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\(\begin{array}{l}a)A = 32,125 - (6,325 + 12,125) - (37 + 13,675)\\ = 32,125 - 6,325 - 12,125 - 37 - 13,675\\ = (32,125 - 12,125) + ( - 6,325 - 13,675) - 37\\ = 20 + ( - 20) - 37\\ = - 37\\b)B = 4,75 + {\left( {\frac{{ - 1}}{2}} \right)^3} + 0,{5^2} - 3.\frac{{ - 3}}{8}\\ = 4,75 + \frac{{ - 1}}{8} + 0,25 + \frac{9}{8}\\ = (4,75 + 0,25) + \left( {\frac{{ - 1}}{8} + \frac{9}{8}} \right)\\ = 5 + \frac{8}{8}\\ = 5 + 1\\ = 6\\c)C = 2021,2345.2020,1234 + 2021,2345.( - 2020,1234)\\ = 2021,2345.[2020,1234 + ( - 2020,1234)]\\ = 2021,2345.0\\ = 0\end{array}\)
c) \(2021,2345.2020,1234+2021,2345.\left(-2020,1234\right)\)
\(\text{=}2021,2345.\left(2020,1234-2020,1234\right)\)
\(\text{=}2021,2345.0\)
\(\text{=}0\)
d)\(4,75+\left(\dfrac{-1}{2}\right)^3+0,5^2-3.\dfrac{-3}{8}\)
\(\text{=}4,75-\dfrac{1}{8}+\dfrac{1}{4}+\dfrac{9}{8}\)
\(\text{=}\left(4,75+0,25\right)+\left(\dfrac{9}{8}-\dfrac{1}{8}\right)\)
\(\text{=}1+1\)
\(\text{=}2\)
Mình nhầm ở chỗ phần d nha.
Kết quả cuối cùng phải là :
\(\left(4,75+0,25\right)+\left(\dfrac{9}{8}-\dfrac{1}{8}\right)\)
\(\text{=}5+1\)
\(\text{=}6\)
[(-19,95) + (-45,75)] + [(4,95) + (+5,75)]
=> [-65,7] + [10,7]
=> -55
nếu mn thấy đúng nhớ cho mk nha
\(\begin{array}{l}0,65.78 + 2\dfrac{1}{5}.2020 + 0,35.78 - 2,2.2020\\ = 0,65.78 + 2,2.2020 + 0,35.78 - 2,2.2020\\ = (0,65.78 + 0,35.78) + (2,2.2020 - 2,2.2020)\\ = 78.(0,65 + 0,35) + 0\\ = 78.1\\ = 78\end{array}\)
\(2+3.\left(\frac{-1}{3}\right)^2\)
=\(2+3.\frac{1}{9}\)
= \(2+\frac{1}{3}\)
=\(\frac{7}{3}\)
\(\begin{array}{l}\frac{7}{6}.3\frac{1}{4} + \frac{7}{6}.( - 0,25)\\ = \frac{7}{6}.\frac{{13}}{4} + \frac{7}{6}.\frac{{ - 25}}{{100}}\\ = \frac{7}{6}.\frac{{13}}{4} + \frac{7}{6}.\frac{{ - 1}}{4}\\ = \frac{7}{6}.[\left( {\frac{{13}}{4} + ( - \frac{1}{4})} \right)]\\ = \frac{7}{6}.\frac{{12}}{4}\\ = \frac{7}{6}.3\\ = \frac{7}{2}\end{array}\)
= -15,5 .( 20,8 - 9,2) + 3,5 . (9,2+20,8)
=-15,5 . 11,6 + 3,5 .30
=-179,8+105
=-74,8
`!`
`(-3/4 + 5/13) xx 7/2 - (9/4 - 8/13 ) xx 7/2`
\(=\left[\left(-\dfrac{3}{4}+\dfrac{5}{13}\right)-\left(\dfrac{9}{4}-\dfrac{8}{13}\right)\right]\times\dfrac{7}{2}\\ =\left(-\dfrac{3}{4}+\dfrac{5}{13}-\dfrac{9}{4}+\dfrac{8}{13}\right)\times\dfrac{7}{2}\\ =\left[\left(-\dfrac{3}{4}-\dfrac{9}{4}\right)+\left(\dfrac{5}{13}+\dfrac{8}{13}\right)\right]\times\dfrac{7}{2}\\ =\left(-\dfrac{12}{4}+\dfrac{13}{13}\right)\times\dfrac{7}{2}\\ =\left(-3+1\right)\times\dfrac{7}{2}\\ =-2\times\dfrac{7}{2}\\ =-\dfrac{14}{2}\\ =-7\)
\(=-\dfrac{1}{3}+\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{3}{4}=1\)
\(\dfrac{-4}{12}-\left(-\dfrac{13}{39}-0.25\right)+0.75\)
\(=\dfrac{-1}{3}+\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{3}{4}\)
=1
\(C=2021.2345\cdot2020.1234+2021.2345\left(-2020.1234\right)\)
\(=2021.2345\left(2020.1234-2020.1234\right)\)
=0