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a) \(x\cdot\frac{1}{2}+x\cdot\frac{1}{4}+x\cdot\frac{1}{8}=\frac{21}{24}\)
\(x\cdot\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\right)=\frac{7}{8}\)
\(x\cdot\frac{7}{8}=\frac{7}{8}\)
\(\Rightarrow x=\frac{7}{8}\div\frac{7}{8}=1\)
b) \(\left(x+4\right)+\left(x+9\right)+\left(x+14\right)+.....+\left(x+44\right)+\left(x+49\right)=1430\)
\(\left(x+x+x+....+x+x\right)+\left(4+9+14+...+44+49\right)=1430\)
\(10x+265=1430\)
\(10x=1430-265\)
\(10x=1165\)
\(\Rightarrow x=\frac{1165}{10}=116,5\)
c) \(x\cdot0,25-0,5=1\)
\(x\cdot0,25=1+0,5\)
\(x\cdot0,25=1,5\)
\(\Rightarrow x=1,5\div0,25=6\)
`@` `\text {Ans}`
`\downarrow`
`2023 \times 14 + 2023 \times 83+97`
`= 2023 \times (14+83) + 97`
`= 2023 \times 97 + 97`
`= 196231 +97`
`= 196328`
`78 \times 31+78 \times 24+78 \times 17+78 \times 22 \times 72`
`= 78 \times (31+24+17+22 \times 72)`
`= 78 \times (31+24+17+1584)`
`= 78 \times 1656`
`= 129168`
`371 \times 69+371 \times 14+629 \times 83`
`= 371 \times (69+14) + 629 \times 83`
`= 371 \times 83 + 629 \times 83`
`= 83 \times (371+629)`
`= 83 \times 1000`
`= 83000`
`91 \times 51+49 \times 163-49 \times 72`
`= 91 \times 51 + 49 \times (163-72)`
`= 91 \times 51+49 \times 91`
`= 91 \times (51+49)`
`= 91 \times 100`
`= 9100`
`3 \times 12 \times 17 + 4 \times 9 \times 81 + 2 \times 6 \times 6`
`= 9 \times 4 \times 17 + 4 \times 9 \times 81 + 4 \times 9 \times 2`
`= 9 \times 4 \times (17+81+2)`
`= 36 \times 100`
`= 3600`
`42 \times 17 + 58 \times 83 \times 42 \times 83 + 42 \times 83 + 17`
`= 17 \times (42+58) + 42 \times 83 \times (58 \times 83 +1)`
`= 17 \times 100 + 3486 \times 4815`
`= 1700 + 16785090`
`= 16786790`
Bài 1:
a) 43+45+47+...+565 [có (565-43)/2+1= 262 số hạng)
= [(565+43)*262]/2
= 79648
b) 21+24+27+...+318 [có (318-21)/3+1= 100 số hạng]
= [(318+21)*100]/2
= 16950
a) \(x:\frac{2}{3}=150\)
\(x=150.\frac{2}{3}\)
\(x=100\)
b) \(\frac{35}{9}:x=\frac{35}{6}\)
\(x=\frac{35}{9}.\frac{6}{35}=\frac{2}{3}\)
c,d tương tự
a ) x : 2/3 = 150 c ) x : 4/7 = 180
x = 150 x 2/3 x = 180 x 4/7
x = 100 x = 720/7
b ) 35/9 : x = 35/6 d ) 49/8 : x = 49/5
x = 35/9 : 35/6 x = 49/8 : 49/5
x = 2/3 x = 5/8
Bài 1:
a; (\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\)) x \(\dfrac{3}{4}\) = \(\dfrac{1}{4}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) : \(\dfrac{3}{4}\)
\(\dfrac{1}{4}\)\(x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{4}\) x \(\dfrac{4}{3}\)
\(\dfrac{1}{4}x\) - \(\dfrac{1}{8}\) = \(\dfrac{1}{3}\)
\(\dfrac{1}{4}x\) = \(\dfrac{1}{3}\) + \(\dfrac{1}{8}\)
\(\dfrac{1}{4}\) \(x\)= \(\dfrac{8}{24}\) + \(\dfrac{11}{24}\)
\(\dfrac{1}{4}x=\dfrac{11}{24}\)
\(x=\dfrac{11}{24}:\dfrac{1}{4}\)
\(x=\dfrac{11}{24}\times4\)
\(x=\dfrac{11}{6}\)
b; \(\dfrac{12}{5}:x\) = \(\dfrac{14}{3}\) x \(\dfrac{4}{7}\)
\(\dfrac{12}{5}\) : \(x\) = \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) : \(\dfrac{8}{3}\)
\(x\) = \(\dfrac{12}{5}\) x \(\dfrac{3}{8}\)
\(x\) = \(\dfrac{9}{10}\)
\(\frac{\left(15+x\right)}{37}=\frac{54}{14}\)
\(\Rightarrow\) \(\left(15+x\right)×14=37×54\)
\(\left(15+x\right)×14=1998\)
\(15+x=1998\div14\)
\(15+x=\frac{999}{7}\)
\(x=\frac{999}{7}-15\)
\(x=\frac{999}{7}-\frac{105}{7}\)
\(x=\frac{894}{7}\)
Vậy...
_ x + 14 chia hết cho 7
=> x = 0
_ x - 16 chia hết cho 8
=> x = 24
_ 54 + x chia hết cho 9
=> x = 0
Khoang cach cua day so tren la 5
So cac so hang la:
[54-4]:5+1=11[so]
Tong day so tu 4 den 54 la
[54+4]x11:2=319
=>x x 11+319=1430
x x 11 =1430-319
x x 11 =1111
x =1111:11
x =101
x + (4 + 9 + 14 + ... + 49 + 54 ) = 1430
Số các số hạng của các dãy số trong ngoặc là:
(54 - 4 ) : 5 + 1 = 11 (số)
Tổng của dãy số đó là:
( 54 + 4 ) x 11 : 2 = 319
Ta có biểu thức:
x + 319 = 1430
x = 1430 - 319
x = 1111