Question

[thảo nguyễn thanh]

Bài 6 ; tính nhanh:

a, A =\(1993^{1^{2\times3\times4\times......\times1994}}\)

b, B =\(1994^{\left(225-1^2\right)\times\left(225-2^2\right).......\left(225-50^2\right)}\)

c, C =\(\frac{2^{10}\times3^{31}+2^{40}\times3^6}{2^{11}\times3^{31}+2^{41}\times3^6}\)

Answer 1

[Thiên Thần Hye Kyo]

a,\(A=1993^{1^{2\times3\times4\times...\times1994}}=1993^1=1993\)

b,\(B=1994^{\left(225-1^2\right)\times\left(225-2^2\right).....\left(225-50^2\right)}\)

     \(=1994^{\left(225-1^2\right)\times\left(225-2^2\right)...\left(225-15^2\right)...\left(225-50^2\right)}\)

     \(=1994^{\left(225-1^2\right)\times\left(225-2^2\right)...\left(225-225\right)...\left(225-50^2\right)}\)

     \(=1994^{\left(225-1^2\right)\times\left(225-2^2\right)...\times0\times...\left(225-50^2\right)}\)

     \(=1994^0=1\)

c, \(C=\frac{2^{10}\times3^{31}+2^{40}\times3^6}{2^{11}\times3^{31}+2^{41}\times3^6}\)

       \(=\frac{2^{10}\times3^6\times\left(1\times3^{25}+2^{30}\times1\right)}{2^{11}\times3^6\times\left(1\times3^{25}+2^{30}\times1\right)}\)

       \(=\frac{2^{10}}{2^{11}}=\frac{1}{2}\)