1. Tính :
a) 11 : 4 + 5,3 × 3,8 =
b) 16,52 : 0,5 - 2,7 : 0,25 =
c) 7/5 : 2/3 : 1,05 - 4/9 =
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a, y + y : 0, 5 + y : 0,25 = 1,05
y x 1 + y x 2 + y x 4 = 1,05
y x ( 1 + 2 + 4 ) = 1,05
y x 7 = 1,05
y = 1,05 : 7
y = 0,15
bài 1 ( bỏ )
2,5 x 9,3 x 4 = ( 2,5 x 9,3 )
= 10 x 9,3
= 93
0,5 x 3,8 x 2 = ( 0,5 x 2 ) x 3,8
= 1 x 3,8
3,8
7,61 x 5 x 02 = 7,61 x ( 0,5 x 2 )
= 7,61 x 1
7,61
5,3 x 6,7 + x 6,7 x 4,7 = ( 5,3 + 4,7 ) x 6,7
= 10 x 6,7
67
Bài 1:
3/5x8/9=3x8/5x9=8/15
Bài 2:
a) 2,5x9,3x4=(2,5x4)x9,3=10x9,3=93
b) 0,5x3,8x2=(0,5x2)x3,8=1x3,8=3,8
c)7,61x5x0,2=7,61x(5x0,2)=7,61x1=7,61
d) 5,3x6,7+6,7x4,7=6,7x(5,3+4,7)=6,7x10=67
a=113/13-(24/7+53/13)=113/13-24/7-53/13=60/13-24/7=396/16
b=(64/9+37/11)-44/9=64/9+37/11-44/9=20/9+37/11=181/33
c=-5/7(2/11+9/11)+15/7=-5/7+15/7=10/7
d=0.7.22/3.20.0.375.5/28=0
e=(6,17+35/9-236/97)(1/3-0.25-1/12)=A.(1/3-1/4-1/12)=A.(1/12-1/12)=A.0=0
e=(6,17 + 3 5/9 - 2 36/97 ) . ( 1/3 - 0,25 - 1/12)=(6,17 + 3 5/9 - 2 36/97 ) .(1/3-1/12-0,25)
=(6,17 + 3 5/9 - 2 36/97 ) .(4/12-1/12-0,25)=(6,17 + 3 5/9 - 2 36/97 ) .(3/12-0,25)
=(6,17 + 3 5/9 - 2 36/97 ) .(1/4-0.25)=(6,17 + 3 5/9 - 2 36/97 ) .(0.25-0.25)
=(6,17 + 3 5/9 - 2 36/97 ) .0=0
Vậy E=0
a) \(\left[\left(-2,7\right)^4\right]^5-\left[\left(-2,7\right)^2\right]^{20}\)
\(=\left(-2,7\right)^{20}-\left(-2,7\right)^{20}\)
\(=0\)
b) \(\left(-0,5\right)^5:\left(-0,5\right)^3-\left(\dfrac{17}{2}\right)^7:\left(\dfrac{17}{2}\right)^6\)
\(=\left(-0,5\right)^2-\dfrac{17}{2}\)
\(=0,25-\dfrac{17}{2}\)
\(=-8,25\)
c) \(\left(8^{14}:4^{12}\right):\left(16^6:8^2\right)\)
\(=8^{14}:4^{12}:16^6\cdot8^2\)
\(=2^{48}:2^{24}:2^{24}\)
\(=0\)
\(\left(\frac{5}{7}+\frac{2}{3}\right).\frac{7}{11}\)
C1:\(=\frac{29}{21}.\frac{7}{11}=\frac{29}{33}\)(tính trong ngoặc rồi mới nhân)
C2:\(=\frac{5}{7}.\frac{7}{11}+\frac{2}{3}.\frac{7}{11}=\frac{5}{11}+\frac{14}{33}=\frac{29}{33}\)(dùng tính chất phân phối)
Những câu khác bn tự làm nha
Mik làm Bài 2 nhé ~
Bài 2 :
a) \(x-\dfrac{1}{2}=-\dfrac{1}{10}\)
\(x=-\dfrac{1}{10}+\dfrac{1}{2}\)
\(x=\dfrac{2}{5}\)
b) \(\dfrac{2}{3}x-\dfrac{7}{6}=\dfrac{5}{2}\)
\(\dfrac{2}{3}x=\dfrac{5}{2}+\dfrac{7}{6}\)
\(\dfrac{2}{3}x=\dfrac{11}{3}\)
\(x=\dfrac{11}{3}:\dfrac{2}{3}\)
\(x=\dfrac{11}{3}.\dfrac{3}{2}\)
\(x=\dfrac{11}{2}\)
c) \(2,5-\left(\dfrac{1}{8}x+\dfrac{1}{2}\right)=\dfrac{3}{4}\)
\(\left(\dfrac{1}{8}x+\dfrac{1}{2}\right)=2,5-\dfrac{3}{4}\)
\(\left(\dfrac{1}{8}x+\dfrac{1}{2}\right)=\dfrac{5}{2}-\dfrac{3}{4}\)
\(\dfrac{1}{8}x+\dfrac{1}{2}=\dfrac{7}{4}\)
\(\dfrac{1}{8}x=\dfrac{7}{4}-\dfrac{1}{2}\)
\(\dfrac{1}{8}x=\dfrac{5}{4}\)
\(x=10\)
Bài 1:
a) \(\dfrac{-4}{11}.\dfrac{7}{9}+\dfrac{-4}{11}.\dfrac{2}{9}-\dfrac{7}{11}\)
\(=\dfrac{-4}{11}.\left(\dfrac{7}{9}+\dfrac{2}{9}\right)-\dfrac{7}{11}\)
\(=\dfrac{-4}{11}.1-\dfrac{7}{11}\)
\(=\dfrac{-4}{11}-\dfrac{7}{11}\)
\(=-1\)
b) \(\dfrac{3}{5}:\dfrac{-7}{10}+0,5-\left(\dfrac{-9}{14}\right)\)
\(=\dfrac{-6}{7}+\dfrac{1}{2}+\dfrac{9}{14}\)
\(=\dfrac{2}{7}\)
c) \(\dfrac{3}{5}-\dfrac{8}{5}:\left(5,25+75\%\right)\)
\(=\dfrac{3}{5}-\dfrac{8}{5}:\left(\dfrac{21}{4}+\dfrac{3}{4}\right)\)
\(=\dfrac{3}{5}-\dfrac{8}{5}:6\)
\(=\dfrac{3}{5}-\dfrac{4}{15}\)
\(=\dfrac{1}{3}\)
a) 11 : 4 + 5,3 x 3,8
= 3,75 + 5,3 x 3,8
= 3,75 + 20,14
= 23,89
b) 16,52 : 0,5 - 2,7 : 0.25
= 33,04 - 2,7 : 0,25
= 33,04 - 10,8
= 22,24
c) 7/5 : 2/3 : 1,05 - 4/9
= 7/5 : 2/3 : 21/20 - 4/9
= 7/5 x 3/2 x 20/21 - 4/9
= (1 x 3 x 2)/ (1 x 1 x 3)
= 6/3
= 2
a 2.75+20.4=22.89
b 33.04-10.8=22.24