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\(12x^2+7x-12\)
\(=12x^2-9x+16x-12\)
\(=3x\left(4x-3\right)+4\left(4x-3\right)\)
\(=\left(4x-3\right)\left(3x+4\right)\)
12x^2+7x-12=(12x^2-9x)+(16x-12)=3x(4x-3)+4(4x-3)=(3x+4)(4x-3)
chúc hok tốt
\(12x^2+7x-12=12x^2-5x+12x-12\)
\(=x\left(12x-5\right)+12\left(x-1\right)\)
Đề sai rồi bạn ời
\(12x^2+7x-12=\left(12x^2-9x\right)+\left(16x-12\right)=3x\left(4x-3\right)+4\left(4x-3\right)=\left(3x+4\right)\left(4x-3\right)\)
12x2 + 7x - 12
= 12x2 + 16x - 9x - 12
= 4x.( 3x + 4 ) - 3.( 3x + 4 )
= ( 3x + 4 ).( 4x - 3 )
\(12x^2+7x-12\)
\(=12x^2+16x-9x-12\)
\(=4x\left(3x+4\right)-3\left(3x+4\right)\)
\(=\left(4x-3\right)\left(3x+4\right)\)
\(12x^2+7x-10\)
\(=12x^2-8x+15x-10\)
\(=4x\left(3x-2\right)+5\left(3x-2\right)\)
\(=\left(4x+5\right)\left(3x-2\right)\)
\(=2x^4+6x^3-3x^3-9x^2-3x^2-9x+2x+6\)
\(=2x^3\left(x+3\right)-3x^2\left(x+3\right)-3x\left(x+3\right)+2\left(x+3\right)\)
\(=\left(x+3\right)\left(2x^3-4x^2+x^2-2x-x+2\right)=\left(x+3\right)\left(x-2\right)\left(2x^2+x-1\right)\)
\(=\left(x+3\right)\left(x-2\right)\left(2x^2+2x-x-1\right)=\left(x+3\right)\left(x-2\right)\left(x+1\right)\left(2x-1\right)\)
2x^4+3x^3-12x^2-7x+6 = (2x^4-x^3)+(4x^3-2x^2)-(10x^2-5x)-(12x-6)
= x^3.(2x-1)+2x^2.(2x-1)-5x.(2x-1)-6.(2x-1) = (2x-1).(x^3+2x^2-5x-6)
= (2x-1).[ (x^3+x^2)+(x^2+x)-(6x+6) ] = (2x-1).(x+1).(x^2+x-6) = (2x-1).(x-1).[(x^2-2x)+(3x-6)]
= (2x-1).(x+1).(x-2).(x+3)
k mk nha
\(12x^2+7x-12=12x^2-9x+16x-12=3x\left(4x-3\right)+4\left(4x-3\right)\)
\(=\left(3x+4\right)\left(4x-3\right)\)