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a; \(\dfrac{3}{5}\) - \(\dfrac{-7}{10}\) - \(\dfrac{13}{-20}\)
= \(\dfrac{12}{20}\) + \(\dfrac{14}{20}\) + \(\dfrac{13}{20}\)
= \(\dfrac{39}{20}\)
b; \(\dfrac{1}{2}\) + \(\dfrac{1}{-3}\) + \(\dfrac{1}{4}\) - \(\dfrac{-1}{6}\)
= \(\dfrac{6}{12}\) - \(\dfrac{4}{12}\) + \(\dfrac{3}{12}\) + \(\dfrac{2}{12}\)
= \(\dfrac{7}{12}\)
\(\frac{3}{4}\times x+\frac{5}{3}\times x=\frac{7}{12}\)
\(\left(\frac{3}{4}+\frac{5}{3}\right)\times x=\frac{7}{12}\)
\(\frac{29}{12}\times x=\frac{7}{12}\)
\(x=\frac{7}{12}\div\frac{29}{12}\)
\(x=\frac{7}{29}\)
\(\frac{7}{13}.\frac{5}{9}+\frac{7}{19}.\frac{8}{13}-3.\frac{7}{19}=\)\(\frac{-1288}{2223}\)
Ta có
a/ 1/3x - 3/4x = 5/12 1/4x + 3/4 +x =7/8
x(1/3-3/4)=5/12 2x=7/8
-5/12x=5/12 x=7/8 : 2 =7/16
x=5/12 : -5/12
x=-1
a) \(\frac{2}{3}x-\frac{1}{2}x=\frac{5}{12}\)
\(x\left(\frac{2}{3}-\frac{1}{2}\right)=\frac{5}{12}\)
\(x\left(\frac{4}{6}-\frac{3}{6}\right)=\frac{5}{12}\)
\(\frac{1}{6}x=\frac{5}{12}\)
\(x=\frac{5}{12}:\frac{1}{6}=\frac{5}{2}\)
b) \(25\%x+\frac{3}{4}x+x=\frac{7}{8}\)
\(x\left(25\%+\frac{3}{4}+1\right)=\frac{7}{8}\)
\(x\left(\frac{1}{4}+\frac{3}{4}+1\right)=\frac{7}{8}\)
\(x\left(1+1\right)=\frac{7}{8}\)
\(2x=\frac{7}{8}\)
\(x=\frac{7}{8}:2=\frac{7}{16}\)
a; 0,2.\(\dfrac{15}{36}\) - (\(\dfrac{2}{5}\) + \(\dfrac{2}{3}\)): 1%
= \(\dfrac{1}{12}\) - \(\dfrac{16}{15}\): \(\dfrac{1}{100}\)
= \(\dfrac{1}{12}\) - \(\dfrac{320}{3}\)
= \(\dfrac{1}{12}\) - \(\dfrac{1280}{12}\)
= - \(\dfrac{1279}{12}\)
b; 75% - 1\(\dfrac{1}{2}\) + 0,5 : \(\dfrac{5}{12}\)
= 0,75 - 1,5 + 1,2
= -0,75 + 1,2
= 0,45
c; 1\(\dfrac{3}{15}.0,75-\left(\dfrac{8}{15}+0,25\right)\).\(\dfrac{24}{47}\)
= \(\dfrac{28}{15}\).0,75 - \(\dfrac{47}{60}\).\(\dfrac{24}{47}\)
= \(\dfrac{7}{5}-\dfrac{2}{5}\)
= 1
d; \(\dfrac{32}{15}\): (-1\(\dfrac{1}{5}\) + 1\(\dfrac{1}{3}\))
= \(\dfrac{32}{15}\): (-\(\dfrac{6}{5}\) + \(\dfrac{4}{3}\))
= \(\dfrac{32}{15}\): \(\dfrac{2}{15}\)
= 16
lạy má, má vào cái ô trên cùng bên trái của phần gửi câu hỏi sẽ có các kí hiệu toán học
Ý bạn là thế này phải không:
\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{199}-\frac{1}{200}\)
\(=1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{200}-2.\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+....+\frac{1}{200}\right)\)
\(=\left(1+\frac{1}{2}+\frac{1}{3}+.....+\frac{1}{99}+\frac{1}{100}+\frac{1}{101}+...+\frac{1}{200}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}\right)\)
=\(\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
cau 1:8/45:8/9-2/5.x=8/45*9/8-2/5.x=8.9/45.8-2/5.x=1/5-2/5.x=2/-3. =>2/5.x=1/5-2/-3=3/15+2/3=3/15+10/15=13/15. =>x=13/15:2/5=13/15.5/2=13.5/15.2=13/6. Vậy x = 13/6. k nha co j ket ban
8/45 : 8/9 - 2/5 . X = 2/-3
8/45 . 9/8 - 2/5 . X = -2/3
1/5 - 2/5 . X = -2/3
-1/5 . X = -2/3
X = -2/3 : -1/5
X = -2/3 x 5/-1 = 10/3
=> x = 10/3
tk ủng hộ nhé !
nếu có sai nhờ anh/ chị / bạn sửa giùm em ạ !!!!!
\(\left(3\dfrac{1}{2}-2x\right)\cdot3\dfrac{1}{3}=7\dfrac{1}{3}\)
\(\Leftrightarrow-2x+\dfrac{7}{2}=\dfrac{22}{3}:\dfrac{10}{3}=\dfrac{11}{5}\)
=>-2x=-13/10
hay x=13/20