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\(\left|x\right|=\left|-5\right|-\left|-10\right|+15\)
\(\Rightarrow\left|x\right|=5-10+15\)
\(\Rightarrow\left|x\right|=10\)
\(\Rightarrow x=\pm10\)
\(\left|x\right|=-(-12)+(-15)+8\)
\(\Rightarrow\left|x\right|=+12+(-15)+8\)
\(\Rightarrow\left|x\right|=12+(-15)+8\)
\(\Rightarrow\left|x\right|=(-3)+8\)
\(\Rightarrow\left|x\right|=5\)
\(\Rightarrow x=\pm5\)
Bài dưới tương tự
|x|=|−5|−|−10|+15
⇒|x|=5−10+15
⇒|x|=10
⇒x=±10
|x|=−(−12)+(−15)+8
⇒|x|=+12+(−15)+8
⇒|x|=12+(−15)+8
⇒|x|=(−3)+8
⇒|x|=5
⇒x=±5
15 × (4 - 7) - 15 × (5 - 3)
= 15 × (-3) - 15 × 2
= 15 × (-3 - 2)
= -15 × 5
= -75
--------
73 × (8 - 59) - 59 × (8 - 73)
= 73 × 8 - 73 × 59 - 59 × 8 + 59 × 73
= 8 × (73 - 59) + 73 × (59 - 59)
= 8 × 14 + 73 × 0
= 8 × 14
= 112
15 x (4-7) - 15 x (5-3)
= 15 x (-3) - 15 x (-2)
= 15 x (-3 - (-2))
= 15 x (-1)
= -15
73 x (8-59) - 59 x (8-73)
= 73 x 8 - 59 x 73 - 59 x (-65)
= 73 x 8 - 59 x (73 - (-65))
= 73 x 8 - 59 x 8
= 8 x (73-59)
= 8 x 14
= 112
a/ x - ( 25 - x) = x - 15
=> x - 25 + x = x - 15
=> 2x - x = -15 + 25
=> x = 10
b/ x - 8 = -13 - 8
=> x = -13 - 8 + 8 = -13
c/ x - (-15) = 5 - (-19)
=> x + 15 = 5 + 19 => x = 5 + 19 - 15 = 9
d/ (x + 35) = 2x + 15 + (13 - 4)
=> x + 35 = 2x + 15 + 13 - 4
=> x - 2x = 15 + 13 - 4 - 35
=> -x = -11 => x = 11
e/ 5 - 2x = 15-(-9) - 3x
=> 5 - 2x = 15 + 9 - 3x
=> -2x + 3x = 15 + 9 - 5
=> x = 19
g/ x + 135 = 3x - 15
=> x - 3x = -15 - 135
=> -2x = -150
=> x = -150/ - 2 = 75
a) Ta có: \(\dfrac{-11}{15}< \dfrac{x}{15}< \dfrac{-8}{15}\)
nên -11<x<-8
hay \(x\in\left\{-10;-9\right\}\)
b) Ta có: \(\dfrac{3}{7}< \dfrac{x}{21}< \dfrac{2}{3}\)
\(\Leftrightarrow\dfrac{9}{21}< \dfrac{x}{21}< \dfrac{14}{21}\)
Suy ra: 9<x<14
hay \(x\in\left\{10;11;12;13\right\}\)
c) Ta có: \(\dfrac{-67}{21}< \dfrac{x}{168}< \dfrac{-3}{8}\)
nên \(\dfrac{-536}{168}< \dfrac{x}{168}< \dfrac{-63}{168}\)
Suy ra: -536<x<-63
hay \(x\in\left\{-535;-534;...;-64\right\}\)
\(\dfrac{-15}{8}\) x \(\left(\dfrac{8}{15}+\dfrac{32}{27}\right)\)
= \(\dfrac{-15}{8}\) x \(\dfrac{232}{135}\)
= \(\dfrac{-29}{9}\)
a) 51 × (-15) + (-15) × 49
= -15 × (51 + 49)
= -15 × 100
= -1500
b) 4 × (5 - 8) + 8 × 4
= 4 . 5 - 4 × 8 + 8 × 4
= 20 - 32 + 32
= 20 + 0
= 20
c) 43 + (-7) - 43 + (-93)
= (43 - 43) - (7 + 93)
= 0 - 100
= -100
d) (44 + 8) - (-2 + 44)
= 44 + 8 + 2 - 44
= (44 - 44) + (8 + 2)
= 0 + 10
= 10
`@` `\text {Ans}`
`\downarrow`
`x^3 = 125`
`=> x^3 = 5^3`
`=> x = 5`
Vậy, `x = 5`
_____
`4^5 \div 4^3`
`=`\(4^{5-3}\)
`= 4^2`
______
\(8^{12}\cdot8^3\div8^{15}\)
`=`\(8^{12+3-15}\)
`=`\(8^0=1\)
______
\(7^{15}\div7^{13}\)
`=`\(7^{15-13}\)
`=`\(7^2\)
_______
\(17^{15}\cdot17^{10}\div17^{22}\)
`=`\(17^{15+10-22}\)
`= 17^3`
_______
\(5^{10}\cdot25\div5^{11}\)
`=`\(5^{10}\cdot5^2\div5^{11}\)
`=`\(5^{10+2-11}\)
`= 5`
_______
\(15^{10}\cdot225\div15^{11}\)
`=`\(15^{10}\cdot15^2\div15^{11}\)
`=`\(15^{12}\div15^{11}\)
`= 15`
`@` `\text {Kaizuu lv uuu}`
\(x^3=125\)
\(\Rightarrow x^3=5^3\)
\(\Rightarrow x=3\)
___________________
\(4^5:4^3\)
\(=4^{5-3}\)
\(=4^2=16\)
___________________
\(8^{12}.8^3:8^{15}\)
\(=8^{15}:8^{15}\)
\(=1\)
___________________
\(7^{15}:7^{13}\)
\(=7^{15-13}\)
\(=7^2=49\)
___________________
\(17^{15}.17^{10}:17^{22}\)
\(=17^{25}:17^{22}\)
\(=17^3=4913\)
___________________
\(5^{10}.25:5^{11}\)
\(=5^{10}.5^2:5^{11}\)
\(=5^{12}:5^{11}\)
\(=5^1=5\)
___________________
\(15^{10}.225:15^{11}\)
\(=15^{10}.15^2:15^{11}\)
\(=15^{12}:15^{11}\)
\(=15^1=15\)
__________________
* an . am = an+m
an : am = an-m
Chúc bạn học tốt
\(-x+8=-15\)
\(\Leftrightarrow-x=-15-8\)
\(\Leftrightarrow-x=-23\)
\(\Leftrightarrow x=23\)
Vậy \(x=23\)
~ học tốt !~
suy ra -x=-15-8
suy ra -x=-23
suy ra x=23