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\(A=\dfrac{5\left(11.13-22.26\right)}{22.26-44.52}\)
\(=\dfrac{5\left(11.13-22.26\right)}{2\left(11.13-22.26\right)}\)
\(=\dfrac{5}{2}\)
\(B=\dfrac{138^2-690}{137^2-548}\)
\(=\dfrac{138^2-138.5}{137^2-137.4}\)
\(=\dfrac{138\left(138-5\right)}{137\left(137-4\right)}\)
\(=\dfrac{138.133}{137.133}\)
\(=\dfrac{138}{137}\)
Ta có:
\(\dfrac{5}{2}=\dfrac{685}{274}\)
\(\dfrac{138}{137}=\dfrac{276}{274}\)
Vì vậy mà \(A>B\)
#die
\(A=\frac{5.\left(11.13-2.11.2.13\right)}{22.26-22.2.26.2}=\frac{5.11.13\left(1-2.2\right)}{22.26\left(1-2.2\right)}=\frac{5.11.13}{2.2.11.13}=\frac{5}{4}\)
\(B=\frac{138^2-138.5}{137^2-137.4}=\frac{138.\left(138-5\right)}{137.\left(137-4\right)}=\frac{138.133}{137.133}=\frac{138}{137}\)
\(\frac{138\cdot138-690}{137\cdot137-548}\)=\(\frac{137+1\cdot137+1-548+142}{137\cdot137-548}\)=\(\frac{1+1+142}{1}\)=\(\frac{144}{1}\)=144
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