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\(\dfrac{-1}{9}.\dfrac{3}{5}+\dfrac{-1}{4}.\dfrac{-4}{5}+\dfrac{1}{9}.\dfrac{2}{5}\)
\(\text{=}\dfrac{-1}{15}+\dfrac{1}{5}+\dfrac{2}{45}\)
\(\text{=}\dfrac{8}{45}\)
Áp dụng tính chất đổi dấu và giao hoán của phép nhân phân số, ta có:
\(\dfrac{-1}{9}.\dfrac{3}{5}+\dfrac{-1}{4}.\dfrac{-4}{5}+\dfrac{1}{9}.\dfrac{2}{5}=\dfrac{1}{5}.\dfrac{-3}{9}+\dfrac{1}{5}.\dfrac{4}{4}+\dfrac{1}{5}.\dfrac{2}{9}\)
\(=\dfrac{1}{5}\left(-\dfrac{3}{9}+1+\dfrac{2}{9}\right)\)
\(=\dfrac{1}{5}\left(-\dfrac{3}{9}+\dfrac{9}{9}+\dfrac{2}{9}\right)\)
\(=\dfrac{1}{5}.\dfrac{8}{9}\)
\(=\dfrac{8}{45}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1-3+5-7+...+21-23
=(1-3)+(5-7)+...+(21-23)
Tổng số cặp là:
[(23-1):2+1]:2=6
Nháp: [(23-1):2+1]:2=(22:2+1):2=12:2=6
=1-3=-2=-2*6=-12
Đây nha bạn.
Chúc bạn học tốt!
\(1-3+5-7+...+21-23\)
\(=\left(1+5+9+13+17+21\right)-\left(3+7+11+15+19+23\right)\)
\(=\left[\left(21-1\right):2+1\right].\left(21+1\right):2-\left[\left(23-3\right):2+1\right].\left(23+3\right):2\)
\(=11.11-11.13\)
\(=121-143\)
\(=-22\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\left(\left(\frac{-12}{16}\right)+\frac{7}{14}\right)-\left(\frac{1}{13}-\frac{3}{13}\right)\) \(=\left(\left(\frac{-3}{4}\right)+\frac{1}{2}\right)-\left(\frac{-2}{13}\right)\) \(=\left(\frac{-2}{8}\right)-\left(\frac{-2}{13}\right)\) \(=\left(\frac{-10}{104}\right)\) \(=\left(\frac{-5}{72}\right)\) | b) \(\frac{10}{11}+\frac{4}{11}:4-\frac{1}{8}\) \(=\frac{10}{11}+\frac{4}{11}:\frac{4}{1}-\frac{1}{8}\) \(=\frac{10}{11}+\frac{4}{11}\cdot\frac{1}{4}-\frac{1}{8}\) \(=\frac{10}{11}+\frac{1}{11}-\frac{1}{8}\) \(=\frac{11}{11}-\frac{1}{8}\) \(=1-\frac{1}{8}\) \(=\frac{7}{8}\) |
HT
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245 - 150 : [(23 - 13)2.(-4) -10] + 20233
= 245 - 150 : [(8 - 13)2..(-4) - 10] + 20233
= 245 - 150 : [(-5)2.(-4) - 10] + 20233
= 245 - 150 : [ -100 - 10] + 20233
= 245 - 150:(-110) + 20233
= 245 + \(\dfrac{15}{11}\) + 20233
= \(\dfrac{2710}{11}\) + 20233
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1500-\left\{5^3\cdot2^3-11\left[7^2-5\cdot2^3+8\left(11^2-121\right)\right]\right\}\\ =1500-\left[125\cdot8-11\left(49-5\cdot8+8\cdot0\right)\right]\\ =1500-\left[125\cdot8-11\left(49-40+0\right)\right]\\ =1500-\left(125\cdot8-11\cdot9\right)\\ =1500-\left(1000-99\right)\\ =1500-901\\ =599\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=5+5^2+5^3+5^4+...+5^{11}+5^{12}\)
\(=\left(5+5^2\right)+\left(5^3+5^4\right)+...+\left(5^{11}+5^{12}\right)\)
\(=\left(5+5^2\right)+5^2\left(5+5^2\right)+...+5^{10}\left(5+5^2\right)\)
\(=30\left(1+5^2+...+5^{10}\right)⋮30\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(112\cdot35+112\cdot65+800\)
\(=112\cdot\left(35+65\right)+800\)
\(=112\cdot100+800\)
\(=11200+800\)
\(=12000\)
\(-23-150+\left(-9\right)+1913\)
\(=1913-\left(23+150+9\right)\)
\(=1913-182\)
\(=1731\)
−23 − 150 + (−9) + 1913
= -23 + (-150) + (-9) + 1913
= -(23 + 150 + 9) + 1913 = -182 + 1913 = 1913 - 182
= 1731