Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(Ca+2H_2O\rightarrow Ca\left(OH\right)_2+H_2\)
b) \(P_2O_5+3H_2O\rightarrow2H_3PO_4\)
c) \(2Na+2H_2O\rightarrow2NaOH+H_2\)
d) \(CaO+H_2O\rightarrow Ca\left(OH\right)_2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
chọn các chất a b c d e thích hợp và hoàn thành các phương trình hóa học sau ghi rõ điều kiện phản ứng nếu có:
sửa đề em nhé
a,A+B->C
2H2+O2-to>2H2O
b,CH4+B->C+D
CH4+2O2-to>2H2O+CO2
c,D+Ca(OH)2->CaCO3+C
CO2+Ca(OH)2->CaCO3+H2O
d,E->CaO +D
CaCO3-to>CaO+CO2
e,A+CuO -> Cu+C
H2+CuO-to>Cu+H2O
![](https://rs.olm.vn/images/avt/0.png?1311)
Fe + O2 = Fe3O4
Fe3O4 + HCl = FeCl2 + FeCl3 + H2O
FeCl2 + NaOH = Fe(OH)2 + NaCl
FeCl3 + NaOH = Fe(OH)3 + NaCl
Fe(OH)2 + O2 + H2O = Fe(OH)3
Fe(OH)3 = Fe2O3 + H2O
=> A=Fe3O4;B=FeCl2;C=FeCl3;D=Fe(OH)2;E;Fe(OH)3;G=NaCl;F=Fe2O3
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,CaO+H_2O\rightarrow Ca\left(OH\right)_2\)
\(b,2Na+2H_2O\rightarrow2NaOH+H_2\uparrow\)
\(c,Zn+2HCl\rightarrow ZnCl_2+H_2\uparrow\)
\(d,H_2+CuO\underrightarrow{t^o}Cu+H_2O\)
\(e,K_2O+H_2O\rightarrow2KOH\)
\(f,Ca+2H_2O\rightarrow Ca\left(OH\right)_2+H_2\uparrow\)
\(g,2Na+H_2SO_4\rightarrow Na_2SO_4+H_2\uparrow\)
\(h,H_2+FeO\underrightarrow{t^o}Fe+H_2O\)
\(i,P_2O_5+3H_2O\rightarrow2H_3PO_4\)
\(CaO+H_2O\rightarrow Ca\left(OH\right)_2\\ 2Na+2H_2O\rightarrow2NaOH+H_2\\ Zn+2HCl\rightarrow ZnCl_2+H_2\\ H_2+CuO\rightarrow\left(t^o\right)Cu+H_2O\\ K_2O+H_2O\rightarrow2KOH\\ Ca+2H_2O\rightarrow Ca\left(OH\right)_2+H_2\\ 2Na+H_2SO_4\rightarrow Na_2SO_4+H_2\\ H_2+FeO\rightarrow\left(t^o\right)Fe+H_2O\\ P_2O_5+3H_2O\rightarrow2H_3PO_4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(CaO+H_2O\rightarrow Ca\left(OH\right)_2\)
b, \(2Na+2H_2O\rightarrow2NaOH+H_2\)
c, \(Zn+2HCl\rightarrow ZnCl_2+H_2\)
d, \(H_2+CuO\underrightarrow{t^o}Cu+H_2O\)
e, \(K_2O+H_2O\rightarrow2KOH\)
f, \(Ca+2H_2O\rightarrow Ca\left(OH\right)_2+H_2\)
g, \(2Na+H_2SO_4\rightarrow Na_2SO_4+H_2\)
h, \(H_2+FeO\underrightarrow{t^o}Fe+H_2O\)
i, \(P_2O_5+3H_2O\rightarrow2H_3PO_4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
A: $CuSO_4 ; B : CuCl_2 ; C : Cu(OH)_2 ; D : CuO ; E : Cu(NO_3)_2$
$CuSO_4 + BaCl_2 \to BaSO_4 + CuCl_2$
$CuCl_2 + 2KOH \to Cu(OH)_2 + 2KCl$
$Cu(OH)_2 \xrightarrow{t^o} CuO + H_2O$
$CuO + H_2 \xrightarrow{t^o} Cu + H_2O$
$Cu(OH)_2 + H_2SO_4 \to CuSO_4 + 2H_2O$
$CuSO_4 + Ba(NO_3)_2 \to BaSO_4 + Cu(NO_3)_2$
$Cu(NO_3)_2 + Fe \to Fe(NO_3)_2 + Cu$
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.2Al+3CuCl_2\rightarrow2AlCl_3+3Cu\)
Tỉ lệ = \(2:3:2:3\)
\(b.2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O\)
Tỉ lệ = \(2:1:1:2\)
\(c.CaO+2HCl\rightarrow CaCl_2+H_2O\)
Tỉ lệ = \(1:2:1:1\)
\(d.Ca\left(OH\right)_2+CO_2\rightarrow CaCO_3+H_2O\)
Tỉ lệ = \(1:1:1:1\)
a.2Al+3CuCl2→2AlCl3+3Cua.2Al+3CuCl2→2AlCl3+3Cu
b.2NaOH+H2SO4→Na2SO4+2H2Ob.2NaOH+H2SO4→Na2SO4+2H2O
c.CaO+2HCl→CaCl2+H2Oc.CaO+2HCl→CaCl2+H2O
d.Ca(OH)2+CO2→CaCO3+H2Od.Ca(OH)2+CO2→CaCO3+H2O
a;
A:CaCO3 (các PTHH bạn tự làm nhé)
c;
B:CuCl2
C:Cu(OH)2
D:CuO
đồng hương nè chú Lê Quang Sáng