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NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
18 tháng 9 2023
a, \(\dfrac{3}{7}\)\(x\)- \(\dfrac{2}{3}\)\(x\) = \(\dfrac{10}{21}\)
(\(\dfrac{3}{7}\) - \(\dfrac{2}{3}\)) \(\times\) \(x\) = \(\dfrac{10}{21}\)
- \(\dfrac{5}{21}\) \(\times\) \(x\) = \(\dfrac{10}{21}\)
\(x\) = \(\dfrac{10}{21}\) : (-\(\dfrac{5}{21}\))
\(x\) = -2
b, \(\dfrac{7}{35}\) : (\(x-\dfrac{1}{3}\)) = - \(\dfrac{2}{25}\)
\(x\) - \(\dfrac{1}{3}\) = \(\dfrac{7}{35}\) : (- \(\dfrac{2}{25}\))
\(x\) - \(\dfrac{1}{3}\) = - \(\dfrac{5}{2}\)
\(x\) = - \(\dfrac{5}{2}\) + \(\dfrac{1}{3}\)
\(x\) = - \(\dfrac{13}{6}\)
c, 3.(\(x\) - \(\dfrac{1}{2}\)) - 5.(\(x\) + \(\dfrac{3}{5}\)) = - \(x\)+ \(\dfrac{1}{5}\)
3\(x\) - \(\dfrac{3}{2}\) - 5\(x\) - 3 = - \(x\) + \(\dfrac{1}{5}\)
- \(x\) + 5\(x\) - 3\(x\) = - \(\dfrac{3}{2}\) - 3 - \(\dfrac{1}{5}\)
\(x\) = - \(\dfrac{47}{10}\)
NM
18 tháng 9 2023
\(a,\dfrac{3}{7}x-\dfrac{2}{3}x=\dfrac{10}{21}\\ \Rightarrow x\left(\dfrac{3}{7}-\dfrac{2}{3}\right)=\dfrac{10}{21}\\ \Rightarrow x.-\dfrac{5}{21}=\dfrac{10}{21}\\ \Rightarrow x=-2\\ b,\dfrac{7}{35}:\left(x-\dfrac{1}{3}\right)=-\dfrac{2}{25}\\ \Rightarrow\dfrac{1}{5}:\left(x-\dfrac{1}{3}\right)=-\dfrac{2}{25}\\ \Rightarrow x-\dfrac{1}{3}=-\dfrac{5}{2}\\ \Rightarrow x=-\dfrac{13}{6}\\ c,3.\left(x-\dfrac{1}{2}\right)-5.\left(x+\dfrac{3}{5}\right)=-x+\dfrac{1}{5}\\ \Rightarrow3x-\dfrac{3}{2}-5x+5=-x+\dfrac{1}{5}\)
\(\Rightarrow x\left(3-5\right)-\dfrac{3}{2}+5=-x+\dfrac{1}{5}\\ \Rightarrow-2x-\dfrac{13}{2}=-x+\dfrac{1}{5}\\ \Rightarrow-x-\dfrac{13}{5}=\dfrac{1}{5}\\ \Rightarrow x=\dfrac{1}{5}-\dfrac{13}{5}\\ \Rightarrow x=-\dfrac{12}{5}.\)
30 tháng 8 2017
a) \(\dfrac{3}{7}x-\dfrac{2}{3}x=\dfrac{10}{21}\)
<=> \(x\left(\dfrac{3}{7}-\dfrac{2}{3}\right)=\dfrac{10}{21}\)
<=> \(x.\left(-\dfrac{5}{21}\right)=\dfrac{10}{21}\)
<=> \(x=-2\)
b) \(\dfrac{7}{35}:\left(x-\dfrac{1}{3}\right)=-\dfrac{2}{25}\)
<=> \(x-\dfrac{1}{3}=-\dfrac{5}{2}\)
<=> \(x=-\dfrac{13}{6}\)
30 tháng 8 2017
a, \(\dfrac{3}{7}x-\dfrac{2}{3}x=\dfrac{10}{21}\)
\(\Leftrightarrow x\left(\dfrac{3}{7}-\dfrac{2}{3}\right)=\dfrac{10}{21}\)
\(\Leftrightarrow x.\dfrac{-5}{21}=\dfrac{10}{21}\)
\(\Leftrightarrow x=-2\)
Vậy ...
b, \(\dfrac{7}{35}:\left(x-\dfrac{1}{3}\right)=\dfrac{-2}{25}\)
\(\Leftrightarrow x-\dfrac{1}{3}=\dfrac{-5}{2}\)
\(\Leftrightarrow x=\dfrac{-13}{6}\)
Vậy ...
NL
2
28 tháng 8 2017
\(\dfrac{3}{7}x-\dfrac{2}{3}x=\dfrac{10}{21}\)
\(x\left(\dfrac{3}{7}-\dfrac{2}{3}\right)=\dfrac{10}{21}\)
\(-\dfrac{5}{21}x=\dfrac{10}{21}\)
\(x=\dfrac{10}{21}:\left(-\dfrac{5}{21}\right)\)
\(x=-2\)
30 tháng 12 2021
\(\text{a)}\dfrac{-3}{5}-x=\dfrac{21}{10}\)
\(x=\dfrac{-3}{5}-\dfrac{21}{10}=\dfrac{-27}{10}\)
\(\text{b)}x:\dfrac{2}{9}=\dfrac{9}{2}\)
\(x\) \(=\dfrac{9}{2}.\dfrac{2}{9}=1\)
\(\text{c) }\dfrac{x}{9}=\dfrac{5}{3}\)
\(\Rightarrow x=\dfrac{9.5}{3}=15\)
\(\text{d)}x:\left(\dfrac{2}{5}\right)^3=\left(\dfrac{5}{2}\right)^3\)
\(x:\dfrac{8}{125}=\dfrac{125}{8}\)
\(x\) \(=\dfrac{125}{8}.\dfrac{8}{125}=1\)
30 tháng 6 2021
Ta có: \(-\dfrac{3}{7}-\dfrac{2}{21}+\left(2\dfrac{2}{3}-3\dfrac{1}{4}\right)=x-\dfrac{5}{3}\)
\(\Leftrightarrow x-\dfrac{5}{3}=-\dfrac{3}{7}-\dfrac{2}{21}+\dfrac{8}{3}-\dfrac{13}{4}\)
\(\Leftrightarrow x-\dfrac{5}{3}=-\dfrac{31}{28}\)
hay \(x=\dfrac{47}{84}\)
Vậy: \(x=\dfrac{47}{84}\)
H
30 tháng 12 2021
\(\dfrac{-3}{5}-x=\dfrac{21}{10}\)
\(x=\dfrac{-3}{5}-\dfrac{21}{10}\)
\(x=\)-\(\dfrac{27}{10}\)
\(x:\dfrac{2}{9}=\dfrac{9}{2}\)
\(x.\dfrac{9}{2}=\dfrac{9}{2}\)
\(x=\dfrac{9}{2}:\dfrac{9}{2}\)
\(x=1\)
\(\dfrac{x}{9}=\dfrac{5}{3}\)
\(x.3=5.9\)
\(x.3=45\)
\(x=45:3=15\)
\(x:\left(\dfrac{2}{5}\right)^3=\left(\dfrac{5}{2}\right)^3\)
\(x:\dfrac{8}{125}=\dfrac{125}{8}\)
\(x.\dfrac{125}{8}=\dfrac{125}{8}\)
\(x=\dfrac{125}{8}:\dfrac{125}{8}=1\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
20 tháng 9 2023
a, - \(\dfrac{1}{10}\) + \(\dfrac{2}{5}\)\(x\) + \(\dfrac{7}{20}\) = \(\dfrac{1}{10}\)
\(\dfrac{2}{5}\)\(x\) = \(\dfrac{1}{10}\) - \(\dfrac{7}{20}\) + \(\dfrac{1}{10}\)
\(\dfrac{2}{5}\) \(x\) = - \(\dfrac{3}{20}\)
\(x\) = - \(\dfrac{3}{20}\): \(\dfrac{2}{5}\)
\(x\) = - \(\dfrac{3}{8}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
20 tháng 9 2023
b, \(\dfrac{1}{3}\) + \(\dfrac{1}{2}\): \(x\) = - \(\dfrac{1}{5}\)
\(\dfrac{1}{2}\): \(x\) = - \(\dfrac{1}{5}\) - \(\dfrac{1}{3}\)
\(\dfrac{1}{2}\): \(x\) = - \(\dfrac{8}{15}\)
\(x\) = \(\dfrac{1}{2}\): (- \(\dfrac{8}{15}\))
\(x\) = - \(\dfrac{15}{16}\)
TA
11 tháng 6 2021
`2/3 x + 5/7 = 3/10`
`2/3 x= 3/10 - 5/7`
`2/3 x=-29/70`
`x = -29/70 : 2/3`
`x=-87/140`
b) `3/4 .x-1/2=3/7`
`3/4 .x=3/7+1/2`
`3/4 .x=13/14`
`x= 13/14 : 3/4`
`x=26/21`
`3/7 x -2/3 x =10/21`
`=> (3/7-2/3)x=10/21`
`=> ( 9/21 - 14/21)x=10/21`
`=>-5/21 x=10/21`
`=> x=10/21 : (-5/21)`
`=> x=10/21 xx (-21/5)`
`=>x=-2`
(3/7 - 2/3).x = 10/21
-5/21.x = 10/21
x = 10/21 : (-5/21)
x = -2
vậy x = -2