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NV
3 tháng 7 2016
|2x| = 9 - 5x
\(\Rightarrow\orbr{\begin{cases}2x=9-5x\\2x=5x-9\end{cases}\Rightarrow\orbr{\begin{cases}7x=9\\-3x=-9\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{9}{7}\\x=3\end{cases}}}\)
Vậy x = 9/7 , x = 3
16 tháng 11 2021
Bài 1:
a: \(\Leftrightarrow x\cdot\left(-11\right)=121\)
hay x=-11
K
3
NT
Nguyễn Thế Vinh
VIP
25 tháng 1 2021
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25 tháng 1 2021
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DN
Các bn ơi. Giúp mik với!!!!!! Mik đang gấp lắm
Đề bài:
Tìm giá trị của x biết |x| = \(\dfrac{-2}{9}\)
6
26 tháng 10 2021
\(\left|x\right|=-\dfrac{2}{9}\)(vô lý do \(\left|x\right|\ge0\forall x\))
Vậy \(S=\varnothing\)
30 tháng 12 2021
a x = \(\dfrac{-1}{12}\)
b x = \(\dfrac{-4}{3}\)
c x = \(\dfrac{-1}{6}\)
d x = \(\dfrac{-1}{4}\)
30 tháng 12 2021
\(\left(4x+1\right)^2=\dfrac{4}{9}\)
\(\left(4x+1\right)=\perp\left(\dfrac{2}{3}\right)^2\)
\(\text{Vậy }4x+1=\dfrac{2}{3}\)
\(4x\) \(=\dfrac{2}{3}+\left(-1\right)=\dfrac{-1}{3}\)
\(x\) \(=\left(\dfrac{-1}{3}\right).\dfrac{1}{4}=\dfrac{-1}{12}\)
\(\text{hoặc }4x+1=\dfrac{-2}{3}\)
\(4x\) \(=\left(\dfrac{-2}{3}\right)+\left(-1\right)=\dfrac{-5}{3}\)
\(x\) \(=\left(\dfrac{-5}{3}\right).\dfrac{1}{4}=\dfrac{-5}{12}\)
\(\Rightarrow x\in\left\{\dfrac{-1}{12};\dfrac{-5}{12}\right\}\)
\(\left(3x-1\right)^2=25\)
\(\left(3x-1\right)^2=\perp\left(5\right)^2\)
\(\text{Vậy }3x-1=5\)
\(3x\) \(=5+1=6\)
\(x\) \(=6:3=2\)
\(\text{hoặc }3x-1=-5\)
\(3x\) \(=\left(-5\right)+1=-4\)
\(x\) \(=\left(-4\right):3=\dfrac{-4}{3}\)
\(\Rightarrow x\in\left\{2;\dfrac{-4}{3}\right\}\)
\(\left(x-\dfrac{1}{3}\right)^2=\dfrac{1}{4}\)
\(\left(x-\dfrac{1}{3}\right)^2=\perp\left(\dfrac{1}{2}\right)^2\)
\(\text{Vậy }x-\dfrac{1}{3}=\dfrac{1}{2}\)
\(x\) \(=\dfrac{1}{2}+\dfrac{1}{3}=\dfrac{5}{6}\)
\(\text{hoặc }x-\dfrac{1}{3}=\dfrac{-1}{2}\)
\(x\) \(=\left(\dfrac{-1}{2}\right)+\dfrac{1}{3}=\dfrac{-1}{6}\)
\(\Rightarrow x\in\left\{\dfrac{5}{6};\dfrac{-1}{6}\right\}\)
\(\left(4x-3\right)^2=16\)
\(\left(4x-3\right)=\perp\left(4\right)^2\)
\(\text{Vậy }4x-3=4\)
\(4x\) \(=4+3=7\)
\(x\) \(=7:4=\dfrac{7}{4}\)
\(\text{hoặc }4x-3=-4\)
\(4x\) \(=\left(-4\right)+3=-1\)
\(x\) \(=\left(-1\right):4=\dfrac{-1}{4}\)
\(\Rightarrow x\in\left\{\dfrac{7}{4};\dfrac{-1}{4}\right\}\)
ND
Nguyễn Đức Trí
VIP
27 tháng 7 2023
Bài 6 :
a) \(\dfrac{625}{5^n}=5\Rightarrow\dfrac{5^4}{5^n}=5\Rightarrow5^{4-n}=5^1\Rightarrow4-n=1\Rightarrow n=3\)
b) \(\dfrac{\left(-3\right)^n}{27}=-9\Rightarrow\dfrac{\left(-3\right)^n}{\left(-3\right)^3}=\left(-3\right)^2\Rightarrow\left(-3\right)^{n-3}=\left(-3\right)^2\Rightarrow n-3=2\Rightarrow n=5\)
c) \(3^n.2^n=36\Rightarrow\left(2.3\right)^n=6^2\Rightarrow\left(6\right)^n=6^2\Rightarrow n=6\)
d) \(25^{2n}:5^n=125^2\Rightarrow\left(5^2\right)^{2n}:5^n=\left(5^3\right)^2\Rightarrow5^{4n}:5^n=5^6\Rightarrow\Rightarrow5^{3n}=5^6\Rightarrow3n=6\Rightarrow n=3\)
ND
Nguyễn Đức Trí
VIP
27 tháng 7 2023
Bài 7 :
a) \(3^x+3^{x+2}=9^{17}+27^{12}\)
\(\Rightarrow3^x\left(1+3^2\right)=\left(3^2\right)^{17}+\left(3^3\right)^{12}\)
\(\Rightarrow10.3^x=3^{34}+3^{36}\)
\(\Rightarrow10.3^x=3^{34}\left(1+3^2\right)=10.3^{34}\)
\(\Rightarrow3^x=3^{34}\Rightarrow x=34\)
b) \(5^{x+1}-5^x=100.25^{29}\Rightarrow5^x\left(5-1\right)=4.5^2.\left(5^2\right)^{29}\)
\(\Rightarrow4.5^x=4.25^{2.29+2}=4.5^{60}\)
\(\Rightarrow5^x=5^{60}\Rightarrow x=60\)
c) Bài C bạn xem lại đề
d) \(\dfrac{3}{2.4^x}+\dfrac{5}{3.4^{x+2}}=\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{10}}\)
\(\Rightarrow\dfrac{3}{2.4^x}-\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{x+2}}-\dfrac{5}{3.4^{10}}=0\)
\(\Rightarrow\dfrac{3}{2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)+\dfrac{5}{3.4^2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)=0\)
\(\Rightarrow\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)\left(\dfrac{3}{2}+\dfrac{5}{3.4^2}\right)=0\)
\(\Rightarrow\dfrac{1}{4^x}-\dfrac{1}{4^8}=0\)
\(\Rightarrow\dfrac{4^8-4^x}{4^{x+8}}=0\Rightarrow4^8-4^x=0\left(4^{x+8}>0\right)\Rightarrow4^x=4^8\Rightarrow x=8\)
a) \(x=\dfrac{7}{2}\)
b) \(\dfrac{1}{35}\)
c) \(\left[{}\begin{matrix}x=10\\x=-20\end{matrix}\right.\)
d) \(x=12.\)
Mấy bài này lần sau bạn tự tính nhé!
Bài 9 : Tìm x ,biết :
a) \(x+\dfrac{1}{2}=2^5:2^3\)
\(x+\dfrac{1}{2}=2^2\)
\(x+\dfrac{1}{2}=4\)
\(x=4-\dfrac{1}{2}\)
\(x=3\dfrac{1}{2}=\dfrac{7}{2}\)
b) \(\dfrac{2}{3}+\dfrac{5}{3}x=\dfrac{5}{7}\)
\(\dfrac{5}{3}x=\dfrac{5}{7}-\dfrac{2}{3}\)
\(\dfrac{5}{3}x=\dfrac{1}{21}\)
\(x=\dfrac{1}{21}:\dfrac{5}{3}\)
\(x=\dfrac{1}{35}\)
c) \(\left|x+5\right|-6=9\)
\(\left|x+5\right|=9+6\)
\(\left|x+5\right|=15\)
\(\Rightarrow\left[{}\begin{matrix}x+5=15\\x+5=-15\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=10\\x=-20\end{matrix}\right.\)
d) \(-\dfrac{12}{13}x-5=6\dfrac{1}{3}\)
\(-\dfrac{12}{13}x-5=\dfrac{79}{13}\)
\(-\dfrac{12}{13}x=\dfrac{79}{13}+5\)
\(-\dfrac{12}{13}x=\dfrac{144}{13}\)
\(x=\dfrac{144}{13}:\dfrac{-12}{13}\)
\(x=-12\)