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a) 200 + 300 x 2 - 100 + ( -100)
= 200 + 600 - 100 + ( -100 )
= 800 - 100 + ( -100 )
= 700 + ( -100 )
= 600
b) 500 - 100 x 3 + ( -13 )
= 500 - 300 + ( -13 )
= 200 + ( -13 )
= 187
a ) 200 + 300 x 2 - 100 + ( - 100 )
= 200 + 600 - 100 + ( - 100 )
= 800 - 100 + ( - 100 )
= 700 + ( - 100 )
= 600
b ) 500 - 100 x 3 + ( - 13 )
= 500 - 300 + ( - 13 )
= 200 + ( - 13 )
= 187
\(a,3\left(x+1\right)-2=4\)
\(\Leftrightarrow3\left(x+1\right)=6\)
\(\Leftrightarrow x+1=2\)
\(\Leftrightarrow x=1\)
Vậy x=1
Các câu còn lại lm tương tự nhé
\(3\left(x+1\right)-2=4\)
<=> \(3x+3-2=4\)
<=> \(3x=3\)
<=> \(x=1\)
\(5\left(x-2\right)+20=45\)
<=> \(5x-10=25\)
<=> \(x=7\)
\(700-7\left(x+2\right)=140\)
<=> \(7x+14=560\)
<=> \(7x=546\)
<=> \(x=78\)
\(200-5\left(2x+4\right)=100\)
<=> \(10x+20=100\)
<=> \(x=8\)
\(5\left(2x-4\right)+150=250\)
<=> \(10x-20=100\)
<=> \(x=12\)
học tốt
a, A = {24;36;48;60}
b, Ta có: B(12) = {0;24;36;48;60;72;84;96;108;120;132;144;156;168;180;192}
B(18) = {0;18;36;54;72;90;108;126;144;162;180;198}
BC(12,18) = B(12) ∩ B(18) = {0;36;72;144;180}
c, BC(12,3) = B(12) ∩ B(3) = {24;36;48;60;72;84;96}
d, B(10) = {0;10;20;30;40;50;60;70;80;90;100;110;120;130;140;150;160;170;180;190}
B(15) = {0;15;30;45;60;75;90;105;120;135;150;165;180;195}
BC(10,15) = B(10) ∩ B(15) = {0;30;60;90;120;150;180}
e, E = B(60) = {0;60;120;180;240;300;360;420;480}
f, F = B(60) = {120;180;240;300;360;420;480}
b) ( x + 500 ) = 1000 - 200 . 2
x + 500 = 1000 - 400
x + 500 = 600
x = 600 - 500
x = 100
100-200-300-400-500-600-700-800-900-1000=-5300
1000+299-1345-234-345-456-567-678-789-89=-3204
1005 : 1003 = 1002
102 . 101 = 103
500200 . 50010 = 500210
105 . 102 = 107
10030 . 10010 = 10040
200100 : 20010 = 20090
10020 . 10010 = 10030
300100 . 300100 = 300200
1005 : 1003
= 1005 - 3
= 1002
102 . 101
= 102 + 1
= 103
500200 . 50010
= 500200 + 10
= 500210
105 . 102
= 105 + 2
= 107
10030 . 10010
= 10030 + 10
= 10040
200100 : 20010
= 200100 - 10
= 200190
10020 . 10010
= 10020 + 10
= 10030
300100 .300100
= 300100 + 100
= 300200
a)
\(512-\left(128-5x\right)=3x+12\\ 512-128+5x=3x+12\\ 384+5x=3x+12\\ 5x-3x=12-384\\ 2x=-372\\ x=\left(-372\right):2\\ x=-186\)
b)
\(\left(2x-1\right)+\left(4x-2\right)+...+\left(400x-200\right)=5+10+...+1000\\ \left(2x+4x+...+400x\right)-\left(1+2+...+200\right)=5+10+...+1000\\ x\left(2+4+...+400\right)=\left(5+10+...+1000\right)+\left(1+2+...+200\right)\\ 2x\cdot\left(1+2+...+200\right)=5\cdot\left(1+2+...+200\right)+1\cdot\left(1+2+...+200\right)\\ 2x\cdot\left(1+2+...+200\right)=\left(5+1\right)\cdot\left(1+2+...+200\right)\\ 2x\cdot\left(1+2+...+200\right)=6\cdot\left(1+2+...+200\right)\\ \Rightarrow2x=6\\ x=6:2\\ x=3\)
c)
\(\left(x+2\right)+\left(4x+4\right)+\left(7x+6\right)+...+\left(25x+18\right)+\left(28x+20\right)=1560\\ \left(x+4x+7x+...+25x+28x\right)+\left(2+4+6+...+18+20\right)=1560\\ x\left(1+4+7+...+25+28\right)+110=1560\\ 145x+110=1560\\ 145x=1560-110\\ 145x=1450\\ x=1450:145\\ x=10\)
d)
\(x+4x+5x+9x+14x+...+97x=500\\ x\left(1+4+5+9+14+...+97\right)=500\)
Dãy số trong ngoặc có quy luật: Số thứ \(n\) bằng số thứ \(n-1\) cộng số thứ \(n-2\)
Suy ra dãy số đó là: \(1+4+5+9+14+23+37+60+97=250\)
Thế vào ta được:
\(250x=500\\ x=500:250\\ x=2\)
e)
\(720-\left[41-\left(2x-5\right)\right]=2^3\cdot5\\ 720-41+\left(2x-5\right)=8\cdot5\\ 720-41+2x-5=40\\ \left(720-41-5\right)+2x=40\\ 674+2x=40\\ 2x=40-674\\ 2x=-634\\ x=\left(-634\right):2\\ x=-317\)
f)
\(697:\dfrac{15x+364}{x}=17\\ \dfrac{15x+364}{x}=697:17\\ \dfrac{15x+364}{x}=41\\ \dfrac{15x+364}{x}\cdot x=41x\\ 15x+364=41x\\ 364=41x-15x\\ 364=26x\\ x=364:26\\ x=14\)
a) 1800 : ( 2 + 4x ) - 100 = 200
=>1800 : ( 2 + 4x ) = 300
=> 2 + 4x = 6
=> 4x = 2
=> x = 2
\(1800:\left(2+4x\right)-100=200\) \(500-\left(9x+700\right):4=100\)
\(1800:\left(2+4x\right)=200+100\) \(\left(9x+700\right):4=500-100\)
\(1800:\left(2+4x\right)=300\) \(\left(9x+700\right):4=400\)
\(2+4x=1800:300\) \(9x+700=400\cdot4\)
\(2+4x=6\) \(9x+700=800\)
\(4x=6-2\) \(9x=800-700\)
\(4x=4\Leftrightarrow x=4:4\Leftrightarrow x=1\) \(9x=100\Leftrightarrow x=100:9\Leftrightarrow x=\frac{100}{9}\)