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\(\dfrac{3}{5}và\dfrac{15}{25}và\dfrac{21}{35};\dfrac{5}{8}và\dfrac{20}{32}\)
\(\dfrac{3}{5}=\dfrac{9}{15}=\dfrac{15}{25}=\dfrac{21}{35}\\ \dfrac{5}{8}=\dfrac{20}{32}\)
a, \(\dfrac{3}{4}\) = \(\dfrac{3\times5}{4\times5}\) = \(\dfrac{15}{20}\) \(\dfrac{5}{7}\) = \(\dfrac{5\times3}{7\times3}\) = \(\dfrac{15}{21}\)
Vì \(\dfrac{15}{20}\) > \(\dfrac{15}{21}\) nên \(\dfrac{3}{4}\) > \(\dfrac{5}{7}\)
b, \(\dfrac{2}{7}\) = \(\dfrac{2\times2}{7\times2}\) = \(\dfrac{4}{14}\) < \(\dfrac{4}{9}\)
Vậy \(\dfrac{2}{7}\) < \(\dfrac{4}{9}\)
c, \(\dfrac{5}{8}\) < 1 < \(\dfrac{8}{5}\)
Vậy \(\dfrac{5}{8}\) < \(\dfrac{8}{5}\)
\(\dfrac{14}{21}=\dfrac{14:7}{21:7}=\dfrac{2}{3}=\dfrac{1}{3}+\dfrac{1}{3}\)
\(\dfrac{15}{29}=\dfrac{1+14}{29}=\dfrac{1}{29}+\dfrac{14}{29}\)
\(\dfrac{9}{35}=\dfrac{1+8}{35}=\dfrac{1}{35}+\dfrac{8}{35}\)
\(\dfrac{16}{27}=\dfrac{2+14}{27}=\dfrac{2}{27}+\dfrac{14}{27}\)
Ta có :
`8/3=(8xx2)/(3xx2)= 16/6`
`7/2=(7xx3)/(2xx3)= 21/6`
Mà `16/6 < 21/6`
`-> 8/3 < 7/2`
\(\dfrac{8}{3}\) = \(\dfrac{16}{6}\)
\(\dfrac{7}{2}\) = \(\dfrac{21}{6}\)
Vì \(\dfrac{16}{6}\) < \(\dfrac{21}{6}\)
nên \(\dfrac{8}{3}\) < \(\dfrac{7}{2}\)
a) Ta có: \(\dfrac{6}{11}=\dfrac{18}{33}\);
\(\dfrac{23}{33}=\dfrac{23}{33}\)
\(\dfrac{2}{3}=\dfrac{22}{33}\)
Do đó: \(\dfrac{6}{11}< \dfrac{2}{3}< \dfrac{23}{33}\)
b) Ta có: \(1>\dfrac{8}{9}>\dfrac{8}{11}\)
\(\dfrac{9}{8}=\dfrac{8}{8}>1\)
Do đó: \(\dfrac{9}{8}>\dfrac{8}{9}>\dfrac{8}{11}\)
a) \(\dfrac{6}{11};\dfrac{2}{3};\dfrac{23}{33}\)
b) \(\dfrac{9}{8};\dfrac{8}{9};\dfrac{8}{11}\)
\(\dfrac{13}{2}=6,5=\dfrac{65}{10}\)
\(\dfrac{11}{40}=0,275=\dfrac{275}{1000}\)
\(\dfrac{32}{5}=6,4=\dfrac{64}{10}\)
\(\dfrac{21}{250}=0,084=\dfrac{84}{1000}\)
\(\dfrac{1}{200}=0,005=\dfrac{5}{1000}\)
\(\dfrac{20}{21}\)
\(\dfrac{20}{21}\)