Question

[Anslimme2007]

So Sánh
a) A=\(\frac{135}{135\cdot136-1}\) và B=\(\frac{136}{136\cdot137-1}\)

b) \(\frac{123}{456}\)và \(\frac{456}{789}\)

c) M =\(\frac{3}{10}+\frac{3}{11}+\frac{3}{12}+\frac{3}{13}+\frac{3}{14}\)và N=2

Answer 1

[Mira - Mai]

a) \(A=\frac{135}{135.136-1}\)             và                    \(B=\frac{136}{136.137-1}\)

   \(A=\frac{1}{136-1}=\frac{1}{135}\)                             \(B=\frac{1}{137-1}=\frac{1}{136}\)

Vì \(\frac{1}{136}\)< \(\frac{1}{135}\)nên A > B.

Answer 2

[ducchinhle]

a, A = \(\frac{136-1}{\left(136-1\right)136-1}\) = \(\frac{136-1}{136^2-136-1}\)                 B=\(\frac{136}{136\left(136+1\right)-1}\)=\(\frac{136}{136^2+136-1}\)

x=136,  A-B =\(\frac{x-1}{x^2-x-1}\)-\(\frac{x}{x^2+x-1}\) =\(\frac{x^3+x^2-x-x^2-x+1-x^3+x^2+x}{\left(x^2-1\right)^2-x^2}\)=\(\frac{x^2-x+2}{\left(x^2-1\right)^2-x^2}\)<0

=> A<B

b,A = \(\frac{456-333}{456}\)= 1-333/456       B=\(\frac{789-333}{789}\)= 1-333/789

=> A>B

c, 3/14<3/13<3/12<3/11<3/10 <2/5

M = 3/10+3/11+3/12+3/13+3/14 < 2/5 x5 = 2= N