Question

[Đào Thu Ngoc]

tim x thuoc Q biet

|2,5-x|+|x-3|=0

Answer 1

[thám tử]

Vì \(\begin{matrix}\left|2,5-x\right|\ge0\forall x\\\left|x-3\right|\ge0\forall x\end{matrix}\)

Dấu "=" xảy ra \(\Leftrightarrow\left\{{}\begin{matrix}\left|2,5-x\right|=0\\\left|x-3\right|=0\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}2,5-x=0\\x-3=0\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=2,5\\x=3\end{matrix}\right.\) ( vô lí )

Vậy ko có giá trị nào thỏa mãn yêu cầu đề bài .

Answer 2

[hattori heiji]

Do |2,5-x|\(\ge0\forall x\)

|x-3|\(\ge0\forall x\)

=>\(\left|2,5-x\right|+\left|x-3\right|=0\)

=>\(\left[{}\begin{matrix}\left|2,5-x\right|=0\\\left|x-3\right|=0\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}2,5-x=0\Rightarrow x=2,5\\x-3=0\Rightarrow x=3\end{matrix}\right.\)

vậy x=2,5 hoặc x=3