TT
1
K
Khách
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NK
2
15 tháng 1 2022
a: \(\left(x,y\right)\in\left\{\left(-9;1\right);\left(-1;9\right);\left(-3;3\right)\right\}\)
b: \(\left(x,y\right)\in\left\{\left(1;7\right);\left(-7;-1\right)\right\}\)
c: \(\left(x,y\right)\in\left\{\left(11;-1\right);\left(-11;1\right)\right\}\)
LV
1
H
19 tháng 12 2021
31. I was very sleepy but I still wanted to watch the football match on TV.
Although ___I was very sleepy, I still wanted to watch the football match on TV.
32. “Do you know what the time is, Mary?” asked John.
John asked ______Mary if she knew what the time was_____________
33. The teacher is introducing a new game. A new __game is being introduced by the teacher______________________________________
34. I haven’t been in this village since May.
The last time _______I went to this village was in May____________
19 tháng 12 2021
31. I was very sleepy but I still wanted to watch the football match on TV.
Although ___I was very sleepy, I still wanted to watch the football match on TV.
32. “Do you know what the time is, Mary?” asked John.
John asked ______Mary if she knew what the time was_____________
33. The teacher is introducing a new game. A new __game is being introduced by the teacher______________________________________
34. I haven’t been in this village since May.
The last time _______I went to this village was in May____________
16 tháng 12 2021
dạ thưa mọe là bằng là bằng 11 có thế mà cũn ko tính đc
LT
1
S
16 tháng 2 2020
You are a young buffalo bruh
\(-x^4+x^3+x-1=x^3\left(1-x\right)-\left(1-x\right)=\left(x^3-1\right)\left(1-x\right)=\left(x-1\right)\left(1-x\right)\left(x^2+x+1\right)=0\)
then x=1 since \(x^2+x+1=\left(x+\frac{1}{2}\right)^2+\frac{3}{4}>0\)
and the final answer is 1
16 tháng 2 2020
Good news:
- I traveled from Singapore to Vietnam yesterday!!! Yay !!!(Of course by plane)
- Now i am learning 2 languages(Vietnamese & Englis)
it is 0 please k for my answer thank you very much