Question

[Nguyễn Lan Anh]

So sánh:

E = \(\dfrac{7^{58}+2}{7^{57}+2}\) ; F = \(\dfrac{7^{57}+2009}{7^{58}+2009}\)

Answer 1

[bảo nam trần]

Ta thấy \(7^{58}>7^{57}\Rightarrow7^{58}+2>7^{57}+2\Rightarrow E=\dfrac{7^{58}+2}{7^{57}+2}>1\)

\(7^{57}< 7^{58}\Rightarrow7^{57}+200< 7^{58}+200\Rightarrow F=\dfrac{7^{57}+200}{7^{58}+200}< 1\)

Vậy E > F

Answer 2

[Mashiro Shiina]

\(VT>1\) \(VP< 1\Leftrightarrow VT>VP\)