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254 x399 - 145 / 254 + 399 x 255
= ( 253 + 1 ) x 399 - 145 / 254 + 399 x 255
= 253 x 399 + ( 399 - 145 )/ 254 + 399 x 255
= 254 x 399 + 255 / 254 + 399 x 155
= 1
A = \(\dfrac{254\times399-145}{254+399\times253}\)
A = \(\dfrac{\left(253+1\right)\times399-145}{254+399\times253}\)
A = \(\dfrac{253\times399+399-145}{254+399\times253}\)
A = \(\dfrac{253\times399+254}{254+399\times253}\)
A = 1
a) \(254x399-145=\left(250+4\right)\left(400-1\right)-145\)
\(=100000+1600-250-145-4=101600-\left(250+145+4\right)\)
\(=101600-399=101201\)
b) \(254+399x253=254+\left(400-1\right)x\left(250+3\right)\)
\(=254+100000+1200-250-3\)
\(=101454-250-3=101201\)
254 × 399 - 145 / 254 + 399 × 253
= (253 + 1) × 399 - 145 / 254 + 399 × 253
= 253 × 399 + (399 - 145) / 254 + 399 × 253
= 253 × 399 + 254 / 254 + 399 × 253
= 1
\(\frac{254x399-145}{254+399x253}\)
\(=\frac{253x399+399-145}{254+399x253}\)
\(=\frac{253x399+254}{254+399x253}=1\)
\(\frac{254.399-145}{254+399.253}\)
\(=\frac{253.399+399-145}{254+399.253}\)
\(=\frac{253.399+254}{254+399.253}=1\)
a) \(\frac{254.399-145}{254+399.253}\)
\(=\frac{253.399+399-145}{254+399.253}\)
\(=\frac{253.399+254}{254+399.253}\)
\(=1\)
b) tự làm
Câu a sai đề (sửa đề lại rồi làm tương tự câu b
Câu b
\(\frac{5932+6001\times5931}{5932\times6001-69}=\frac{5932+6001\times5931}{\left(5931+1\right)\times6001-69}=\frac{5932+6001\times5931}{5931\times6001+6001-69}=\frac{5932+6001\times5931}{5932\times6001+5932}=1\)
\(254.399-\frac{145}{254+399.255}=101346-\frac{145}{101999}=1012031170\)
\(5932+6001.\frac{5931}{35597863}=1\)
\(\frac{254.399-145}{254+399.253}=\frac{\left(253+1\right).399-145}{254+399.253}=\frac{253.399+\left(399-145\right)}{254+399.253}\)
\(=\frac{253.399+254}{254+399.253}=1\)
\(\frac{254\times399-145}{254+399\times253}\)
\(=\frac{253\times399+399-145}{254+399\times253}\)
\(=\frac{253\times399+254}{254+399\times253}\)
\(=1\)
399 + 254 x 399 - 399 x 255 : 399 x 254 + 399 x 255
1 x 399 + 254 x 399 - 399 x 255 : 399 x 254 + 399 x 255
( 1 + 254 - 255 ) x 399 : 399 x ( 254 + 255 )
0 x 399 x A
0
\(\frac{254\times399-145}{254+399\times253}=\frac{'253+1'\times399-145}{254+399\times253}\)
\(=\frac{235\times399-145}{254+399\times253}\)
\(=\frac{253\times399+254}{254+399\times253}\)
\(=1\)
Vậy: Số cần tìm là :1
\(\frac{254x399-145}{254+399x\left(254+1\right)}\)
\(=\frac{254x399-145}{254+399x254+399}\)
\(=\frac{-145}{254+399}\)
\(=\frac{-145}{653}\)