B=-3/11:2/9+-3/11.7/3
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9 tháng 1 2023
a: \(\dfrac{-3}{25}\cdot\dfrac{4}{17}\cdot\dfrac{5}{-3}\cdot\dfrac{17}{2}=\dfrac{4}{17}\cdot\dfrac{17}{2}\cdot\dfrac{3}{25}\cdot\dfrac{5}{3}=2\cdot\dfrac{1}{5}=\dfrac{2}{5}\)
b: \(=-\dfrac{8}{15}\cdot\dfrac{13}{16}\cdot\dfrac{30}{13}=\dfrac{-8}{15}\cdot\dfrac{15}{8}=-1\)
c: \(=\dfrac{3}{11}\left(\dfrac{2}{9}\cdot\dfrac{-8}{33}+\dfrac{7}{9}\right)=\dfrac{3}{11}\cdot\dfrac{215}{297}=\dfrac{2015}{1089}\)
ET
0
DV
1
NK
2
23 tháng 4 2018
a)7/19.8/11+3/11.7/19+-12/19
=7/19.(8/11+3/11)+-12/19
=7/19.1+-12/19
=7/19+-12/19
=-5/19
23 tháng 4 2018
a)
\(\dfrac{7}{19}\cdot\dfrac{8}{11}+\dfrac{3}{11}\cdot\dfrac{7}{19}+\dfrac{-12}{19}\\ =\dfrac{7}{19}\cdot\left(\dfrac{8}{11}+\dfrac{3}{11}\right)+\dfrac{-12}{19}=\dfrac{7}{19}\cdot1+\dfrac{-12}{19}=\dfrac{7}{19}+\dfrac{-12}{19}=\dfrac{5}{19}\)
DT
0
T
13 tháng 2 2018
1. Tìm x, biết:
a) \(\frac{4}{x}=\frac{8}{6}\). Ta có: \(\frac{8}{6}=\frac{8:2}{6:2}=\frac{4}{3}\Rightarrow x=3\)
b) \(\frac{3}{x-5}=\frac{4}{x+2}\). Ta có: \(5-2=3\)
\(\Rightarrow x=\left(3.5\right)+\left(4.2\right)+3=15+8+3=26\)
c) \(\frac{x}{-2}=\frac{-8}{x}\Rightarrow x=\left(-8\right):\left(-2\right)=4\)
2. Rút gọn
a) \(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}\Leftrightarrow\frac{2^3.2^1.5^2.11.11.7}{2^3.5^2.5^1.7.7.11}\Leftrightarrow\frac{2^1.11}{5^1.7}=\frac{22}{35}\)
b) Tương tự
c) Tương tự
13 tháng 2 2018
\(\frac{4}{x}=\frac{8}{6}\Rightarrow x=\frac{4.6}{8}=3\)
\(\frac{3}{x-5}=\frac{-4}{x+2}\Rightarrow3\left(x+2\right)=-4\left(x-5\right)\)
\(\Rightarrow3x+6=-4x+20\)
\(\Rightarrow3x+4x=20-6\)
\(\Rightarrow7x=14\)
\(\Rightarrow x=2\)
\(\frac{x}{-2}=\frac{-8}{x}\Rightarrow x^2=\left(-8\right)\left(-2\right)=16\Rightarrow x=\pm4\)
\(-\dfrac{3}{11}:\dfrac{2}{9}+\dfrac{-3}{11}\cdot\dfrac{7}{3}\)
\(=-\dfrac{3}{11}\cdot\dfrac{9}{2}+\dfrac{-3}{11}\cdot\dfrac{7}{3}\)
\(=-\dfrac{3}{11}\left(\dfrac{9}{2}+\dfrac{7}{3}\right)\)
\(=-\dfrac{3}{11}\cdot\dfrac{27+14}{6}=\dfrac{-3}{6}\cdot\dfrac{41}{11}=\dfrac{-1}{2}\cdot\dfrac{41}{11}=\dfrac{-41}{22}\)