Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(645-\left(27+x\right)-342=123\)
\(\Leftrightarrow\)\(-24-x=123\)
\(\Leftrightarrow\)\(x=123+24=147\)
Vậy...
b) \(\left|x\right|+87=123\)
\(\Leftrightarrow\)\(\left|x\right|=123-87=36\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=36\\x=-36\end{cases}}\)
Vậy....
c) \(\left|x-12\right|=42\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x-12=42\\x-12=-42\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=54\\x=-30\end{cases}}\)
Vậy...
a) 645 - ( 27 + x ) - 342 = 123
645 - ( 27 + x ) = 123 + 342
645 - ( 27 + x ) = 465
27 + x = 645 - 465
27 + x = 180
x = 180 - 27
x = 53
b) ! x ! + 87 = 123
! x ! = 123 - 87
! x ! = 36
-> x = 36 hoặc x = -36
c) ! x - 12 ! = 42
-> x - 12 = 42 hoặc x - 12 = -42
Nếu x - 12 = 42 thì ta có : Nếu x - 12 = -42 thì ta có :
x = 42 + 12 x = -42 + 12
x = 54 x = -30
a, (-72).(15 - 49) + 15.(-56 + 72)
= -72 . 15 + 72.49 - 15.56 + 15.72
= (-72.15 + 15.72) + (72.49 - 15.56)
= 3528 - 84
= 2688
1b, 1532 + (-186) + (-1432) + (-14) + 123
= (1532 - 1432) - (186 + 14) + 123
= 100 - 200 + 123
= 223 - 200
= 23
\(x\left(x+1\right)=156\)
\(\Rightarrow x^2+x=156\)
\(\Rightarrow x^2+x-156=0\)
\(\Rightarrow x^2+13x-12x-156=0\)
\(\Rightarrow x\left(x+13\right)-12\left(x+13\right)=0\)
\(\Rightarrow\left(x+13\right)\left(x-12\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=12\\x=-13\end{matrix}\right.\)
___________________
\(x\left(x+1\right)=342\)
\(\Rightarrow x^2+x=342\)
\(\Rightarrow x^2+x-342=0\)
\(\Rightarrow x^2+19x-18x-342=0\)
\(\Rightarrow x\left(x+19\right)-18\left(x+19\right)=0\)
\(\Rightarrow\left(x+19\right)\left(x-18\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=-19\\x=18\end{matrix}\right.\)
__________________
\(x\left(x+1\right)=650\)
\(\Rightarrow x^2+x=650\)
\(\Rightarrow x^2-x+650=0\)
\(\Rightarrow x^2+26x-25x-650=0\)
\(\Rightarrow x\left(x+26\right)-25\left(x+26\right)=0\)
\(\Rightarrow\left(x+26\right)\left(x-25\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=-26\\x=25\end{matrix}\right.\)
______________________
\(x\left(x+1\right)=380\)
\(\Rightarrow x^2+x=380\)
\(\Rightarrow x^2+x-380=0\)
\(\Rightarrow x^2+20x-19x-380=0\)
\(\Rightarrow x\left(x+20\right)-19\left(x+20\right)=0\)
\(\Rightarrow\left(x+20\right)\left(x-19\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=-20\\x=19\end{matrix}\right.\)
a, \(x\).(\(x\) + 1) = 156
156 = 22.3.13 = 12.13
Vậy \(x\).(\(x\) + 1) = 12.13
Vậy \(x\) = 12
b, \(x.\)(\(x\) + 1) = 342
342 = 2.32.19 = 18.19
\(x\).(\(x+1\)) = 18.19
\(x\) = 18
c, \(x\).(\(x\) + 1) = 650
650 = 2.52.13 = 25.26
\(x\).(\(x\) +1) = 25.26
\(x\) = 25
d, \(x\).(\(x\) +1) = 380
380 = 22.5.19 = 19.20
\(x\).(\(x\) + 1) = 19.20
\(x\) = 19
$-48\times76+48\times(-123)$
$=-48\times76+(-48)\times123$
$=-48\times(76+123)$
$=-48\times199$
$=-9552$
−48.76+48.(−123)
=−48.76+(−48).123
=−48.(76+123)
=−48.199
=−9552
43 + 2.(x - 342 ) = 123
2.(x-342 ) = 123 - 43
2.(x-342) = 80
x - 342 = 80 : 2
x - 342 = 40
x = 40 + 342
x = 382
ket qua la 382