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TN
0
T
22 tháng 8 2023
\(1)\)\(-\dfrac{10}{11}.\dfrac{8}{9}+\dfrac{7}{18}.\dfrac{10}{11}\)
\(=\dfrac{10}{11}\left(-\dfrac{8}{9}+\dfrac{7}{18}\right)\)
\(=\dfrac{10}{11}\left(\dfrac{-16}{18}+\dfrac{7}{18}\right)\)
\(=\dfrac{10}{11}.\left(-\dfrac{1}{2}\right)=-\dfrac{5}{11}\)
\(2)\)\(\dfrac{12}{25}.\dfrac{23}{7}-\dfrac{12}{7}.\dfrac{13}{25}\)
\(=\dfrac{12}{7}.\dfrac{23}{25}-\dfrac{12}{7}.\dfrac{13}{25}\)
\(=\dfrac{12}{7}.\left(\dfrac{23}{25}-\dfrac{13}{25}\right)\)
\(=\dfrac{12}{7}.\dfrac{2}{5}=\dfrac{24}{35}\)
\(3)\)\(\dfrac{3}{7}.\dfrac{16}{15}-\dfrac{2}{15}.\dfrac{-3}{7}\)
\(=\dfrac{3}{7}.\dfrac{16}{15}-\dfrac{3}{7}.\dfrac{-2}{15}\)
\(=\dfrac{3}{7}.\left(\dfrac{16}{15}+\dfrac{2}{15}\right)\)
\(=\dfrac{3}{7}.\dfrac{18}{15}=\dfrac{18}{35}\)
\(4)\)\(-\dfrac{4}{13}.\dfrac{5}{17}+\dfrac{-12}{13}.\dfrac{4}{17}\)
\(=-\dfrac{4}{13}.\dfrac{5}{17}+\dfrac{-4}{13}.\dfrac{12}{17}\)
\(=-\dfrac{4}{13}.\left(\dfrac{5}{17}+\dfrac{12}{17}\right)\)
\(=-\dfrac{4}{13}.\dfrac{17}{17}=-\dfrac{4}{13}\)
22 tháng 8 2023
`#040911`
`1)`
`-10/11 * 8/9 + 7/18 . 10/11`
`= 10/11 * (-8/9 + 7/18)`
`= 10/11 * (-1/2)`
`= -5/11`
`2)`
`12/25 * 23/7 - 12/7 *13/25`
`= 12/7 * 23/25 - 12/7 * 13/25`
`= 12/7 * (23/25 - 13/25)`
`= 12/7 * 2/5`
`= 24/35`
`3)`
`3/7 * 16/15 - 2/15 * (-3)/7`
`= 3/7 * (16/15 + 2/15)`
`= 3/7 * 6/5`
`= 18/35`
`4)`
`-4/13 * 5/17 + (-12)/13 * 4/17`
`= -4/17 * 5/13 + (-12)/13 * 4/17`
`= 4/17 * (-5/13 - 12/13)`
`= 4/17 * (-17)/13`
`= -4/13`
SB
2
H9
HT.Phong (9A5)
CTVHS
12 tháng 7 2023
\(-\dfrac{3}{16}+-\dfrac{3}{8}-\dfrac{5}{4}\)
\(=-\dfrac{3}{16}-\dfrac{3}{8}-\dfrac{5}{4}\)
\(=-\dfrac{3}{16}-\dfrac{6}{16}-\dfrac{20}{16}\)
\(=\dfrac{-3-6-20}{16}\)
\(=-\dfrac{29}{16}\)
\(\left(-\dfrac{25}{13}\right)+\dfrac{-9}{17}+\dfrac{12}{13}+\dfrac{25}{17}\)
\(=\left[\left(-\dfrac{25}{13}\right)+\dfrac{12}{13}\right]+\left[\left(-\dfrac{9}{17}+\dfrac{25}{17}\right)\right]\)
\(=-\dfrac{13}{13}+\dfrac{17}{17}\)
\(=-1+1\)
\(=0\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
21 tháng 8 2023
\(\dfrac{-4}{13}.\dfrac{5}{17}+\dfrac{-12}{13}.\dfrac{4}{17}\)
= \(\dfrac{-4}{13}.\dfrac{5}{17}+\dfrac{-4}{13}.\dfrac{12}{17}\)
= \(\dfrac{-4}{13}.\left(\dfrac{5}{17}+\dfrac{12}{17}\right)\)
= \(\dfrac{-4}{13}.\dfrac{17}{17}\)
= \(\dfrac{-4}{13}.1\)
= \(\dfrac{-4}{13}\)
PD
Phan Đức Linh
VIP
21 tháng 8 2023
= \(\dfrac{-4.5-12.4}{13.17}\)
=\(\dfrac{-4\left(5+12\right)}{13.17}\)
=\(\dfrac{-4.17}{13.17}\)
=\(\dfrac{-4}{13}\)
KS
2
AN
26 tháng 12 2017
\(-\dfrac{4}{13}.\dfrac{5}{17}+-\dfrac{12}{17}.\dfrac{4}{13}+\dfrac{4}{13}\)
= \(-\dfrac{4}{13}.\dfrac{5}{17}+-\dfrac{12}{17}.\dfrac{4}{13}+\dfrac{4}{13}.1\)
=\(\dfrac{4}{13}.\left(\dfrac{-5}{17}+\dfrac{-12}{17}+1\right)\)
= \(\dfrac{4}{13}.\left(-1+1\right)\)
= \(\dfrac{4}{13}.0\)
= 0
23 tháng 11 2019
\(\frac{-4}{13}.\frac{5}{17}+\frac{-12}{13}.\frac{4}{17}+\frac{4}{13}\)
\(=\frac{4}{13}.\frac{-5}{17}+\frac{-12}{17}.\frac{4}{13}+\frac{4}{13}\)
\(=\frac{4}{13}.\left(\frac{-5}{17}+\frac{-12}{17}+1\right)\)
\(=\frac{4}{13}.0\)
\(=0\)
31 tháng 8 2017
\(\left(\frac{-4}{13}+\frac{4}{13}+\frac{-12}{13}\right)\times\left(\frac{5}{17}+\frac{4}{17}\right)\)
\(=\)\(\frac{-12}{13}\times\left(\frac{5}{17}+\frac{4}{17}\right)\)
\(=\)\(\frac{-12}{13}\times\frac{9}{17}=\frac{-106}{221}\)
\(-\dfrac{4}{13}.\dfrac{5}{17}+\left(-\dfrac{12}{13}\right).\dfrac{4}{17}+\dfrac{4}{13}.\)
\(=\dfrac{4}{13}.\left(-\dfrac{5}{17}\right)+\left(-\dfrac{12}{17}\right).\dfrac{4}{13}+\dfrac{4}{13}.1\)
\(=\dfrac{4}{13}\left[\left(-\dfrac{5}{17}\right)+\left(-\dfrac{12}{17}\right)+1\right].\)
\(=\dfrac{4}{13}.\left[-1+1\right].\)
\(=\dfrac{4}{13}.0=0.\)
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