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A = (1 - 2/3 + 4/3) - (4/5 - 1) + (7/5 + 2)
A= (3/3 - 2/3 + 4/3) - (4/5 - 5/5) + (7/5 + 10/5)
A= 5/3 + 1/5 + 17/5
A= 5/3 +18/5
A= 25/15 + 54/15
A= 79/15
B= (-3 + 3/4 - 1/3 ) : (5 + 2/5 - 2/3)
B= (-36/12 + 9/12 - 4/12) : (75/15 + 6/15 - 10/15)
B= -31/12 : 71/15
B= -155/284
C= (3/5 - 4/5 ) . (2/7 - 3/14) - (5/9 - 7/27) . (1 - 3/5) + (1 - 11/12) . (1-11/12)
C= -1/5 . 1/14 - 8/27 . 2/5 + 1/12 . 1/12
C=-1/70 - 16/135 + 1/144
C=-216/15120 - 1792/15120 + 105/15120
C=-1903/15120
\(A=\left(12^2+14^2+16^2+18^2+20^2\right)-\left(1^2+3^2+5^2+7^2+9^2\right)\)
\(A=\left(12^2-1^2\right)+\left(14^2-3^2\right)+\left(16^2-5^2\right)+\left(18^2-7^2\right)+\left(20^2-9^2\right)\)\(A=\left(12+1\right)\left(12-1\right)+\left(14+3\right)\left(14-3\right)+\left(16-5\right)\left(16+5\right)+\left(18-7\right)\left(18+7\right)+\left(20-9\right)\left(20+9\right)\)
\(A=11.13+11.17+11.21+11.25+11.29\)
\(A=11.\left(13+17+21+25+29\right)\)
\(A=11.\left[\left(13+17\right)+\left(21+29\right)+25\right]\)
\(A=11.\left(30+50+25\right)\)
\(A=11.105=1155\)
\(F=\left(\dfrac{A}{B}\right)^2\)
\(A=\left(\dfrac{7}{2^9}-\dfrac{14}{2^{11}}+\dfrac{21}{768}\right)=\left(\dfrac{7}{2^9}-\dfrac{14}{2^{11}}+\dfrac{7}{256}\right)=\left(\dfrac{7}{2^9}-\dfrac{7}{2^{10}}+\dfrac{7}{2^8}\right)=7.\left(\dfrac{1}{2^9}-\dfrac{1}{2^{10}}+\dfrac{1}{2^8}\right)\)
\(B=\left(\dfrac{5}{2^9}-\dfrac{20}{2^{12}}+\dfrac{25}{1280}\right)=\left(\dfrac{5}{2^9}-\dfrac{4.5}{2^{12}}+\dfrac{5}{256}\right)=\left(\dfrac{5}{2^9}-\dfrac{5}{2^{10}}+\dfrac{5}{2^8}\right)=5.\left(\dfrac{1}{2^9}-\dfrac{1}{2^{10}}+\dfrac{1}{2^8}\right)\)\(F=\left(\dfrac{A}{B}\right)^2=\left(\dfrac{7}{5}\right)^2\)
\(A=\left(12^2+14^2+...+20^2\right)-\left(1^2+3^2+5^2+7^2+9^2\right)\)
\(A=12^2+14^2+...+20^2-1^2+3^2+5^2+7^2+9^2\)
\(A=2^2.\left(6^2+7^2+8^2+9^2\right)-\left(1^2+3^2+5^2+7^2+9^2\right)\)
\(A=2^2.330-\left(1+9+25+49+81\right)\)
\(A=1320-165\)
\(A=1155\)
Vậy : \(A=1155\)