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\(B=136.25+75.136-6^2.10^2\)
\(=136.\left(75+25\right)-36.100\)
\(=136.100-36.100\)
\(=\left(136-36\right).100\)
\(=100.100=10000\)
\(C=2^3.5^3-\left\{7^2.2^3.5^2.\left[4^3:8+11^2:121-2\left(37-5.7\right)\right]\right\}\)
\(=10^3-\left\{49.8.25.\left[8+1+2.2\right]\right\}\)
\(=1000-\left(49.200.13\right)\)
\(=1000-127400\)
\(=-126400\)
Bài này đơn giản thôi bạn
B= 136.(25+75)-36.100
B= 136. 100-36.100
B= 100.(136-36)
B= 100.100
B= 10000
a: A=-a+b-c+a+b+c
=2b
b: Khi a=1; b=-1; c=-2 thì A=2*(-1)=-2
a) A= -a+b-c + a+b+c = 2b
b) Vì giá trị của A = không phụ thuộc vào a hay c nên A=2b=2.(-1)= -2
a, Rút gọn
A = ( - a - b - c ) - ( - a - b - c )
= - a - b - c - a - b - c
= 2b
\(=\dfrac{1}{2}\left(\dfrac{2}{1\cdot3}+\dfrac{2}{3\cdot5}+...+\dfrac{2}{2003\cdot2005}\right)\)
\(=\dfrac{1}{2}\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{2003}-\dfrac{1}{2005}\right)\)
\(=\dfrac{1}{2}\cdot\dfrac{2004}{2005}=\dfrac{1002}{2005}\)
1) 279 : 81 = (33)9 : 34 = 327 : 34 = 323
2) a) = 170.3 + 154 : 14 = 510 + 11 = 521
b) = 136.(25 + 75) - 72 = 13600 - 49 = 13 551
c) = (2.5)3 - [(7.2)3 - 25.(64: 8 + 121 : 121 - 2.2)] = 1000 - [2744 - 25.(8 + 1 - 4)] = 1000 - 2619 = 1619
\(\dfrac{11\cdot9^{11}\cdot3^7-27^{10}}{4\cdot81^1}\)
\(=\dfrac{11\cdot3^{22}\cdot3^7-\left(3^3\right)^{10}}{4\cdot3^4}\)
\(=\dfrac{11\cdot3^{29}-3^{30}}{4\cdot3^4}\)
\(=\dfrac{3^{29}\cdot\left(11-3\right)}{4\cdot3^4}\)
\(=\dfrac{3^{29}\cdot8}{4\cdot3^4}\)
\(=3^{25}\cdot2\)
@ Huỳnh Thanh Phong
Sao lại lấy 329 là thừa số chung ạ
\(c=2^3.5^3-\left\{7^2.2^3-5^2.\left[4^3::8+11^2:121-2\left(37-5.7\right)\right]\right\}\)
\(c=8.5-\left\{49.8-25.\left[8:8+121:121-2\left(37-5.7\right)\right]\right\}\)
\(c=8.5-\left\{49.8-25.\left[8:8+121:121-2\left(37-35\right)\right]\right\}\)
\(c=8.5-\left\{49.8-25.\left[8:8+121:121+2.2\right]\right\}\)
\(c=8.5-\left\{1+1+2.2\right\}\)
\(c=8.5-\left\{1+1+4\right\}\)
\(c=8.5-6\)
\(c=40-6\)
\(c=34\)
nhầm
\(c=2^3.5^3-\left\{7^2.2^3-5^2.\left[4^3:8+11^2:121-2\left(37-5.7\right)\right]\right\}\)
\(c=8.125-\left\{49.8-25.\left[8:8+121:121-2\left(37-35\right)\right]\right\}\)
\(c=8.125-\left\{49.8-25.\left[8:8+121:121-2.2\right]\right\}\)
\(c=8.125-\left\{49.8-25.\left[1+1-2.2\right]\right\}\)
\(c=8.125-\left\{49.8-25.\left[1+1-4\right]\right\}\)
\(c=8.125-\left\{49.8-25.-2\right\}\)
\(c=8.125-\left\{392+50\right\}\)
\(c=8.125-442\)
\(c=1000-442\)
\(c=558\)
A= 2+5+8+11+...+2012
số số hạng là :
(2012-2) : 3 + 1 = 671
A = (2012+2) x 671 : 2
A = 675 697
A= 136.(25+75) - (6.10)2 = 136 . 100 - 602 = 13600 - 3600 = 10000
B= (2.5)3 - {(7.2)2 - 52. [43 : 23 + 112 : 112 - 2(37 -35)]}
=103 - {142 - 52 .[(4:2)3 + (11:11)2 - 2.2]} = 1000 - { 154 - 25 .[8 + 1 -4]} = ....