Question

[Nguyễn Trịnh Bảo Minh]

yx2 +yx4 +yx6 +yx8 +...+ yx100 =5100

giúp mình nha mình đang gấp
 

Answer 1

[Dang Tung]

\(=>y\times\left(2+4+6+8+...+100\right)=5100\\ =>y\times\left(100+2\right)\times50:2=5100\\ =>y\times2500=5100\\ =>y=\dfrac{5100}{2500}=2\)

Answer 2

[𝔅𝔲̀𝔦 ℌ𝔬𝔞̀𝔫𝔤 𝔗𝔥𝔦𝔢̂𝔫 𝔏𝔞𝔪]

\(y.2+y.4+y.6+y.8+...+y.100=5100\\ \Rightarrow y.\left(2+4+6+8+...+100\right)=5100\\ \Rightarrow y.\dfrac{\left(100+2\right).\left[\left(100-2\right):2+1\right]}{2}=5100\\ \Rightarrow y.\dfrac{102.50}{2}=5100\\ \Rightarrow y.2550=5100\\ \Rightarrow y=5100:2550\\ \Rightarrow y=2\)