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28 tháng 6 2017

a)\(7x\left(y-4\right)^2-\left(4-y\right)^3=7x\left(4-y\right)^2-\left(4-y\right)^3=\left(4-y\right)^2\left(7x-4+y\right)\)

b)\(\left(4x-8\right)\left(x^2+6\right)-\left(4x-8\right)\left(x+7\right)+9\left(8-4x\right)\)

\(=\left(4x-8\right)\left(x^2+6\right)-\left(4x-8\right)\left(x+7\right)-9\left(4x-8\right)\)

\(=\left(4x-8\right)\left(x^2-x-10\right)=4\left(x-2\right)\left(x^2-x-10\right)\)

28 tháng 6 2017

a.\(7x.\left(y-4\right)^2-\left(4-y\right)^3\)=\(7x.\left(4-y\right)^2-\left(4-y\right)^3=\left(4-y\right)^2.\left(7x+y-4\right)\)

b.\(\left(4x-8\right).\left(x^2+6\right)-\left(4x-8\right)\left(x+7\right)+9.\left(8-4x\right)\)

=\(\left(4x-8\right)\left(x^2+6-x-7-9\right)=\left(4x-8\right)\left(x^2-x-10\right)\)

6 tháng 9 2017

Ta có : 5x(x - 2y) + 2(2y - x)2

= 5x(x - 2y) + 2(x - 2y)2 (vì (2y - x)2 = (x - 2y)2 )

= (x - 2y)[5x + 2(x - 2y)]

= (x - 2y)(5x + 2x - 4y)

= (x - 2y)(7x - 4y)

b) 7x(y - 4)2 - (4 - y)3 

= 7x(y - 4)2 - (4 - y)2(4 - y)

= 7x(y - 4)2 - (y - 4)2(4 - y)

= (y - 4)2(7x - 4 + y)

c) (4x - 8)(x2 + 6) - (4x - 8)(x + 7) + 9(8 - 4x)

= (4x - 8)(x2 + 6) - (4x - 8)(x + 7) - 9(4x - 8)

= (4x - 8)(x2 + 6 - x - 7 - 9)

= 2(x - 4)(x2 - x - 10)

16 tháng 10 2021

\(1,\\ a,=7x^3-49x^2+21x\\ b,=x^2-x-42\\ c,=x^2-16x+64\\ d,=9x^2+12x+4\\ e,=x^2-16-25+10x-x^2=10x-41\\ 2,\\ a,\Rightarrow2\left(x-7\right)=19\\ \Rightarrow x-7=\dfrac{19}{2}\Rightarrow x=\dfrac{33}{2}\\ b,\Rightarrow4x^2-20x+25-4x^2+3x-2x=50\\ \Rightarrow-19x=25\Rightarrow x=-\dfrac{25}{19}\)

AH
Akai Haruma
Giáo viên
14 tháng 8 2019

a)

\(5x(x-2y)+2(2y-x)^2=5x(x-2y)+2(x-2y)^2\)

\(=(x-2y)[5x+2(x-2y)]=(x-2y)(7x-4y)\)

b)

\(7x(y-4)^2-(4-y)^3=7x(y-4)^2+(y-4)^3=(y-4)^2(7x+y-4)\)

c)

\((4x-8)(x^2+6)-(4x-8)(x+7)+9(8-4x)\)

\(=(4x-8)(x^2+6)-(4x-8)(x+7)-9(4x-8)\)

\(=(4x-8)[(x^2+6)-(x+7)-9]=(4x-8)(x^2-x-10)=4(x-2)(x^2-x-10)\)

d)

\(x^2-xz-9y^2+3yz=(x^2-9y^2)-(xz-3yz)\)

\(=(x-3y)(x+3y)-z(x-3y)=(x-3y)(x+3y-z)\)

e)

\(x^2(x^2-6)-x^2+9=x^4-7x^2+9=(x^4-6x^2+9)-x^2\)

\(=(x^2-3)^2-x^2=(x^2-3-x)(x^2-3+x)\)

AH
Akai Haruma
Giáo viên
12 tháng 8 2019

a)

\(5x(x-2y)+2(2y-x)^2=5x(x-2y)+2(x-2y)^2\)

\(=(x-2y)[5x+2(x-2y)]=(x-2y)(7x-4y)\)

b)

\(7x(y-4)^2-(4-y)^3=7x(y-4)^2+(y-4)^3=(y-4)^2(7x+y-4)\)

c)

\((4x-8)(x^2+6)-(4x-8)(x+7)+9(8-4x)\)

\(=(4x-8)(x^2+6)-(4x-8)(x+7)-9(4x-8)\)

\(=(4x-8)[(x^2+6)-(x+7)-9]=(4x-8)(x^2-x-10)=4(x-2)(x^2-x-10)\)

d)

\(x^2-xz-9y^2+3yz=(x^2-9y^2)-(xz-3yz)\)

\(=(x-3y)(x+3y)-z(x-3y)=(x-3y)(x+3y-z)\)

e)

\(x^2(x^2-6)-x^2+9=x^4-7x^2+9=(x^4-6x^2+9)-x^2\)

\(=(x^2-3)^2-x^2=(x^2-3-x)(x^2-3+x)\)