=\frac{\left(5^2\right)^5}{\left(2^2\right)^5}.\frac{2}{5}+-\frac{5}{2^2}\)
\(=\frac{5^{10}}{2^{10}}.\frac{2}{5}+\frac{-5}{2^2}\)
\(=\frac{5.5^9.2}{2.2^9.5}+-\frac{5}{2^2}\)
\(=\frac{5^9}{2^9}+-\frac{5}{2^2}\)
đến đây thì mk ko pik lm nữa!ahihi nếu bn nào nghĩ đc cách tính thuận tiện hơn thì góp ý giùm nha!!!