1/2+1/6+1/12+1/20+...+1/420
K
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31 tháng 1 2018
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{420}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{20.21}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{20}-\frac{1}{21}\)
\(=1-\frac{1}{21}\)
\(=\frac{20}{21}\)
DK
1
25 tháng 8 2023
\(\left(x+\dfrac{1}{2}\right)+\left(x+\dfrac{1}{6}\right)+\left(x+\dfrac{1}{12}\right)+...+\left(x+\dfrac{1}{420}\right)=20\)
\(\left(x+x+x+...+x\right)+\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{420}\right)=20\) (20 số x)
\(20x+\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{20}-\dfrac{1}{21}\right)=20\)
\(20x+\left(1-\dfrac{1}{21}\right)=20\)
\(20x+\dfrac{20}{21}=20\)
\(20x=20-\dfrac{20}{21}\)
\(20x=\dfrac{400}{21}\)
\(x=\dfrac{400}{21}:20\)
\(x=\dfrac{400}{21}.\dfrac{1}{20}\)
\(x=\dfrac{20}{21}\)
NB
2
HL
7 tháng 3 2017
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+......+\frac{1}{420}+\frac{1}{462}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{20.21}+\frac{1}{21.22}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+......+\frac{1}{20}-\frac{1}{21}+\frac{1}{21}-\frac{1}{22}\)
\(=1-\frac{1}{22}\)
\(=\frac{22}{22}-\frac{1}{22}=\frac{21}{22}\)
NV
1
HQ
Hà Quang Minh
Giáo viên
4 tháng 8 2023
\(A=\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+...+\dfrac{1}{420}\\ \Rightarrow A=\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+...+\dfrac{1}{20\times21}\\ \Rightarrow A=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{20}-\dfrac{1}{21}\\\Rightarrow A=\dfrac{1}{2}-\dfrac{1}{20}=\dfrac{9}{20}\)
H9
HT.Phong (9A5)
CTVHS
4 tháng 8 2023
Sau khi rút gọn phải còn:
\(A=\dfrac{1}{2}-\dfrac{1}{21}\) (chứ anh)
\(A=\dfrac{19}{42}\)
4 tháng 9 2021
Ta có: \(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{420}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{20}-\dfrac{1}{21}\)
\(=1-\dfrac{1}{21}=\dfrac{20}{21}\)
4 tháng 9 2021
\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{420}\\ =\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{20.21}\\ =1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-....-\dfrac{1}{21}+\dfrac{1}{21}\\ =1-\dfrac{1}{21}\\ =\dfrac{20}{21}\)
NT
0