a) (5/4)^2:-(35/24)^2 b)25*5^-2*5^3*5^0 giải giúp mk
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a)12+24+35-2-14-25=30
b)1-2+3-4+5-6+7-8+9=5
c)25-12-3+24+36=70
Tìm xx biết: \left(x^{4}\right)^{3}=\dfrac{x^{19}}{x^{6}}(x4)3=x6x19
Trả lời: x=x=
\(a,-\frac{9}{12}=-\frac{9:3}{12:3}=-\frac{3}{4}\)
\(\frac{-18}{-24}=\frac{\left(-18\right):\left(-6\right)}{\left(-24\right):\left(-6\right)}=\frac{3}{4}\)
\(-\frac{35}{70}=-\frac{35:35}{70:35}=\frac{1}{2}\)
\(-\frac{9}{27}=-\frac{9:9}{27:9}=-\frac{1}{3}\)
\(b,\frac{1313}{4242}=\frac{1313:101}{4242:101}=\frac{13}{42}\)
\(\frac{-353535}{-424242}=\frac{\left(-353535\right):\left(-70707\right)}{\left(-424242\right):\left(-70707\right)}=\frac{5}{6}\)
\(c,\frac{2^3\times4^3\times5^4}{8^2\times25^3\times7}=\frac{2^3\times4^3\times25^2}{8\times8^2\times25^2\times25\times7}\) ( 4^3 = 8^2 ; 5^4 = 25^2 )
\(=\frac{1}{25\times7}=\frac{1}{175}\)
\(a.\frac{-9}{-12}=\frac{-9:3}{-12:3}=\frac{-3}{-4}.\)
\(\frac{-18}{-24}=\frac{-18:6}{-24:6}=\frac{-3}{-4}\)
\(\frac{-35}{-70}=\frac{-35:35}{-70:35}=\frac{-1}{-2}\)
\(\frac{-9}{-27}=\frac{-9:9}{-27:9}=\frac{-1}{-3}\)
a) (-5) . (-5) . (-5) . (-5) . (-5) = ( -5 )5 = -3125
b) (-2) . (- 2) . (-2) .( -3) . (-3) . (-3) = ( -2)3 . ( - 3)2 = ( -8 ) . ( -9 ) = 72
94
a, (-5).(-5).(-5).(-5).(-5) = (-5)^5=-3125
b, (-2).(-2).(-2).(-3).(-3).(-3) = (-2)^3 .(-3)^3=(-8).(-27)=216
95
(-1)^3=(-1)(-1)(-1)= -(1.1.1)=-1
số nguyên : 0 ; 1
96
237.(-26)+26.137= (-237+137).26= -100.26=-2600
63.(-25)+25.(-23)= [(-63)+(-23)].25= (-86).25 = -2150
97
a, (-16).1253.(-8).(-4).(-3)= 1924608>0
b, 13.(-24).(-15).(-8).4 = -149760<0
xong rùi đó nhớ k nha
a, (-25) + 276 - (276 - 25)
= (-25) + 276 - 276 + 25
= [ (-25) + 25] - (276 - 276)
= 0 - 0
= 0
b, 24 x 46 + 24 x 53 + 24
= 24 x ( 46 + 53 + 1)
= 24 x 100
= 2400
\(a,\left(\frac{5}{4}\right)^2\div-\left(\frac{35}{24}\right)^2\)
\(=\frac{25}{16}\div\frac{-1225}{576}\)
\(=\frac{-36}{49}\)
b, Xin lỗi bn, mk k đc hiểu đề cho lắm!
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Bổ sung cho♈♐๖ۣۜShizu _ ℒɪȿᶏ⁀ᶦᵈᵒᶫ⁹⁷
\(b,\text{ }25\cdot5^{-2}\cdot5^3\cdot5^0\)
\(=5^2\cdot5^{-2}\cdot5^3\cdot1\)
\(=5^3\)