Tìm y:
a, y - 6 : 2 - ( 48 - 24 x 2 : 6 - 3 ) = 0
b, ( 7 x 13 + 8 x 13 ) : ( \(9\frac{2}{3}\)- y ) = 39
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\(a)y-6:2-\left(48-24x2:6-3\right)=0\)\(0\)
\(y-3-\left(48-48:6-3\right)=0\)
\(y-3-\left(48-8-3\right)=0\)
\(y-3-\left(40-3\right)=0\)
\(y-3-37=0\)
\(y-\left(3+37\right)=0\)
\(y-40=0\)
\(y=0+40\)
\(y=40\)
\(b)\left(7x13+8x13\right):\left(9\frac{2}{3}-y\right)=39\)
\(\left(91+104\right):\left(\frac{29}{3}-y\right)=39\)
\(195:\left(\frac{29}{3}-y\right)=39\)
\(\frac{29}{3}-y=195:39\)
\(\frac{29}{3}-y=5\)
\(y=\frac{29}{3}-5\)
\(y=\frac{14}{3}\)
a) y - 6 chia 2 - ( 48 - 24 x 2 chia 6 - 3 ) = 0
=> y - 6 chia 2 - ( 48 - 48 chia 6 - 3 ) = 0
=> y - 6 chia 2 - ( 48 - 8 -3 ) = 0
= > y - 6 chia 2 - 37 = 0
=> y - 6 chia 2 = 0 + 37
=> y - 6 chia 2 = 37
=> y -6 = 37 chia 2
=> y - 6 = 37 / 2
=> y = 37 / 2 + 6
=> y = 49 / 2
Vậy y = 49 / 2
b) ( 7 x 13 + 8 x 13 ) chia ( 92 /3-y ) = 39
=> ( 91 + 104 ) chia ( 92/3 - y ) =39
=> 195 chia ( 92 /3 - y ) = 39
=> 92/3 - y = 7605
=> y = 7605 + 92/3
=> y = 22907 /3
Vậy y = 22907 / 3
a) y - 6 : 2 - (48 - 24 x 2 : 6 - 3) = 0
y - 3 - (48 - 48 : 6 - 3) = 0
y - 3 - (48 - 8 - 3) = 0
y - 3 - 37 = 0
y - ( 3+37) = 0
y - 40 =0
y =0+40
Y =40
b) ( 7x13 - 8x13) : ( 9 2/3 -y) =39
(7+8)x13 : (29/3 - y) =39
15 x 13 : (29/3-y) =39
195 : (29/3 - y) =39
29/3 - y =195 : 39
29/3 - y = 5
y = 29/3 - 5
y = 14/3
1: Áp dụng tính chất của DTSBN, ta được:
\(\dfrac{x}{7}=\dfrac{y}{13}=\dfrac{x-y}{7-13}=\dfrac{42}{-6}=-7\)
=>x=-48; y=-91
2: x/y=3/4
=>4x=3y
=>4x-3y=0
mà 2x+y=10
nên x=3 và y=4
3: =>7x-3y=0 và x-y=-24
=>x=18 và y=42
4: =>7x-5y=0 và x+y=24
=>x=10 và y=14
Tìm x εIN biết
a) 390 - (x-8) = 168:13
b) (x-140) : 7 = 27 - 24
c) x- 6 :2 - ( 48 - 24 ) :2 :6 - 3 = 0
d) x+5.2-(32+16.3:6-15)=0
b) \(\left(x-140\right):7=27-24\)
\(\left(x-140\right):7=3\)
\(x-140=21\)
\(x=161\)
vay \(x=161\)
c) \(x-6:2-\left(48-24\right):2:6-3=0\)
\(x-3-24:2:6-3=0\)
\(x-3-2-3=0\)
\(x-8=0\)
\(x=8\)
vay \(x=8\)
d) \(x+5.2-\left(32+16.3:6-15\right)=0\)
\(x+10-\left(32+8-15\right)=0\)
\(x+10-25=0\)
\(x-15=0\)
\(x=15\)
vay \(x=15\)
a) \(390-\left(x-8\right)=168:13\)
\(390-x+8=\frac{168}{13}\)
\(x+8=390-\frac{168}{13}\)
\(x+8=\frac{5070}{13}-\frac{168}{13}\)
\(x+8=\frac{4902}{13}\)
\(x=\frac{4902}{13}-8\)
\(x=\frac{4798}{13}\)
vay \(x=\frac{4798}{13}\)
a) \(y-6:2-\left(48-24.2:6-3\right)=0.\)
\(\Rightarrow y-3-\left(48-8-3\right)=0\)
\(\Rightarrow y-3-37=0\)
\(\Rightarrow y=0+37+3=40\)
Vậy y = 40
b) \(\left(7.13+8.13\right):\left(9\frac{2}{3}-y\right)=39\)
\(\Rightarrow195:\left(\frac{29}{3}-y\right)=39\)
\(\Rightarrow\frac{29}{3}-y=195:39=5\)
\(\Rightarrow y=\frac{29}{3}-5=\frac{14}{3}\)
Vậy y=\(\frac{14}{3}\)
a) y - 6 : 2 - ( 48 - 24 x 2 : 6 - 3 ) = 0
y - 6 : 2 - ( 48 - 48 : 6 - 3 ) = 0
y - 6 : 2 - ( 48 - 8 - 3 ) = 0
y - 6 : 2 - 37 = 0
y - 3 = 0 + 37
y - 3 = 37
y = 37 + 3
y = 40
b) ( 7 x 13 + 8 x 13 ) : ( \(9\frac{2}{3}\) - y ) = 39
( 15 x 13 ) : ( \(9\frac{2}{3}\) - y ) = 39
195 : ( \(9\frac{2}{3}\) - y ) = 39
\(9\frac{2}{3}\) - y = 195 : 39
\(9\frac{2}{3}-y=5\)
\(y=9\frac{2}{3}-5\)
\(y=\frac{14}{3}\)