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\(\frac{\left(-2\right)^3.3^3.5^3.7.8}{3.2^4.5^3.14}=\frac{2^5.3^3.5^3.7.\left(-2\right)}{3.2^5.5^3.7}=\frac{3^2.\left(-2\right)}{1}=-18\)
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a: 14/35=2/5
b: 23/62=23/62
c: -33/143=-3/11
d: -53/81=-53/81
e: \(\dfrac{2^2\cdot5^2}{2^5\cdot5^4}=\dfrac{1}{2^3\cdot5^2}=\dfrac{1}{8\cdot25}=\dfrac{1}{200}\)
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\(\dfrac{-2^3\cdot3^3\cdot5^3\cdot7\cdot8}{3\cdot5^3\cdot2^4\cdot42}\)
\(=\dfrac{-2^6\cdot3^3\cdot5^3\cdot7}{3\cdot5^3\cdot2^4\cdot2\cdot3\cdot7}\)
\(=\dfrac{-2^6\cdot3^3\cdot5^3}{2^5\cdot3^2\cdot5^3}=-2\cdot3=-6\)
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Ta có; \(\frac{\left(2^3.3^4\right)}{\left(2^2.3^3.5\right)}\Leftrightarrow\frac{\left(2^2.2^1.3^3.3^1\right)}{2^2.3^3.5}\Leftrightarrow\frac{\left(2.3\right)}{5}=\frac{6}{5}\)
Đs: \(\frac{6}{5}\)
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