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Ta có: 1/4+1/5+...+1/10>1/10.7=7/10
1/11+1/12+...+1/19>1/20.9=9/20
Kết hợp lại ta có B= 1/4+1/5+1/6+...+1/19>7/10+9/20=23/20>1.Vậy B>1
ta co 1/4+1/5+......+1/10>1/10.7=7/10
1/11+1/12+.....1/19>1/20.9=9/20
kết hợp lại ta có mB=1/4+1/5+1/6+......1/19>7/10+9/20=23/20>1 vậy B>1
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vì \(\frac{1}{4}< 1,\frac{1}{5}< 1,......,\frac{1}{19}< 1\) nên B < 1.
Ta có: \(B=\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+...+\frac{1}{19}\)
\(\Rightarrow B=\frac{1}{4}+\left(\frac{1}{5}+\frac{1}{6}+...+\frac{1}{9}\right)+\left(\frac{1}{10}+\frac{1}{11}+...+\frac{1}{19}\right)\)
Vì \(\frac{1}{5}+\frac{1}{6}+...+\frac{1}{9}>\frac{1}{9}+\frac{1}{9}+...+\frac{1}{9}=5\cdot\frac{1}{9}=\frac{5}{9}>\frac{1}{2}\)
Vì \(\frac{1}{10}+\frac{1}{11}+...+\frac{1}{19}>\frac{1}{19}+...+\frac{1}{19}=10\cdot\frac{1}{19}=\frac{10}{19}>\frac{1}{2}\)
\(\Rightarrow B>\frac{1}{4}+\frac{5}{9}+\frac{10}{19}>\frac{1}{4}+\frac{1}{2}+\frac{1}{2}=\frac{1}{4}+\frac{2}{4}+\frac{2}{4}\)
\(\Rightarrow B>\frac{5}{4}>1\Rightarrow B>1\)
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ta có: \(\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+...+\frac{1}{10}>\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+...+\frac{1}{10}=\frac{7}{10}\)( có 7 số 1/10)
\(\frac{1}{11}+...+\frac{1}{19}>\frac{1}{19}+...+\frac{1}{19}=\frac{9}{19}\)( có 9 số 1/19)
\(\Rightarrow\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+...+\frac{1}{19}>\frac{7}{10}+\frac{9}{19}=1\frac{33}{190}>1\)
\(\Rightarrow B=\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+...+\frac{1}{19}>1\left(đpcm\right)\)
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Ta thấy:
\(\frac{1}{2^2}< \frac{1}{1.2}\)
\(\frac{1}{3^2}< \frac{1}{2.3}\)
........................
\(\frac{1}{8^2}< \frac{1}{7.8}\)
\(\Rightarrow B< \frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{7.8}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{7}-\frac{1}{8}=1-\frac{1}{8}< 1\)
Vậy B < 1
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B = 1/22 + 1/32 + 1/42 + 1/52 + 1/62 + 1/72 + 1/82 < 1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8
B = < 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8
B = < 1 - 1/8 < 1
=> đpcm
Ta có:\(\frac{1}{5}>\frac{1}{6}>...>\frac{1}{19}\)
=>B=\(\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+...+\frac{1}{19}>\frac{1}{4}+\frac{1}{19}+\frac{1}{19}+...+\frac{1}{19}\)(15 lần 1/19)
=>B>1/4+15/19=79/76>1
=>B>1