1/7 . 1/3 + 1/7 . 1/2 - 1/7
giúp mik zới
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Đáp án của mình là:
3 ( |1 - x | - 2 ) + 1 = 7
3 ( |1 - x | - 2 ) = 7 - 1
3 ( |1 - x | - 2 ) = 6
1 - x - 2 = 6 : 3
1 - x - 2 = 2
1 - x = 2 + 2
1 - x = 4
x = 1 - 4
x = -3
nhé bạn!
__HT__
b)\(\left(2\frac{1}{3}+3\frac{1}{2}\right).0,2+25\%=\left(\frac{7}{3}+\frac{7}{2}\right).\frac{1}{5}+\frac{1}{4}=\left(\frac{14}{6}+\frac{21}{6}\right).\frac{1}{5}+\frac{1}{4}=\frac{35}{6}.\frac{1}{5}+\frac{1}{4}=\frac{7}{6}+\frac{1}{4}=\frac{14}{12}+\frac{3}{12}=\frac{17}{12}=1\frac{5}{12}\)
đây là một bãi rác , nơi câu dễ thì giúp rất nhiều , còn câu khó tuy bt nhưng ko giúp , hình như tui hỏi bài nhầm chỗ r
\(B=\left(8-2,25+\dfrac{2}{7}\right)-\left(-6-\dfrac{3}{7}+1\dfrac{1}{4}\right)-\left(3+0,5-1\dfrac{2}{7}\right)\\ B=8-\dfrac{9}{4}+\dfrac{2}{7}+6+\dfrac{3}{7}-\dfrac{5}{4}-3-\dfrac{1}{2}+\dfrac{9}{7}\\ B=\left(8+6-3\right)+\left(-\dfrac{9}{4}-\dfrac{5}{4}\right)+\left(\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{9}{7}\right)-\dfrac{1}{2}\)
\(B=11-\dfrac{7}{2}+2-\dfrac{1}{2}\\ B=\left(11+2\right)+\left(-\dfrac{7}{2}-\dfrac{1}{2}\right)\\ B=13-4\\ B=9.\)
(1+7/9).(1+7/20).(1+7/33).(1+7/48)......(1+7/180)
=16/9.27/20.40/33.55/48........187/180
=2.8/1.9 . 3.9/2.10 . 4.10/3.11 . 5.11/4.12 ........ 11.17/18.10
=(2.3.4.5.......11).(8.9.10......17)/(1.2.3.4.....18).(9.10.11.12......18)
=11.8/1.18=88/18=44/9
VT=(1/5+1/6+...+1/9)+(1/10+1/11+...+1/14)+(1/15+1/16+1/17)
VT<(1/5+...+1/5)+(1/10+...+1/10)+(1/15+1/15+1/15)=
=5/5+5/10+3/15=1+1/2+1/5<2
bn ơi đừng đùa dai nữa bn trung học cơ sở mà ko ccongj đc hơn cả cá em lớp 1
nhắc lần thứ N @congtibaocao
a) (-25)+72-80
=47-80
=-33
b) (-3) . 5 + 28 - (-15)
=-15 +28+15
=(15-15)+28
=0+28
=28
c) (-42) : 7 + (-14) - (-3) . 4
=(-6)-14-(-12)
=-20+12
=-8
d) 15 - 6 : (-3) + (-7) . (-2)
=15-(-2)+14
=17+14
=21
\(4,7\div0,25+5,3\times4\)
\(=18,8+21,2\)
\(=40\)
\(3\times\left(a-2\right)+150=240\)
\(3\times\left(a-2\right)=90\)
\(a-2=30\)
\(a=32\)
\(\dfrac{1}{9}+a+\dfrac{7}{12}=\dfrac{17}{18}\)
\(\dfrac{1}{9}+a=\dfrac{13}{36}\)
\(a=\dfrac{1}{4}\)
\(\left(\dfrac{1}{2}\times\dfrac{1}{3}+\dfrac{1}{3}\times\dfrac{1}{4}+\dfrac{1}{4}\times\dfrac{1}{5}+\dfrac{1}{5}\times\dfrac{1}{6}+\dfrac{1}{6}\times\dfrac{1}{7}+\dfrac{1}{7}\times\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)
\(\left(\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}+\dfrac{1}{6\times7}+\dfrac{1}{7\times8}\right)\times a=\dfrac{9}{16}\)
\(\left(\dfrac{1}{2}-\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)
\(\dfrac{3}{8}\times a=\dfrac{9}{16}\)
\(a=\dfrac{3}{2}\)
\(\dfrac{3}{7}\): \(\dfrac{1}{3}\) + \(\dfrac{2}{7}\) \(\times\) \(\dfrac{1}{7}\)
= \(\dfrac{3}{7}\) \(\times\) \(\dfrac{3}{1}\) + \(\dfrac{2}{49}\)
= \(\dfrac{9}{7}\) + \(\dfrac{2}{49}\)
= \(\dfrac{63}{49}\) + \(\dfrac{2}{49}\)
= \(\dfrac{65}{49}\)
1/7 . 1/3 + 1/7 . 1/2 - 1/7
=1/7(1/3+1/2-1)
=1/7 (1/3-1/2)
=1/7 (-1/6)=-1/42
\(\dfrac{1}{7}.\dfrac{1}{3}+\dfrac{1}{7}.\dfrac{1}{2}-\dfrac{1}{7}\)
\(\dfrac{1}{7}.\dfrac{1}{3}+\dfrac{1}{7}.\dfrac{1}{2}-\dfrac{1}{7}.1\)
\(\dfrac{1}{7}\left(\dfrac{1}{3}+\dfrac{1}{2}-1\right)\)
\(\dfrac{1}{7}\cdot-\dfrac{1}{6}\)
\(-\dfrac{1}{42}\)