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M=7x-7y+4ax-4ay-5
=7(x-y)+4a(x-y)-5
=(7.0)+(4a.0)-5
=0+0-5
=-5
Vậy giá trị biểu thức M=7x-7y+4ax-4ay-5 bằng -5
Ta có \(M=7\left(x-y\right)+4a\left(x-y\right)-5=7.0+4a.0-5=-5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a.\(x=0;y=-1\)
\(\Rightarrow2.0-\dfrac{-1\left(0^2-2\right)}{0.-1-1}=0-\dfrac{2}{-1}=2\)
b.\(x=2\)
\(\Rightarrow4.2^2-3\left|2\right|-2=16-6-2=8\)
\(x=-3\)
\(\Rightarrow4.\left(-3\right)^2-3\left|-3\right|-2=36-9-2=25\)
c.\(x=-\dfrac{1}{5};y=-\dfrac{3}{7}\)
\(\Rightarrow5.\left(-\dfrac{1}{5}\right)^2-7.\left(-\dfrac{3}{7}\right)+6=5.\dfrac{1}{25}+3+6=\dfrac{1}{5}+3+6=\dfrac{46}{5}\)
thay x=2 và biểu thức A ta đc
\(A=4.2^2-3.\left|2\right|-2=4.4-6-2=16-6-2=8\)
thay x=-3 biểu thức A ta đc
\(A=4.\left(-3\right)^2-3.\left|-3\right|-2=4.9-9-2=36-9-2=25\)
thay x=-1/5 ; y=-3/7 biểu thức B ta đc
\(B=5.\left(-\dfrac{1}{5}\right)^2-7.\left(-\dfrac{3}{7}\right)+6\)
\(B=5\cdot\dfrac{1}{25}+3+6\)
\(B=\dfrac{1}{5}+3+6=\dfrac{46}{5}\)
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7x-7y+4ax-4ay-5
=7(x-y)-4a(x-y)-5
mà x-y=0
=7.0-4a.0-5
=0-0-5
=-5
\(F=4x-6y+7=2\left(2x-3y\right)+7=2\cdot7+7=21\)
\(a-b=-7\)
=>a=b-7
\(E=\dfrac{3a-2b}{2a+7b}=\dfrac{3\left(b-7\right)-2b}{2\left(b-7\right)+7b}\)
\(=\dfrac{3b-21-2b}{2b-14+7b}=\dfrac{b-21}{9b-14}\)
\(K=7x-7y+4ax-4ay-5\)
\(=7\left(x-y\right)+4a\left(x-y\right)-5\)
\(=7\cdot0+4a\cdot0-5=-5\)