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a) 1/20 - (x - 8/5) = 1/10
x - 8/5 = 1/20 - 1/10
x - 8/5 = -1/20
x = -1/20 + 8/5
x = 31/20
b) 7/4 - (x + 5/3) = -12/5
x + 5/3 = 7/4 + 12/5
x + 5/3 = 83/20
x = 83/20 - 5/3
x = 149/60
c) x - [17/2 - (-3/7 + 5/3)] = -1/3
x - (17/2 - 26/21) = -1/3
x - 305/42 = -1/3
x = -1/3 + 305/42
x = 97/14
chắc h có mấy thành cay r nên ko làm bn lên mạng tải phẩn mêm có cánh iair đó :D
a:=>3x=15
=>x=5
b: =>x+3=0,96
=>x=-2,04
c: =>x^2=36
=>x=6 hoặc x=-6
`a, 3/4=(3x)/20`
`3x*4=3*20`
`3x*4=60`
`3x=60 \div 4`
`3x=15`
`x=15 \div 3`
`x=5`
`b, (1,2)/(x+3)=5/4`
`1,2*4=(x+3)*5`
`4,8=(x+3)*5`
`x+3= 4,8 \div 5`
`x+3=0,96`
`x=0,96-3`
`x=-2,04`
`c, (x^2)/32=9/8`
`x^2*8=32*9`
`x^2*8=288`
`x^2=288 \div 8`
`x^2=36`
`x^2=(+-6)^2`
`-> \text {x= 6 hoặc -6}`
e: \(=\dfrac{5^{30}\cdot3^{20}}{3^{15}\cdot5^{30}}=3^5=243\)
a, \(\dfrac{5}{2}\)\(x\) - \(\dfrac{3}{4}\) = \(\dfrac{1}{4}\)
\(\dfrac{5}{2}\)\(x\) = \(\dfrac{1}{4}\) + \(\dfrac{3}{4}\)
\(\dfrac{5}{2}\)\(x\) = 1
\(x\) = 1: \(\dfrac{5}{2}\)
\(x\) = \(\dfrac{2}{5}\)
b, \(\dfrac{x+4}{20}\) = \(\dfrac{5}{x+4}\) (đk \(x\) ≠ -4)
(\(x\)+4).(\(x\) + 4) = 20.5
(\(x\)+ 4)2 = 100
(\(x\) + 4)2 = 102
\(\left[{}\begin{matrix}x+4=-10\\x+4=10\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-10-4\\x=10-4\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-14\\x=6\end{matrix}\right.\)
Vậy \(x\) \(\in\) {-14; 6}
a, - \(\dfrac{1}{10}\) + \(\dfrac{2}{5}\)\(x\) + \(\dfrac{7}{20}\) = \(\dfrac{1}{10}\)
\(\dfrac{2}{5}\)\(x\) = \(\dfrac{1}{10}\) - \(\dfrac{7}{20}\) + \(\dfrac{1}{10}\)
\(\dfrac{2}{5}\) \(x\) = - \(\dfrac{3}{20}\)
\(x\) = - \(\dfrac{3}{20}\): \(\dfrac{2}{5}\)
\(x\) = - \(\dfrac{3}{8}\)
b, \(\dfrac{1}{3}\) + \(\dfrac{1}{2}\): \(x\) = - \(\dfrac{1}{5}\)
\(\dfrac{1}{2}\): \(x\) = - \(\dfrac{1}{5}\) - \(\dfrac{1}{3}\)
\(\dfrac{1}{2}\): \(x\) = - \(\dfrac{8}{15}\)
\(x\) = \(\dfrac{1}{2}\): (- \(\dfrac{8}{15}\))
\(x\) = - \(\dfrac{15}{16}\)
`#3107`
a)
\(\dfrac{11}{12}-\left(\dfrac{2}{5}+\dfrac{3}{4}x\right)=\dfrac{2}{3}?\\ \Rightarrow\dfrac{2}{5}+\dfrac{3}{4}x=\dfrac{11}{12}-\dfrac{2}{3}\\ \Rightarrow\dfrac{2}{5}+\dfrac{3}{4}x=\dfrac{1}{4}\\ \Rightarrow\dfrac{3}{4}x=\dfrac{1}{4}-\dfrac{2}{5}\\ \Rightarrow\dfrac{3}{4}x=-\dfrac{3}{20}\\ \Rightarrow x=-\dfrac{3}{20}\div\dfrac{3}{4}\\ \Rightarrow x=-\dfrac{1}{5}\)
Vậy, \(x=-\dfrac{1}{5}\)
b)
\(\dfrac{-2}{5}+\dfrac{5}{3}\cdot\left(\dfrac{3}{2}-\dfrac{4}{15}x\right)=\dfrac{-7}{6}\\ \Rightarrow\dfrac{5}{3}\cdot\left(\dfrac{3}{2}-\dfrac{4}{15}x\right)=\dfrac{-7}{6}-\dfrac{-2}{5}\\ \Rightarrow\dfrac{5}{3}\cdot\left(\dfrac{3}{2}-\dfrac{4}{15}x\right)=-\dfrac{23}{30}\\ \Rightarrow\dfrac{3}{2}-\dfrac{4}{15}x=-\dfrac{23}{30}\div\dfrac{5}{3}\\ \Rightarrow\dfrac{3}{2}-\dfrac{4}{15}x=-\dfrac{23}{50}\\ \Rightarrow\dfrac{4}{15}x=\dfrac{3}{2}-\left(-\dfrac{23}{50}\right)\\ \Rightarrow\dfrac{4}{15}x=\dfrac{49}{25}\\ \Rightarrow x=\dfrac{147}{20}\)
Vậy, \(x=\dfrac{147}{20}\)
c)
\(\dfrac{1}{2}+\dfrac{3}{4}x=\dfrac{1}{4}\\ \Rightarrow\dfrac{3}{4}x=\dfrac{1}{4}-\dfrac{1}{2}\\ \Rightarrow\dfrac{3}{4}x=-\dfrac{1}{4}\\ \Rightarrow x=-\dfrac{1}{4}\div\dfrac{3}{4}\\ \Rightarrow x=-\dfrac{1}{3}\)
Vậy, \(x=-\dfrac{1}{3}.\)
\(#Emyeu1aithatroi...\)
(2/5 + 3/4 . x)= 11/12 -2/3
(2/5 +3/4 . x)= 1/4
3/4 . x = 1/4 - 2/5
3/4 . x = -3/20
x = -3/20 : 3/4
x = -1/5
Vậy .....
\(\dfrac{3}{4}+\dfrac{2}{5}x=\dfrac{3}{20}\\ =>\dfrac{2}{5}x=\dfrac{3}{20}-\dfrac{3}{4}\\ =>\dfrac{2}{5}x=\dfrac{3-3\times5}{20}\\ =>\dfrac{2}{5}x=-\dfrac{3}{5}\\ =>x=-\dfrac{3}{5}:\dfrac{2}{5}\\ =>x=-\dfrac{3}{2}\)
Vậy \(S=\left\{-\dfrac{3}{2}\right\}\)
\(\dfrac{2}{5}x=\dfrac{3}{20}-\dfrac{3}{4}\)
\(\dfrac{2}{5}x\)=\(\dfrac{-3}{5}\)
x=\(\dfrac{-3}{5}\):\(\dfrac{2}{5}\)
x=\(\dfrac{-3}{2}\)