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dấu <=> thứ 4 em làm nhầm rồi, 4x - 6x = - 2x chứ! Rồi tiếp theo em nên đưa về hằng đẳng thức chứ giải vậy ko đc đâu.
Bài2:
a: \(Q=\left(\dfrac{2x+1}{x\left(x-5\right)}-\dfrac{2x}{x\left(x+5\right)}\right)\cdot\dfrac{x\left(x-5\right)\left(x+5\right)}{21x-2}\)
\(=\dfrac{2x^2+11x+5-2x^2+10x}{x\left(x-5\right)\left(x+5\right)}\cdot\dfrac{x\left(x-5\right)\left(x+5\right)}{21x-2}\)
\(=\dfrac{21x+5}{21x-2}\)
b: Để Q là số nguyên thì \(21x-2+7⋮21x-2\)
\(\Leftrightarrow21x-2\in\left\{1;-1;7;-7\right\}\)
hay \(x\in\left\{\dfrac{1}{7};\dfrac{1}{21};\dfrac{3}{7};-\dfrac{5}{21}\right\}\)
Bài 1:
a) Ta có: \(E=\left(2x+5\right)^2-5\left(x-4\right)\left(x+4\right)-3\left(x-2\right)^3\)
\(=4x^2+20x+25-5\left(x^2-16\right)-3\left(x^3-6x^2+12x-8\right)\)
\(=4x^2+20x+25-5x^2+60-3x^3+18x^2-36x+24\)
\(=-3x^3+17x^2-16x+109\)
b) Ta có: \(F=\left(2x-3\right)^3-4\left(2x+4\right)^2+3\left(x+3\right)\left(x^2-3x+9\right)\)
\(=8x^3-36x^2+54x-27-4\left(4x^2+16x+16\right)+3\left(x^3+27\right)\)
\(=8x^3-36x^2+54x-27-16x^2-64x-64+3x^3+81\)
\(=11x^3-52x^2-10x-10\)
c) Ta có: \(G=\left(2x+1\right)^2-3\left(x+2\right)\left(x^2-2x+4\right)+\left(x+3\right)^3\)
\(=4x^2+4x+1-3\left(x^3+8\right)+x^3+9x^2+27x+27\)
\(=x^3+13x^2+31x+28-3x^3-24\)
\(=-2x^3+13x^2+31x+4\)
a) 2x + 1 = 5 - 5x
=> 2x + 5x = 5 - 1
=> 7x = 4
=> x = 4/7
b) 3x - 2 = 2x + 5
=> 3x - 2x = 5 + 2
=> x = 7
c) 7(x - 2) = 5(3x + 1)
=> 7x - 14 = 15x + 5
=> 7x - 15x = 5 + 14
=> - 8x = 19
=> x = - 19/8
d) 2x + 5 = 20 - 3x
=> 2x + 3x = 20 - 5
=> 5x = 15
=> x = 3
e) x - 3 = 18 - 5x
=> x + 5x = 18 + 3
=> 6x = 21
=> x = 21/6 = 7/2
Dạng 1: Rút gọn
Bài 1
a) Rút gọn
P= (\(\dfrac{8}{x^2-16}+\dfrac{1}{x+4}\)):\(\dfrac{1}{x^2-2x-8}\)
= (\(\dfrac{8}{\left(x+4\right)\left(x-4\right)}+\dfrac{x-4}{\left(x+4\right)\left(x-4\right)}\)):\(\dfrac{1}{\left(x-4\right)\left(x+2\right)}\)
= \(\dfrac{x+4}{\left(x+4\right)\left(x-4\right)}:\dfrac{1}{\left(x-4\right)\left(x+2\right)}\)
= \(\dfrac{1}{x-4}.\left(x-4\right)\left(x+2\right)\)
= x+2
Bài 2
a) Rút gọn
D=(\(\dfrac{1}{x-1}-\dfrac{x}{1-x^3}.\dfrac{x^2+x+1}{x+1}\)):\(\dfrac{2x+1}{x^2+x+1}\)
= (\(\dfrac{1}{x-1}+\dfrac{x}{\left(x-1\right)\left(x+1\right)}\)):\(\dfrac{2x+1}{x^2+x+1}\)
= \(\dfrac{2x+1}{\left(x+1\right)\left(x-1\right)}\).\(\dfrac{x^2+x+1}{2x+1}\)
= \(\dfrac{x^2+x+1}{\left(x+1\right)\left(x-1\right)}\)
b) Tìm x∈Z để D∈Z
D=\(\dfrac{x^2+x+1}{\left(x+1\right)\left(x-1\right)}=\dfrac{x^2+x+1}{x^2-1}=\dfrac{x^2-1}{x^2-1}+\dfrac{x+2}{x^2-1}=1+\dfrac{x+2}{x^2-1}\)Để D nguyên thì x+2=0⇔x=-2(t/m)
Vậy ...........................
Dạng 2: Phương trình
Bài 1. Giải phương trình
a) 2x+1=5-5x
⇔ 2x+5x=5-1
⇔ 7x=4
⇔ x=\(\dfrac{4}{7}\)
Vậy S=\(\left\{\dfrac{4}{7}\right\}\) là tập nghiệm của hương trình
b) 3x-2=2x+5
⇔ 3x-2x=5+2
⇔ x=7
Vậy......................
c) 7(x-2)=5(3x+1)
⇔ 7x-14=15x+5
⇔ 7x-15x=5+14
⇔ -8x=19
⇔ x=-\(\dfrac{19}{8}\)
Vậy..........................
d) 2x+5=20-3x
⇔ 2x+3x=20-5
⇔ 5x=15
⇔ x=3
Vậy...................
e) x-3=18-5x
⇔ x+5x=18+3
⇔ 6x=21
⇔ x=\(\dfrac{7}{2}\)
Vậy..............................
a) x(2x^2 -3) -x^2 (5x+1 ) + x^2
<=> 2x^3 -3x -5x^3 -x^2 +x^2
<=>3x^3 -3x
b) 3x(x-2) -5x(1-x)-8(x^2 -3)
=3x^2 -6x -5x +5x^2 -8x^2 +24
= -11x+24
Bài 2:
a: \(M=\dfrac{x^2+2x}{2\left(x+5\right)}+\dfrac{x-5}{x}+\dfrac{50-5x}{2x\left(x+5\right)}\)
\(=\dfrac{x^3+2x^2+2\left(x-5\right)\left(x+5\right)+50-5x}{2x\left(x+5\right)}\)
\(=\dfrac{x^3+2x^2+50-5x+2x^2-50}{2x\left(x+5\right)}\)
\(=\dfrac{x^3+4x^2-5x}{2x\left(x+5\right)}=\dfrac{x\left(x^2+4x-5\right)}{2x\left(x+5\right)}=\dfrac{x-1}{2}\)
b: Khi x=3 thì \(M=\dfrac{3-1}{2}=\dfrac{2}{2}=1\)
Khi x=5 thì \(M=\dfrac{5-1}{2}=\dfrac{4}{2}=2\)
Bài 1:
a) \(\left(6x+1\right)^2+\left(6x-1\right)^2-2\left(1+6x\right)\left(6x-1\right)\)
\(=36x^2+72x+1+36x^2-72x+1-2\left(36x^2-1\right)\)
\(=36x^2+72x+1+36x^2-72x+1-72x^2+2\)
\(=4\)
b) \(3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^{16}-1\right)\left(2^{16}+1\right)\)
\(=2^{32}-1\)
c) \(x\left(2x^3-3\right)-x^2\left(5x+1\right)+x^2\)
\(=2x^4-3x-5x^3-x^2+x^2\)
\(=2x^4-5x^3-3x\)
d) \(3x\left(x-2\right)-5x\left(1-x\right)-8\left(x^2-3\right)\)
\(=3x^2-6x-5x+5x^2-8x^2+24\)
\(=-11x+24\)
a: =2x^2+6x-2x^2+x
=7x
b: =2x^2-3x-2x+3-x^2+4x-4
=x^2-x-1
c: \(=9x^2-6x+1+2x^2-x+6x-3=11x^2-x-2\)
d: \(=x^3+2x^2-x-2-x^3+8=2x^2-x+6\)