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Bài 1:
Ta có: \(x-35\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow65\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow x=\dfrac{1}{25}:\dfrac{13}{20}=\dfrac{1}{25}\cdot\dfrac{20}{13}=\dfrac{4}{65}\)
Vậy: \(x=\dfrac{4}{65}\)
Bài 2:
a) Ta có: \(17\dfrac{2}{31}-\left(\dfrac{15}{17}+6\dfrac{2}{31}\right)\)
\(=17\dfrac{2}{31}-\dfrac{15}{17}-6\dfrac{2}{31}\)
\(=11+\dfrac{2}{31}-\dfrac{15}{17}\)
\(=\dfrac{5366}{527}\)
Bài 1:
a: x/-2=-18/x
=>x2=36
=>x=6 hoặc x=-6
b: x/2+x/5=17/10
=>7/10x=17/10
hay x=17/7
\(S=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{99.100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}=\frac{99}{100}\)
ta có
1+2+3+.........+x=5050
=>\(\frac{x.\left(x+1\right)}{2}=5050\)
=>x.(x+1)=5050.2
=>x.(x+1)=10100
=>x.(x+1)=100.101
=>x=100
\(x-4=26\\ \Leftrightarrow x=30\)
\(\left(40+x\right).2=180\\ \Leftrightarrow40+x=90\\ \Leftrightarrow x=50\)
\(\left(14+5x\right):2=3^5:3^2\\ \Leftrightarrow\left(14+5x\right):2=27\\ \Leftrightarrow14+5x=54\\ \Leftrightarrow5x=40\\ \Leftrightarrow x=8\)
\(\dfrac{x}{10}=\dfrac{-3}{5}\\ \Rightarrow x=\dfrac{10.\left(-3\right)}{5}=-6\\ ------------\\ x+\dfrac{5}{12}=\dfrac{-2}{3}\\ x=\dfrac{-2}{3}-\dfrac{5}{12}\\ x=\dfrac{-8}{12}-\dfrac{5}{12}\\ x=\dfrac{-13}{12}\)
\(2x+1=9\\ \Leftrightarrow2x=8\\ \Leftrightarrow x=4\)
\(15-3x=3\\ \Leftrightarrow3x=12\\ \Leftrightarrow x=4\)