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a) (x+2)2+(y-3)4 = 0
\(\Rightarrow\hept{\begin{cases}\left(x+2\right)^2=0\\\left(y-3\right)^4=0\end{cases}\Rightarrow\hept{\begin{cases}x=-2\\x=3\end{cases}}}\)
Vậy ...
a) 350 - 6(x - 2) = 230
6(x - 2) = 350 - 230
6(x - 2) = 120
x - 2 = 120 : 6
x - 2 = 20
x = 20 + 2
x = 22
a) 1800 : ( 2 + 4x ) - 100 = 200
=>1800 : ( 2 + 4x ) = 300
=> 2 + 4x = 6
=> 4x = 2
=> x = 2
\(1800:\left(2+4x\right)-100=200\) \(500-\left(9x+700\right):4=100\)
\(1800:\left(2+4x\right)=200+100\) \(\left(9x+700\right):4=500-100\)
\(1800:\left(2+4x\right)=300\) \(\left(9x+700\right):4=400\)
\(2+4x=1800:300\) \(9x+700=400\cdot4\)
\(2+4x=6\) \(9x+700=800\)
\(4x=6-2\) \(9x=800-700\)
\(4x=4\Leftrightarrow x=4:4\Leftrightarrow x=1\) \(9x=100\Leftrightarrow x=100:9\Leftrightarrow x=\frac{100}{9}\)
Ta có : 7(x - 1) + 2x(x - 1) = 0
<=> (2x + 7)(x - 1) = 0
\(\Leftrightarrow\orbr{\begin{cases}2x+7=0\\x-1=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=-7\\x=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-\frac{7}{2}\\x=1\end{cases}}\)
\(-7\left(5-x\right)-2\left(x-10\right)=15\)
\(\Leftrightarrow-35+7x-2x+20=15\)
\(\Leftrightarrow5x-5=15\)
\(\Leftrightarrow5x=20\)
\(\Leftrightarrow x=4\)
Vậy \(x=4\)
\(4\left(x-1\right)-3\left(x-2\right)=-|-5|\)
\(\Leftrightarrow4x-4-3x+6=-5\)
\(\Leftrightarrow x+2=-5\)
\(\Leftrightarrow x=-7\)
Vậy \(x=-7\)
~ học tốt ~
a) \(5\left(x+7\right)-10=2^3\cdot5\)
\(\Rightarrow5\left(x+7\right)-10=40\)
\(\Rightarrow5\left(x+7\right)=40+10\)
\(\Rightarrow x+7=\dfrac{50}{5}\)
\(\Rightarrow x+7=10\)
\(\Rightarrow x=10-7\)
\(\Rightarrow x=3\)
b) \(9x-2\cdot3^2=3^4\)
\(\Rightarrow9x-18=81\)
\(\Rightarrow9x=81+18\)
\(\Rightarrow9x=99\)
\(\Rightarrow x=\dfrac{99}{9}\)
\(\Rightarrow x=11\)
c) \(5^{25}\cdot5^{x-1}=5^{25}\)
\(\Rightarrow5^{x-1}=5^{25}:5^{25}\)
\(\Rightarrow5^{x-1}=1\)
\(\Rightarrow5^{x-1}=5^0\)
\(\Rightarrow x-1=0\)
\(\Rightarrow x=1\)
9x+5.4 = 200 4x-20 = 2^5:2^2 2.3^x-5=157
9x+ 20 = 200 4x-20 = 2^3 2.3^x=157+5
9x = 200-20 4x-20 = 8 2.3^x=162
9x = 180 4x = 8+20 3^x=162:2
x= 180 : 9 4x = 28 3^x=81
x=2 x = 28:4 mà 3^4=81 => x=4
x = 7
giúp mình với nha chiều nộp rồi
câu 1:
\(\left(9x+2\right)\cdot3=50\)
\(\Leftrightarrow9x+2=\frac{50}{3}\)
\(\Leftrightarrow9x=\frac{44}{3}\)
\(\Leftrightarrow x=\frac{44}{27}\)
Câu2
\(\left(9x+5\right)\cdot4=200\)
\(\Leftrightarrow9x+5=50\)
\(\Leftrightarrow9x=45\)
\(\Leftrightarrow x=5\)