Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a, 2\(xy\) - 2\(x\) + 3\(y\) = -9
(2\(xy\) - 2\(x\)) + 3\(y\) - 3 = -12
2\(x\)(\(y-1\)) + 3(\(y-1\)) = -12
(\(y-1\))(2\(x\) + 3) = -12
Ư(12) = {-12; -6; -4; -3; -2; -1; 1; 2; 3; 4; 6; 12}
Lập bảng ta có:
| \(y\)-1 | -12 | -6 | -4 | -3 | -2 | -1 | 1 | 2 | 3 | 4 | 6 | 12 |
| \(y\) | -11 | -5 | -3 | -2 | -1 | 0 | 2 | 3 | 4 | 5 | 7 | 13 |
| 2\(x\)+3 | 1 | 2 | 3 | 4 | 6 | 12 | -12 | -6 | -4 | -3 | -2 | -1 |
| \(x\) | -1 | -\(\dfrac{1}{2}\) | 0 | \(\dfrac{1}{2}\) | \(\dfrac{3}{2}\) | \(\dfrac{9}{2}\) | \(-\dfrac{15}{2}\) | \(-\dfrac{9}{2}\) | -\(\dfrac{7}{2}\) | -3 | \(-\dfrac{5}{2}\) | -2 |
Theo bảng trên ta có: Các cặp \(x\);\(y\) nguyên thỏa mãn đề bài là:
(\(x;y\)) = (-1; -11); (0; -3); (-3; 5); ( -2; 13)
b, (\(x+1\))2(\(y\) - 3) = -4
Ư(4) = {-4; -2; -1; 1; 2; 4}
Lập bảng ta có:
| \(\left(x+1\right)^2\) | - 4(loại) | -2(loại) | -1(loại) | 1 | 2 | 4 |
| \(x\) | 0 | \(\pm\)\(\sqrt{2}\)(loại) | 1; -3 | |||
| \(y-3\) | 1 | 2 | 4 | -4 | -2 | -1 |
| \(y\) | -1 | 2 |
Theo bảng trên ta có: các cặp \(x;y\) nguyên thỏa mãn đề bài là:
(\(x;y\)) = (0; -1); (-3; 2); (1; 2)
Tính P = 11+2+11+2+3+11+2+3+4+...+11+2+3+4+...+2021
Chúc bạn học tốt nhé
P=1+1/3+1/6+1/10+…..+1/2021×2022÷2
P/2=1/2+1/6+1/12+1/20+…..+1/2021×2022
P/2=1/1×2+1/2×3+1/3×4+…….+1/2021×2022
P/2=1-1/2+1/2-1/3+1/3-1/4+….+1/2021-1/2022=1-1/2022=2021/2022
P=2021/1011
Chúc bn học tốt
1. \(\frac{x-3}{x+2}=\frac{3}{4}\)
=> \(4(x-3)=3(x+2)\)
=> 4x - 12 = 3x + 6
=> 4x - 12 - 3x = 6
=> 4x - 3x - 12 = 6
=> x = 18
2. \(\frac{4-x}{x-1}=\frac{-5}{6}\)
=> 6[4 - x] = -5[x - 1]
=> 24 - 6x = 5 - 5x
=> 24 - 6x - 5 = 5x
=> 24 - 5 = 6x - 5x
=> 19 = x
=> x = 19
3. \(\frac{3-x}{-x+2}=\frac{-1}{3}\)
=> 3[3 - x] = -1[-x + 2]
=> 9 - 3x = x - 2
=> 9 - 3x + x = -2
=> 9 - 4x = -2
=> 4x = 9 - [ -2]
=> 4x = 9 + 2 = 11
=> x = 11/4
4. \(\frac{x-1}{12}=\frac{-3}{1-x}\)
=> [x-1][1-x] = -36
=> -[x-1]2 = -36
=> [x-1]2 = 36
=> [x-1]2 = 62
=> x -1 = 6 hoặc x - 1 = -6
=> x = 7 hoặc x = -5
5 . |x - 3 | - 8 = -4
=> |x - 3| = -4 + 8
=> |x - 3| = 4
=> x - 3 = 4 hoặc x - 3 = -4
=> x = 7 hoặc x = -1
Mấy bài sau tương tự
a) \(\dfrac{1}{2}-\left(x+\dfrac{1}{3}\right)=\dfrac{5}{6}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{1}{2}-\dfrac{5}{6}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{-1}{3}\)
\(\Rightarrow x=\dfrac{-1}{3}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{-2}{3}\)
b)\(\dfrac{3}{4}-\left(x+\dfrac{1}{2}\right)=\dfrac{4}{5}\)
\(\Rightarrow x+\dfrac{1}{2}=\dfrac{3}{4}-\dfrac{4}{5}\)
\(\Rightarrow x+\dfrac{1}{2}=\dfrac{-1}{20}\)
\(\Rightarrow x=\dfrac{-1}{20}-\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{-11}{20}\)
c) \(\dfrac{3}{35}-\left(\dfrac{3}{5}+x\right)=\dfrac{2}{7}\)
\(\Rightarrow\dfrac{3}{5}+x=\dfrac{3}{35}-\dfrac{2}{7}\)
\(\Rightarrow\dfrac{3}{5}+x=\dfrac{-1}{5}\)
\(\Rightarrow x=\dfrac{-1}{5}-\dfrac{3}{5}\)
\(\Rightarrow x=\dfrac{-4}{5}\)
d)\(\dfrac{2}{3}.x=\dfrac{4}{27}\)
\(\Rightarrow x=\dfrac{4}{27}:\dfrac{2}{3}\)
\(\Rightarrow x=\dfrac{2}{9}\)
e) \(\dfrac{-3}{5}.x=\dfrac{21}{10}\)
\(\Rightarrow x=\dfrac{21}{10}:\dfrac{-3}{5}\)
\(\Rightarrow x=\dfrac{-7}{2}\)
\(A=\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2021}\right)\)
\(A=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.....\frac{2020}{2021}\)
\(A=\frac{1}{2021}\)
`a)25/(x+1)-1 1/6=-1/3-0,5`
`=>25/(x+1)=-1/3-1/2+1+1/6`
`=>25/(x+1)=1/3`
`=>75=x+1`
`=>x=74`
Vậy `x=74`
`b)(2x+25 3/5)^2-9/25=0`
`=>(2x+128/5)=9/25`
`**2x+128/5=3/5`
`=>2x=-125/5=-25`
`=>x=-25/2`
`**2x+128/5=-3/5`
`=>2x=-131/5`
`=>x=-131/10`
a ) 13/20
B)
C..........................................................
minh dang tính
\(2.\left(2x-\frac{4}{3}\right)^2+\frac{1}{4}=\frac{1}{2}\)
\(\Rightarrow\left(2x-\frac{4}{3}\right)^2=\frac{1}{2}-\frac{1}{4}\)
\(\Rightarrow\left(2x-\frac{4}{3}\right)^2=\frac{1}{4}\)
\(\Rightarrow\left(2x-\frac{4}{3}\right)=\sqrt{\frac{1}{4}}\)
\(\Rightarrow\left(2x-\frac{4}{3}\right)=\frac{1}{2}\)
\(\Rightarrow2x=\frac{1}{2}+\frac{4}{3}\)
\(\Rightarrow2x=\frac{11}{6}\)
\(\Rightarrow x=\frac{11}{6}\div2\)
\(\Rightarrow x=\frac{11}{6}\times\frac{1}{2}\)
\(\Rightarrow x=\frac{11}{12}\)