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a) \(2\dfrac{3}{4}-x=\dfrac{3}{4}\)
\(\Rightarrow\dfrac{11}{4}-x=\dfrac{3}{4}\)
\(\Rightarrow x=\dfrac{11}{4}-\dfrac{3}{4}=\dfrac{8}{4}=2\)
b) \(x:\dfrac{5}{6}=-\dfrac{3}{5}\)
\(\Rightarrow x=-\dfrac{3}{5}.\dfrac{5}{6}=-\dfrac{15}{30}=-\dfrac{1}{2}\)
c) \(1\dfrac{1}{3}+\dfrac{2}{3}:x=1\)
\(\Rightarrow\dfrac{2}{3}:x=1-1\dfrac{1}{3}\)
\(\Rightarrow\dfrac{2}{3}:x=-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{3}:-\dfrac{1}{3}\)
\(\Rightarrow x=-2\)
d) \(x-\dfrac{1}{9}=\dfrac{8}{3}\)
\(\Rightarrow x=\dfrac{8}{3}+\dfrac{1}{9}\)
\(\Rightarrow x=\dfrac{25}{9}\)
e) \(\dfrac{1}{2}x+650\%x-x=-6\)
\(\Rightarrow\dfrac{1}{2}x+\dfrac{13}{2}x-x=-6\)
\(\Rightarrow x\left(\dfrac{1}{2}+\dfrac{13}{2}-1\right)-6\)
\(\Rightarrow6x=-6\)
\(\Rightarrow x=\dfrac{-6}{6}=-1\)
g) \(2\left(x-\dfrac{1}{2}\right)+3\left(-1+\dfrac{x}{3}\right)=x\left(\dfrac{2}{x}-1\right)\) \(\text{Đ}K:x\ne0\)
\(\Rightarrow2x-1-3+x=2-x\)
\(\Rightarrow3x-4=2-x\)
\(\Rightarrow3x+x=2+4\)
\(\Rightarrow4x=6\)
\(\Rightarrow x=\dfrac{6}{4}=\dfrac{3}{2}\)
a: \(\Leftrightarrow3x-9+13⋮x-3\)
\(\Leftrightarrow x-3\in\left\{1;-1;13;-13\right\}\)
hay \(x\in\left\{4;2;16;-10\right\}\)
b: \(\Leftrightarrow x\left(x+3\right)-13⋮x+3\)
\(\Leftrightarrow x+3\in\left\{1;-1;13;-13\right\}\)
hay \(x\in\left\{-2;-4;10;-16\right\}\)
c: \(\Leftrightarrow x^2-1+4⋮x-1\)
\(\Leftrightarrow x-1\in\left\{1;-1;2;-2;4;-4\right\}\)
hay \(x\in\left\{2;0;3;-1;5;-3\right\}\)
\(PT\Leftrightarrow\left(x-2\right).\left(x+7\right)=\left(x+9\right).\left(x-1\right)\)
\(\Leftrightarrow x^2+5x-14=x^2+8x-9\)
\(\Leftrightarrow-3x=5\)
\(\Leftrightarrow x=\frac{-5}{3}\left(TMĐK\right)\)
\(\frac{x-2}{x-1}=\frac{x+9}{x+7}\)
=> \(\frac{\left(x-1\right)-1}{x-1}=\frac{\left(x+7\right)+2}{x+7}\)
=> \(1-\frac{1}{x-1}=1+\frac{2}{x+7}\)
=> \(-\frac{1}{x-1}=\frac{2}{x+7}\)
=> \(-1.\left(x+7\right)=2\left(x-1\right)\)
=> \(-x-7=2x-2\)
=> \(-x-2x=-2+7\)
=> \(-3x=5\)
=> \(x=5:\left(-3\right)=-\frac{5}{3}\)
(x - 9) 2= x + 1(1)
Vì (x - 9)2\(\ge\)0 => x + 1\(\ge\)0
=> (1) <=> \(\orbr{\begin{cases}x-9=\sqrt{x+1}\\x-9=-\sqrt{x+1}\end{cases}}\)
Lớp 6 đã học căn r hả bạn
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