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a) 5x = 125
5x = 53
=> x = 3
b) x3 = 64
x3 = 43
=> x = 4
c) ( x - 1 ) 2 = 25
( x - 1 ) 2 = 52
=> x - 1 = 5
=> x = 5 + 1
=> x = 6
d) 5x + 5x+2 = 130
5x . 1 + 5x . 52 = 130
5x . ( 1 + 52 ) = 130
5x . 26 = 130
5x = 130 : 26
5x = 5
=> x = 1
a. 8 + (x - 9) = 125 - 64
8 + (x - 9) = 61
x - 9 = 53
x = 62
b. 5 x (X + 7) - 10 = 8 x 5
5 x (X + 7) - 10 = 40
5 x (X + 7) = 50
X + 7 = 10
X = 3
a) 12 + ( 5 + x ) = 20
⇔ 5 + x = 8
⇔ x = 3
Vậy x = 3
b) 120 + ( 50 + x ) = 180
⇔ 50 + x = 60
⇔ x = 10
Vậy x = 10
c) 175 + ( 30 - x ) = 200
⇔ 30 - x = 25
⇔ x = 5
Vậy x = 5
d) 130 - ( 100 + x ) = 25
⇔ 100 + x = 105
⇔ x = 5
Vậy x = 5
e) 145 - ( 125 + x ) = 12
⇔ 125 + x = 133
⇔ x = 8
Vậy x = 8
j) 5 ( x + 12 ) + 22 = 92
⇔ 5x + 60 + 22 = 92
⇔ 5x + 82 = 92
⇔ 5x = 10
⇔ x = 2
Vậy x = 2
g) 3 ( x + 23 ) + 6 = 96
⇔ 3x + 69 + 6 = 96
⇔ 3x + 75 = 96
⇔ 3x = 21
⇔ x = 7
Vậy x = 7
Tìm x :
a) 12 + ( 5 + x ) = 20
5 + x =20 - 12
5 + x = 8
x = 3
b) 120 + ( 50 + x ) = 180
50 + x = 180-120
50 + x = 60
x = 60 - 50
x = 10
c) 175 + ( 30 - x ) = 200
30 -x = 200 - 175
30 - x = 25
x = 30-25
x=5
d) 130- ( 100 +x ) =25
100 + x =130 - 25
100+x= 105
x=105-100
x=5
e) 145 - (125+x) = 12
125+x = 145-12
125+x=133
x= 133-125
x=8
j) 5 (x+12) +22 = 92
5 ( x+12) = 92 -22
5 (x+12)=70
x+12=70 : 5
x + 12 = 14
x = 14-12
x=2
g) 2 (x+23) + 6 =96
2 (x+23) = 96 - 6
2 (x+23)= 90
x+23=90:2
x+23=45
x= 45-23
x=22
CHÚC BẠN HỌC TỐT
a) 5.x< 40
=> x = 0 ; 1 ; 2 ; 3 ; 4 ; 5 ; 6 ; 7
b)5(x-20)=35
= ( x - 20 ) = 35 : 5 = 7
( x - 20 ) = 7
=>x = 20 + 7 = 27
c) (x-125)-130=5
( x - 125 ) = 5 + 130
( x - 125 ) = 135
=>x = 135 + 125
= 360
d)215+(x+21):2=358
( x + 21 ) : 2 = 358 - 215
( x +2 1 ) : 2 = 170
( x + 21 ) = 170 x 2 = 340
( x + 21 ) = 340 - 21 = 319
a.1+3+5+7+...+2x+1=225
[(2x+1-1):2+1]x(2x+1+1):2=225
(x+1)x(2x+2):2=225
(x+1)x(x+1)=225
(x+1)2=225
(x+1)2=152
x+1=15
x=14
_______________
b. 130-[5.(9-x)+43]=47
5.(9-x)+43=83
5.(9-x)=40
9-x=8
x=1
_______________
c.16x<324
24x<220
=>x∈{0;1;2;3;4}
a: =>(x+1)^2=225
=>x+1=15
=>x=14
b: =>[5*(9-x)+43]=130-47=83
=>5(9-x)=40
=>9-x=8
=>x=1
c: =>2^4x<2^20
=>4x<20
=>0<x<5
a) 125 : x + ( 32 + 15 ) = 72
125 : x + 47 = 72
125 : x = 72 - 47
125 : x = 25
x = 125 : 25
x = 5
b) ( 35 + 135 ) - 2 . x = 86
170 - 2 . x = 86
2 . x = 170 - 86
2 . x = 84
x = 84 : 2
x = 42
c) 7 . x - 5 = 65
7 . x = 65 + 5
7 . x = 70
x = 70 : 7
x = 10
A) 125 / x + (32 + 15) = 72
125 / x + 47 = 72
125 / x = 72 - 47
125 / x = 25
x = 125 / 25
x = 5
\(1.125+\left(x-5\right)=130\)
\(\Leftrightarrow125+x+5=130\)
\(\Leftrightarrow x=0\)
\(2.127-\left(5-x\right)=120\)
\(\Leftrightarrow127-5+x=120\)
\(\Leftrightarrow122+x=120\)
\(\Leftrightarrow x=-2\)
\(3.25-\left(x-3\right)=12-x\)
\(\Leftrightarrow25-x+3=12-x\)
\(\Leftrightarrow\left(25-x+3\right)-\left(12-x\right)=0\)
\(\Leftrightarrow25-x+3-12+x=0\)
\(\Leftrightarrow-x+x=-16\)
Vì \(x\in Z\) Nên \(x\) không tồn tại.
\(4.\left(-2\right)^3-\left(x-5\right)=-3+x\)
\(\Leftrightarrow-8-x+5-x=-3\)
\(\Leftrightarrow-2x=-3+8-5\)
\(\Leftrightarrow-2x=0\)
\(\Leftrightarrow x=0\)
\(5.\left(-2\right)^2-\left(6-x\right)=13\)
\(\Leftrightarrow4-6+x=13\)
\(\Leftrightarrow-2+x=12\)
\(\Leftrightarrow x=14\)
1, 125 + (x-5)=130
125+x-5=130
x-5=130-125
x-5=5
x=5+5=10
2, 127-(5-x)=120
127+5+x=120
5+x=120-127
5+x=-7
x=-7-5
x=-12
3, 25-(x-3)=12-x
25+x+3=12-x
28+x=12-x
x+x=12-28
2x=16
x=-8
4, \(\left(-2\right)^3-\left(x-5\right)=-3+x\)
\(\left(-2\right)^3\)+x+5=-3+x
\(\left(-2\right)^3\)+5+(-3)=x+x
-8+5-3=2x
-6=2x
x=-3
5, 3.\(\left(-2\right)^2\)-(6-x)=13
3.(-4)+6+x=13
-12+6+x=13
-6+x=13
x=13+6
x=19
5 ( x - 7 ) = 5
x - 7 = 1
=> x = 8
\(5.\left(x-7\right)=130-125=5\)
\(x-7=1,x=8\)