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\(=\frac{2^{15}\cdot\left(3^2\right)^4}{2^7\cdot3^7\cdot\left(2^3\right)^3}\)
\(=\frac{2^{15}\cdot3^8}{2^7\cdot3^7\cdot2^9}\)
\(=\frac{2^{15}\cdot3^8}{2^{16}\cdot3^7}\)
\(=\frac{3}{2}\)
Bài làm :
\(\frac{2^{15}.9^4}{6^7.8^3}\)
\(=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.(2^3)^3}\)
\(=\frac{2^{15}.3^8}{2^7.3^7.2^9}\)
\(=\frac{3}{2}\)
Học tốt nhé
\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
\(=\frac{2^{19}.\left(3^3\right)^3+15.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2^{10}+\left(2^2.3\right)^{10}}\)
\(=\frac{2^{19}.3^9+15.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)
\(=\frac{2^{19}.3^9+15.2^{18}.3^8}{2^{19}.3^9+2^{20}.3^{10}}\)
\(=\frac{2^{18}.3^8\left(2.3+15\right)}{2^{19}.3^9\left(1+2.3\right)}\)
\(=\frac{6+15}{2.3\left(1+6\right)}\)
\(=\frac{21}{6.7}\)
\(=\frac{21}{42}\)
\(=\frac{1}{2}\)
\(\frac{4.6^{14}}{9^7.8^5}=\frac{2^2.\left(2.3\right)^{14}}{\left(3^2\right)^7.\left(2^3\right)^5}=\frac{2^{16}.3^{14}}{3^{14}.2^{15}}=2\)
\(\frac{4.6^{14}}{9^7.8^5}=\frac{2^2.2^{14}.3^{14}}{\left(3^2\right)^7.\left(2^3\right)^5}=\frac{2^2.2^{14}.3^{14}}{3^{14}.2^{15}}=2\)
học tốt
\(=\frac{2^{19}3^9+3\cdot5\cdot2^{18}\cdot3^8}{2^9\cdot3^9\cdot2^{10}+4^{10}\cdot3^{10}}=\frac{2^{19}\cdot3^9+5\cdot2^{18}\cdot3^9}{2^{19}\cdot3^9+2^{20}\cdot3^{10}}=\frac{2^{18}\cdot3^9\cdot\left(2+5\right)}{2^{19}\cdot3^9\left(1+6\right)}=\frac{1}{2}\)
\(P=\frac{3^{2010}-6^{2010}+9^{2010}-12^{2010}+15^{2010}-18^{2010}}{-1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}}\)
\(P=\frac{-3^{2010}.\left(-1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}\right)}{-1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}}\)
\(P=-3^{2010}\)
Bài làm :
Ta có :
\(\frac{2^{15}.9^4}{6^7.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^7.3^72^9}=\frac{3}{2}\)
Bài làm :
\(\frac{2^{15}.9^4}{6^7.8^3}\)
\(=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^7.\left(2^3\right)^3}\)
\(=\frac{2^{15}.3^8}{2^7.3^7.2^9}\)
\(=\frac{3}{2}\)
Học tốt nhé